a)
Interpretation:
The product of the reaction in which actophenone reacts with HNO3 and H2SO4 is to be predicted. The observed regiochemistry is to be explained by drawing the resonance structures of the intermediates.
Concept introduction:
The carbonyl group is an electron withdrawing group. Hence in
To predict:
The product of the reaction in which actophenone reacts with HNO3 and H2SO4.
To explain:
The observed regiochemistry by drawing the resonance structures of the intermediates.
Answer to Problem 77AP
Actophenone reacts with HNO3 and H2SO4 to produce m-nitroacetophenone.
Explanation of Solution
The electrophile, NO2+, attacks the aromatic ring in the first step to produce a resonance stabilized carbocation (sigma complex). In the second step the carbocation deprotonates to yield the product. For the meta attack the intermediate is more stabilized as shown.
For ortho and para attack one of the resonance forms will be unstable as there will be a positive charge on the carbon to which the carbonyl group is attached.
Actophenone reacts with HNO3 and H2SO4 to produce m-nitroacetophenone.
b)
Interpretation:
The product of the reaction in which toluene reacts with isopropyl chloride in the presence of AlCl3 is to be predicted. The observed regiochemistry is to be explained by drawing the resonance structures of the intermediates.
Concept introduction:
Alkyl groups are an electron releasing groups. Hence during aromatic electrophilic substitution reactions the alkyl groups will activate the ring and orient the electrophile to the ortho and para positions.
To predict:
The product of the reaction in which toluene reacts with isopropyl chloride in the presence of AlCl3.
To explain:
The observed regiochemistry by drawing the resonance structures of the intermediates.
Answer to Problem 77AP
When toluene reacts with isopropyl chloride in the presence of AlCl3 the products obtained are o- and p-isopropylbenzenes. The p-isomer will predominate.
Explanation of Solution
The electrophile, (CH3)2CH+, attacks the aromatic ring in the first step to produce a resonance stabilized carbocation (sigma complex). In the second step the carbocation deprotonates to yield the product. For the ortho and para attacks, one of the the resonance structures has a positive charge on a carbon adjacent to the methyl group. This form is stabilized by electron release from the methyl group. Such stabilization is not possible for the meta attack. Hence a mixture of ortho-para products is produced in which the p-isomer predominates.
For ortho attack:
For para attack:
When toluene reacts with isopropyl chloride in the presence of AlCl3 the products obtained are o- and p-isopropylbenzenes. The p-isomer will predominate.
c)
Interpretation:
The product of the reaction in which benzonitrile reacts with chlorine in the presence of FeCl3 is to be predicted. The observed regiochemistry is to be explained by drawing the resonance structures of the intermediates.
Concept introduction:
The nitrile group is an electron withdrawing group. Hence in aromatic electrophilic substitution reactions the nitrile group will deactivate the ring and orient the electrophile to the meta position.
To predict:
The product of the reaction in which benzonitrile reacts with chlorine in the presence of FeCl3.
To explain:
The observed regiochemistry by drawing the resonance structures of the intermediates.
Answer to Problem 77AP
When benzonitrile reacts with chlorine in the presence of FeCl3 meta chlorobenzonitrile will be produced.
Explanation of Solution
The electrophile, Cl+, attacks the aromatic ring in the first step to produce a resonance stabilized carbocation (sigma complex). In the second step the carbocation deprotonates to yield the product. For the meta attack the intermediate is more stabilized as shown.
For ortho and para attack one of the resonance forms will be unstable as there will be a positive charge on the carbon to which the nitrile group is attached.
When benzonitrile reacts with chlorine in the presence of FeCl3 meta chlorobenzonitrile will be produced.
d)
Interpretation:
The product of the reaction in which methoxy benzene reacts with iodine in the presence of CuCl2 is to be predicted. The observed regiochemistry is to be explained by drawing the resonance structures of the intermediates.
Concept introduction:
Methoxy group is an electron releasing group. Hence during aromatic electrophilic substitution reactions the methoxy group will activate the ring and orient the electrophile to the ortho and para positions.
To predict:
The product of the reaction in which benzene reacts with iodine in the presence of CuCl2.
To explain:
The observed regiochemistry by drawing the resonance structures of the intermediates.
Answer to Problem 77AP
When methoxybenzene reacts with iodine in the presence of CuCl2, the products obtained are o- and p-iodobenzenes.
Explanation of Solution
Iodine itself is unreactive toward aromatic rings. CuCl2 accelerate the iodination reaction by oxidizing iodine to a more powerful by electrophilic species that reacts like I+.
The electrophile, I+, attacks the aromatic ring in the first step to produce a resonance stabilized carbocation (sigma complex). In the second step the carbocation deprotonates to yield the product. For the ortho and para attacks, one of the the resonance structures has a positive charge on a carbon adjacent to the methoxy group. This form is stabilized by electron release from the methoxy group. Such stabilization is not possible for the meta attack. Hence a mixture of ortho-para products is produced.
Ortho attack:
Meta attack:
When methoxybenzene reacts with iodine in the presence of CuCl2, the products obtained are o- and p-iodobenzenes.
Want to see more full solutions like this?
Chapter 16 Solutions
OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card for McMurry's Organic Chemistry, 9th
- Follow the curved arrows to draw a second resonance structure for each species. Explain and steps for individual understanding.arrow_forwardDraw all reasonable resonance structures for the following cation. Then draw the resonance hybrid. Provide steps and explanationarrow_forwardHow are the molecules or ions in each pair related? Classify them as resonance structures, isomers, or neither.arrow_forward
- How do I solve this Alkyne synthesis homework problem for my Organic Chemistry II class? I have to provide both the intermediate products and the reagents used.arrow_forwardSubstance X is known to exist at 1 atm in the solid, liquid, or vapor phase, depending on the temperature. Additionally, the values of these other properties of X have been determined: melting point enthalpy of fusion 90. °C 8.00 kJ/mol boiling point 130. °C enthalpy of vaporization 44.00 kJ/mol density 2.80 g/cm³ (solid) 36. J.K mol (solid) 2.50 g/mL (liquid) heat capacity 32. J.Kmol (liquid) 48. J.Kmol (vapor) You may also assume X behaves as an ideal gas in the vapor phase. Ex Suppose a small sample of X at 50 °C is put into an evacuated flask and heated at a constant rate until 15.0 kJ/mol of heat has been added to the sample. Graph the temperature of the sample that would be observed during this experiment. o0o 150- 140 130- 120- 110- 100- G Ar ?arrow_forwardMechanism. Provide the mechanism for the reaction below. You must include all arrows, intermediates, and formal charges. If drawing a Sigma complex, draw all major resonance forms. The ChemDraw template of this document is available on Carmen. Br FeBr3 Brarrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage LearningOrganic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning