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2. Laboratory Preliminary Discussion First-order High-pass RC Filter Analysis The first-order high-pass RC filter shown in figure 3 below represents all voltages and currents in the time domain. We will again convert the circuit to its s-domain equivalent as shown in figure 4 and apply Laplace transform techniques. ic(t) C vs(t) i₁(t) + + vc(t) R1 ww Vi(t) || 12(t) V2(t) R₂ Vout(t) VR2(t) = V2(t) Figure 3: A first-order high-pass RC filter represented in the time domain. Ic(s) C + Vs(s) I₁(s) + + Vc(s) R₁ www V₁(s) 12(s) V₂(s) R₂ Vout(S) = VR2(S) = V2(s) Figure 4: A first-order high-pass RC filter represented in the s-domain. Again, to generate the s-domain expression for the output voltage, You (S) = V2 (s), for the circuit shown in figure 4 above, we can apply voltage division in the s-domain as shown in equation 2 below. Equation 2 will be used in the prelab computations to find an expression for the output voltage, xc(t), in the time domain. equation (2) R₂ Vout(s) = V₂(s) = R₂+ R₁||Zc(s)s(s) Preliminary Laboratory (Prelab) Work (Week #1) 2. (con't) In the space provided below for prelab work, complete the following tasks for the circuit shown in figure 4. If you require more page area to complete your computations, feel free to add space as needed between the prelab work areas below. a) Find the inverse Laplace transform for equation 2 to generate an expression for the time domain voltage Xout(t) = V2(t) assuming nominal values of R₁ = 47.0[k], R2 = 5.2[kQ], C= 0.01 [u], and a time-domain source voltage signal of Xs(t) = u(t). (9 points) b) Sketch the response,_out(t) = v2(t), for t≥0. Include both ys(t) and v2(t) in your sketch, and indicate the time constant associated with the response. (3 points) c) Generate a transient response using the Pspice tool in the Cadence software package to verify the time domain plot completed in part 2b above. (3 points) Prelab Part (2a):

2. Laboratory Preliminary Discussion First-order High-pass RC Filter Analysis The first-order high-pass RC filter shown in figure 3 below represents all voltages and currents in the time domain. We will again convert the circuit to its s-domain equivalent as shown in figure 4 and apply Laplace transform techniques. ic(t) C vs(t) i₁(t) + + vc(t) R1 ww Vi(t) || 12(t) V2(t) R₂ Vout(t) VR2(t) = V2(t) Figure 3: A first-order high-pass RC filter represented in the time domain. Ic(s) C + Vs(s) I₁(s) + + Vc(s) R₁ www V₁(s) 12(s) V₂(s) R₂ Vout(S) = VR2(S) = V2(s) Figure 4: A first-order high-pass RC filter represented in the s-domain. Again, to generate the s-domain expression for the output voltage, You (S) = V2 (s), for the circuit shown in figure 4 above, we can apply voltage division in the s-domain as shown in equation 2 below. Equation 2 will be used in the prelab computations to find an expression for the output voltage, xc(t), in the time domain. equation (2) R₂ Vout(s) = V₂(s) = R₂+ R₁||Zc(s)s(s) Preliminary Laboratory (Prelab) Work (Week #1) 2. (con't) In the space provided below for prelab work, complete the following tasks for the circuit shown in figure 4. If you require more page area to complete your computations, feel free to add space as needed between the prelab work areas below. a) Find the inverse Laplace transform for equation 2 to generate an expression for the time domain voltage Xout(t) = V2(t) assuming nominal values of R₁ = 47.0[k], R2 = 5.2[kQ], C= 0.01 [u], and a time-domain source voltage signal of Xs(t) = u(t). (9 points) b) Sketch the response,_out(t) = v2(t), for t≥0. Include both ys(t) and v2(t) in your sketch, and indicate the time constant associated with the response. (3 points) c) Generate a transient response using the Pspice tool in the Cadence software package to verify the time domain plot completed in part 2b above. (3 points) Prelab Part (2a):

