Two different equations showing the change in Gibbs free energy are given. The derivation of E ° as a function of temperature for the given equations, the graphical determination of Δ H ° and Δ S ° from measurements of E ° at different temperature and the property used for designing a reference half-cell that would produce a potential relatively stable with respect to temperature is to be stated. Concept introduction: Gibbs free energy is basically the maximum amount of non-expansion work done. Therefore, it is represented as, W max = Δ G ° The relationship between Gibbs free energy change and cell potential is given by the formula, Δ G ° = − n F E ° cell The relation between Δ G ° , Δ H ° and Δ S ° is given as, Δ G ° = Δ H ° − T Δ S ° To determine: The derivation of E ° as a function of temperature for the given equations, the graphical determination of Δ H ° and Δ S ° from measurements of E ° at different temperatures and the property used for designing a reference half-cell that would produce a potential relatively stable with respect to temperature. The relation obtained from the given equations is, E ° cell = T ( Δ S ° n F ) + ( − Δ H ° n F )
Two different equations showing the change in Gibbs free energy are given. The derivation of E ° as a function of temperature for the given equations, the graphical determination of Δ H ° and Δ S ° from measurements of E ° at different temperature and the property used for designing a reference half-cell that would produce a potential relatively stable with respect to temperature is to be stated. Concept introduction: Gibbs free energy is basically the maximum amount of non-expansion work done. Therefore, it is represented as, W max = Δ G ° The relationship between Gibbs free energy change and cell potential is given by the formula, Δ G ° = − n F E ° cell The relation between Δ G ° , Δ H ° and Δ S ° is given as, Δ G ° = Δ H ° − T Δ S ° To determine: The derivation of E ° as a function of temperature for the given equations, the graphical determination of Δ H ° and Δ S ° from measurements of E ° at different temperatures and the property used for designing a reference half-cell that would produce a potential relatively stable with respect to temperature. The relation obtained from the given equations is, E ° cell = T ( Δ S ° n F ) + ( − Δ H ° n F )
Solution Summary: The author explains that Gibbs free energy is basically the maximum amount of non-expansion work done.
Two different equations showing the change in Gibbs free energy are given. The derivation of
E° as a function of temperature for the given equations, the graphical determination of
ΔH° and
ΔS° from measurements of
E° at different temperature and the property used for designing a reference half-cell that would produce a potential relatively stable with respect to temperature is to be stated.
Concept introduction:
Gibbs free energy is basically the maximum amount of non-expansion work done. Therefore, it is represented as,
Wmax=ΔG°
The relationship between Gibbs free energy change and cell potential is given by the formula,
ΔG°=−nFE°cell
The relation between
ΔG°,
ΔH° and
ΔS° is given as,
ΔG°=ΔH°−TΔS°
To determine: The derivation of
E° as a function of temperature for the given equations, the graphical determination of
ΔH° and
ΔS° from measurements of
E° at different temperatures and the property used for designing a reference half-cell that would produce a potential relatively stable with respect to temperature.
The relation obtained from the given equations is,
Acetic acid is added to DI water at an initial concentration of 10 -6 M (Ka=1.8x10-5)
A. Using the "ICE" Method, what would the pH be at equilibrium? State assumptions and show your
work.
B. Using the simultaneous equations method, what would the pH be at equilibrium? Show your work
1. Show that the change in entropy for a fixed amount of ideal gas held at a constant
temperature undergoing a volume change is given by the simple equation
AS = NkB In
Hint: Start with the equation
M
dS =
du + (Œ) dv - Ž (#) an,
dU
du+av-dN;
j=1
Why doesn't the equation for the entropy of an ideal gas depend on the strength of the
intermolecular forces for the gas?
2. Make an ice cube at 1 bar pressure by freezing an amount of liquid water that is 2
cm x 2 cm x 2 cm in volume. The density of liquid water at 0 °C is 1.000 g cm³ and the
density of ice at 0 °C is 0.915 g cm³. Note that this difference in density is the reason
your water pipes burst if they freeze and why you shouldn't forget to take your bottle of
pop out of the freezer if you put it in there to try and cool it down faster.
A. What is the work of expansion upon freezing?
B. Is work done on the system or by the system?
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