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3. For the AM demodulator in figure, v(t) = m(t)cos (2πfet + 4) with a constant where the message signal is m(t) v(t)- =Acos (2πfmt) and carrier signal is v(t) = cos (2πfet) with fm

3. For the AM demodulator in figure, v(t) = m(t)cos (2πfet + 4) with a constant where the message signal is m(t) v(t)- =Acos (2πfmt) and carrier signal is v(t) = cos (2πfet) with fm

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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3. For the AM demodulator in figure, v(t) = m(t)cos (2πfet + 4) with a constant where the message signal is m(t) v(t)- =Acos (2πfmt) and carrier signal is v(t) = cos (2πfet) with fm <fm «fe. H(f)^ H(f) → vo(t) D v₁(t) vc(t) -fM 0 fm f Determine (a) (12%) v₁(t); (b) (13%) vo(t).
Transcribed Image Text:3. For the AM demodulator in figure, v(t) = m(t)cos (2πfet + 4) with a constant where the message signal is m(t) v(t)- =Acos (2πfmt) and carrier signal is v(t) = cos (2πfet) with fm <fm «fe. H(f)^ H(f) → vo(t) D v₁(t) vc(t) -fM 0 fm f Determine (a) (12%) v₁(t); (b) (13%) vo(t).
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