Delmar's Standard Textbook Of Electricity
7th Edition
ISBN: 9781337900348
Author: Stephen L. Herman
Publisher: Cengage Learning
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Textbook Question
Chapter 17, Problem 15PP
An R-L series circuit contains two resistors and two inductors. The resistors are 68
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Three non-reactive loads are connected in delta
across a three-phase, three-wire, 400 V supply in the
following way: (i) 10 kW across R and Y lines; (ii)
6 kW across Y and B lines; (iii) 4 kW across B and R
lines. Draw a phasor diagram showing the three line
voltages and the load currents and determine: (a) the
current in the B line and its phase relationship to the
line voltage VBR; (b) the reading of a wattmeter whose
current coils are connected in the B line and whose
voltage circuit is connected across the B and R lines.
The phase rotation is R–Y–B. Where would a second
wattmeter be connected for the two-wattmeter
method and what would be its reading?
ANS:
21.8 A, 36°35′ lagging; 7 kW; 13 kW
NEED HANDWRITTEN SOLUTION DO NOT USE AI OR CHATGPT
A factory has the following load with power factor of 0.85 lagging in each phase.
Between the red and yellow phases 40 A, between the yellow and blue phases 50 A,
and between the blue and red phases 60 A. If the supply is 415 V, three-phase,
calculate the line currents. Draw a phasor diagram for phase and line quantities. Ensure to draw all necessary diagrams
ANS: IR
= 87.178<-68.380 A; IY = 78.102<-178.120 A; IB = 95.394<61.210 A.
Chapter 17 Solutions
Delmar's Standard Textbook Of Electricity
Ch. 17 - 1. What is the relationship of voltage and current...Ch. 17 - What is the relationship of voltage and current...Ch. 17 - 3. What is power factor?
Ch. 17 - 4. A circuit contains a 20- resistor and an...Ch. 17 - 5. An R-L series circuit has a power factor of...Ch. 17 - 6. An R-L series circuit has an apparent power of...Ch. 17 - 7. The resistor in an R-L series circuit has a...Ch. 17 - 8. An R-L series circuit has a reactive power of...Ch. 17 - 9. An R-L series circuit contains a resistor and...Ch. 17 - 10. What is the voltage drop across the resistor...
Ch. 17 - 11. A phase angle meter connected in an R-L series...Ch. 17 - 12. An R-L series circuit has a power factor of...Ch. 17 - An AC electric motor is connected to a 240-V,...Ch. 17 - You are a journeyman electrician working in an...Ch. 17 - Assume that the circuit shown in Figure 17-2 is...Ch. 17 - Assume that the voltage drop across the resistor,...Ch. 17 - Assume the circuit shown in Figure 17-2 has an...Ch. 17 - Assume the circuit shown in Figure 17-2 has a...Ch. 17 - In an R-L series circuit,...Ch. 17 - In an R-L series circuit,...Ch. 17 - In an R-L series circuit,...Ch. 17 - In an R-L series circuit, the apparent power is...Ch. 17 - 9. An R-L series circuit is connected to a 60-Hz,...Ch. 17 - In an R-L series circuit, Z=88,R=32.FindXL.Ch. 17 - In an R-L series circuit, apparent power = 450 VA,...Ch. 17 - In an R-L series circuit, =22, true power = 94...Ch. 17 - An R-L series circuit contains two resistors and...Ch. 17 - An R-L series circuit contains two resistors and...Ch. 17 - An R-L series circuit contains two resistors and...Ch. 17 - An R-L series circuit contains two resistors and...
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- Answer question D only using by hand first darw cylinder then calculate show me starrow_forwardThe phase currents in a delta-connected three-phase load are as follows: between the red and yellow lines, 30 A at p.f. 0.707 leading; between the yellow and blue lines, 20 A at unity p.f.; between the blue and red lines, 25 A at p.f. 0.866 lagging. Calculate the line currents and draw the complete phasor diagram. ANS: 21.6 A in R, 49.6 A in Y, 43.5 A in Barrow_forward. Two wattmeters connected to measure the input to a balanced three-phase circuit indicate 2500 W and 500 W respectively. Find the power factor of the circuit: (a) when both readings are positive; (b) when the latter reading is obtained after reversing the con nections to the current-coil of one instrument. Draw the phasor and connection diagrams. ANS: 0.655, 0.359arrow_forward
- Explain the advantage of connecting the low-voltage winding of distribution transformers in star. A factory has the following load with power factor of 0.9 lagging in each phase. Red phase 40 A, yellow phase 50 A and blue phase 60 A. If the supply is 400 V, three phase, four-wire, calculate the current in the neutral and the total active power. Draw a phasor diagram for phase and line quantities. Assume that, relative to the current in the red phase, the current in the yellow phase lags by 120° and that in the blue phase leads by 120°. ANS: 17.3 A, 31.2 kWarrow_forwardA three-phase, 400 V system has the following load connected in delta: between the red and yellow lines, a non-reactive resistor of 100 Ω; between the yellow and blue lines, a coil having a reactance of 60 Ω and negligible resistance; between the blue and red lines, a loss-free capacitor having a reactance of 130 Ω. Calculate: (a) the phase currents; (b) the line currents. Assume the phase sequence to be R–Y, Y–B and B–R. Also, draw the complete phasor diagram. ANS: 4.00 A, 6.67 A, 3.08 A, 6.85 A, 10.33 A, 5.8 Aarrow_forwardWith the aid of a circuit diagram, show that two wattmeters can be connected to read the total power in a three-phase, three-wire system. Two wattmeters connected to read the total power in a three-phase system supplying a balanced load read 10.5 kW and −2.5 kW respectively. Calculate the total active power. Drawing suitable phasor diagrams, explain the significance of: (a) equal wattmeter readings; (b) a zero reading on one wattmeter. ANS: 8 kWarrow_forward
- A factory has the following load with power factor of 0.9 lagging in each phase. Red phase 40 A, yellow phase 50 A and blue phase 60 A. If the supply is 400 V, three-phase, four-wire, calculate the current in the neutral and the total active power. Draw a phasor diagram for phase and line quantities. Assume that, relative to the current in the red phase, the current in the yellow phase lags by 120° and that in the blue phase leads by 120°.arrow_forwardFundimentals of Energy Systems Q8arrow_forwardTwo wattmeters are used to measure power in a three phase, three-wire network. Show by means of connection and complexor (phasor) diagrams that the sum of the wattmeter readings will measure the total active power. Two such wattmeters read 120 W and 50 W when connected to measure the active power taken by a balanced three-phase load. Find the power factor of the load. If one wattmeter tends to read in the reverse direction, explain what changes may have occurred in the circuit ANS: 0.815arrow_forward
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