The equilibrium constant ( K P ) for the reaction H 2 ( g ) + CO 2 ( g ) ⇌ H 2 O ( g ) + CO ( g ) is 4.40 at 2000 K. (a) Calculate Δ G ° for the reaction. (b) Calculate Δ G for the reaction when the partial pressures are P H 2 = 0.25 atm, P CO 2 = 0.78 atm, P H 2 O = 0.66 atm, and P CO = 1.20 atm.
The equilibrium constant ( K P ) for the reaction H 2 ( g ) + CO 2 ( g ) ⇌ H 2 O ( g ) + CO ( g ) is 4.40 at 2000 K. (a) Calculate Δ G ° for the reaction. (b) Calculate Δ G for the reaction when the partial pressures are P H 2 = 0.25 atm, P CO 2 = 0.78 atm, P H 2 O = 0.66 atm, and P CO = 1.20 atm.
Solution Summary: The author explains that the laws of thermodynamics explain the fundamental quantities such as temperature, energy, and randomness in a system.
is 4.40 at 2000 K. (a) Calculate ΔG° for the reaction. (b) Calculate ΔG for the reaction when the partial pressures are
P
H
2
=
0.25
atm,
P
CO
2
=
0.78
atm,
P
H
2
O
=
0.66
atm, and PCO = 1.20 atm.
2. Consider the following equilibrium:
C (s) + H,O (g) = CÓ (g) + H, (g), AH® = +131.3 kJ-mol·'
(1) Please write the expression of reaction quotient K. (2) Use Le Chatelier's
Principle to state and explain the effect on the equilibrium when: (a) the
pressure of H2O is increased; (b) the temperature is increased; (c) the
concentration of the H, is increased; (d) The total pressure is increased by
decreasing the volume.
作答
Calculate ΔG° for each of the following reactions from the equilibrium constant at the temperature given.(a) Cl2(g) + Br2(g) ⟶ 2BrCl(g) T = 25 °C Kp = 4.7 × 10−2(b) 2SO2(g) + O2(g) ⇌ 2SO3(g) T = 500 °C Kp = 48.2(c) H2 O(l) ⇌ H2 O(g) T = 60 °C Kp = 0.196 atm(d) CoO(s) + CO(g) ⇌ Co(s) + CO2(g) T = 550 °C Kp = 4.90 × 102(e) CH3 NH2(aq) + H2 O(l) ⟶ CH3 NH3+(aq) + OH−(aq) T = 25 °C Kp = 4.4 × 10−4(f) PbI2(s) ⟶ Pb2+(aq) + 2I−(aq) T = 25 °C Kp = 8.7 × 10−9
(5b) Write the expression for the equilibrium constant Kp for the following reaction.Enclose pressures in parentheses and do NOT write the chemical formula as a subscript. For example, enter (PNH3 )2 as (P NH3)2. If either the numerator or denominator is 1, please enter 1
2 CuCl2(s)
↔
2 CuCl(s)
+
Cl2(g)
K =
(8c) Consider the following reaction where Kc = 6.50×10-3 at 298 K: 2 NOBr (g) 2 NO (g) + Br2 (g) A reaction mixture was found to contain 9.96×10-2 moles of NOBr (g), 4.61×10-2 moles of NO (g), and 4.42×10-2 moles of Br2 (g), in a 1.00 liter container.Indicate True (T) or False (F) for each of the following: 1. In order to reach equilibrium NOBr(g) must be consumed .2. In order to reach equilibrium Kc must decrease .3. In order to reach equilibrium NO must be produced .4. Qc is less than Kc.5. The reaction is at equilibrium. No further reaction will occur.
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The Laws of Thermodynamics, Entropy, and Gibbs Free Energy; Author: Professor Dave Explains;https://www.youtube.com/watch?v=8N1BxHgsoOw;License: Standard YouTube License, CC-BY