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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2. Laboratory Preliminary Discussion First-order High-pass RC Filter Analysis The first-order high-pass RC filter shown in figure 3 below represents all voltages and currents in the time domain. We will again convert the circuit to its s-domain equivalent as shown in figure 4 and apply Laplace transform techniques. ic(t) C vs(t) i₁(t) + + vc(t) R1 ww Vi(t) || 12(t) V2(t) R₂ Vout(t) VR2(t) = V2(t) Figure 3: A first-order high-pass RC filter represented in the time domain. Ic(s) C + Vs(s) I₁(s) + + Vc(s) R₁ www V₁(s) 12(s) V₂(s) R₂ Vout(S) = VR2(S) = V2(s) Figure 4: A first-order high-pass RC filter represented in the s-domain. Again, to generate the s-domain expression for the output voltage, You (S) = V2 (s), for the circuit shown in figure 4 above, we can apply voltage division in the s-domain as shown in equation 2 below. Equation 2 will be used in the prelab computations to find an expression for the output voltage, xc(t), in the time domain. equation (2) R₂ Vout(s) = V₂(s) = R₂+ R₁||Zc(s)s(s)
Transcribed Image Text:2. Laboratory Preliminary Discussion First-order High-pass RC Filter Analysis The first-order high-pass RC filter shown in figure 3 below represents all voltages and currents in the time domain. We will again convert the circuit to its s-domain equivalent as shown in figure 4 and apply Laplace transform techniques. ic(t) C vs(t) i₁(t) + + vc(t) R1 ww Vi(t) || 12(t) V2(t) R₂ Vout(t) VR2(t) = V2(t) Figure 3: A first-order high-pass RC filter represented in the time domain. Ic(s) C + Vs(s) I₁(s) + + Vc(s) R₁ www V₁(s) 12(s) V₂(s) R₂ Vout(S) = VR2(S) = V2(s) Figure 4: A first-order high-pass RC filter represented in the s-domain. Again, to generate the s-domain expression for the output voltage, You (S) = V2 (s), for the circuit shown in figure 4 above, we can apply voltage division in the s-domain as shown in equation 2 below. Equation 2 will be used in the prelab computations to find an expression for the output voltage, xc(t), in the time domain. equation (2) R₂ Vout(s) = V₂(s) = R₂+ R₁||Zc(s)s(s)
Preliminary Laboratory (Prelab) Work (Week #1) 2. (con't) In the space provided below for prelab work, complete the following tasks for the circuit shown in figure 4. If you require more page area to complete your computations, feel free to add space as needed between the prelab work areas below. a) Find the inverse Laplace transform for equation 2 to generate an expression for the time domain voltage Xout(t) = V2(t) assuming nominal values of R₁ = 47.0[k], R2 = 5.2[kQ], C= 0.01 [u], and a time-domain source voltage signal of Xs(t) = u(t). (9 points) b) Sketch the response,_out(t) = v2(t), for t≥0. Include both ys(t) and v2(t) in your sketch, and indicate the time constant associated with the response. (3 points) c) Generate a transient response using the Pspice tool in the Cadence software package to verify the time domain plot completed in part 2b above. (3 points) Prelab Part (2a):
Transcribed Image Text:Preliminary Laboratory (Prelab) Work (Week #1) 2. (con't) In the space provided below for prelab work, complete the following tasks for the circuit shown in figure 4. If you require more page area to complete your computations, feel free to add space as needed between the prelab work areas below. a) Find the inverse Laplace transform for equation 2 to generate an expression for the time domain voltage Xout(t) = V2(t) assuming nominal values of R₁ = 47.0[k], R2 = 5.2[kQ], C= 0.01 [u], and a time-domain source voltage signal of Xs(t) = u(t). (9 points) b) Sketch the response,_out(t) = v2(t), for t≥0. Include both ys(t) and v2(t) in your sketch, and indicate the time constant associated with the response. (3 points) c) Generate a transient response using the Pspice tool in the Cadence software package to verify the time domain plot completed in part 2b above. (3 points) Prelab Part (2a):
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