Although silver chloride is insoluble in water, it readily dissolves upon the addition of ammonia. AgCl ( s ) + 2 NH 3 ( a q ) ⇌ Ag ( NH 3 ) 2 + ( a q ) + Cl − ( a q ) a What is the equilibrium constant for this dissolving process? b Ammonia is added to a solution containing excess AgCl( s ). The final volume is 1.00 L and the resulting equilibrium concentration of NH 3 is 0.80 M . Calculate the number of moles of AgCl dissolved, the molar concentration of Ag(NH 3 ) 2 + , and the number of moles of NH 3 added to the original solution.
Although silver chloride is insoluble in water, it readily dissolves upon the addition of ammonia. AgCl ( s ) + 2 NH 3 ( a q ) ⇌ Ag ( NH 3 ) 2 + ( a q ) + Cl − ( a q ) a What is the equilibrium constant for this dissolving process? b Ammonia is added to a solution containing excess AgCl( s ). The final volume is 1.00 L and the resulting equilibrium concentration of NH 3 is 0.80 M . Calculate the number of moles of AgCl dissolved, the molar concentration of Ag(NH 3 ) 2 + , and the number of moles of NH 3 added to the original solution.
Solution Summary: The author explains that the equilibrium constant of a chemical equation can be derived by taking sum of other equations.
Although silver chloride is insoluble in water, it readily dissolves upon the addition of ammonia.
AgCl
(
s
)
+
2
NH
3
(
a
q
)
⇌
Ag
(
NH
3
)
2
+
(
a
q
)
+
Cl
−
(
a
q
)
a What is the equilibrium constant for this dissolving process?
b Ammonia is added to a solution containing excess AgCl(s). The final volume is 1.00 L and the resulting equilibrium concentration of NH3 is 0.80 M. Calculate the number of moles of AgCl dissolved, the molar concentration of Ag(NH3)2+, and the number of moles of NH3 added to the original solution.
Diels Alder Cycloaddition: Focus on regiochemistry (problems E-F) –> match + of thedienophile and - of the diene while also considering stereochemistry (endo).
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Question 4
Determine the rate order and rate constant for sucrose hydrolysis.
Time (hours)
[C6H12O6]
0
0.501
0.500
0.451
1.00
0.404
1.50
0.363
3.00
0.267
First-order, k = 0.210 hour 1
First-order, k = 0.0912 hour 1
O Second-order, k =
0.590 M1 hour 1
O Zero-order, k = 0.0770 M/hour
O Zero-order, k = 0.4896 M/hour
O Second-order, k = 1.93 M-1-hour 1
10 pts
Chapter 17 Solutions
OWLv2 for Ebbing/Gammon's General Chemistry, 11th Edition, [Instant Access], 1 term (6 months)
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell