To prove: That the vertical component of force on a point P due to a small polar rectangle of size Δ r × Δ θ located at distance r .

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Answer 1

Question

Chapter 16.5, Problem 59E

(a)

To determine

To prove:

That the vertical component of force on a point P due to a small polar rectangle of size $Δ r \times Δ θ$ located at distance r.

(b)

To determine

To explain:

Why the force on the point P due to entire circular disk is given by the integral

$F = k Q ρ d \int_{0}^{2 π} \int_{0}^{R} \frac{r d r d θ}{{(r^{2} + d^{2})}^{\frac{3}{2}}}$

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9. a) Determie values of a and b so that the function is continuous. ax - 2b f(x) 2 x≤-2 -2x+a, x ≥2 \-ax² - bx + 1, −2 < x < 2) 9b) Consider f(x): = 2x²+x-3 x-b and determine all the values of b such that f(x) does not have a vertical asymptote. Show work.

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Answer 2

Question

Chapter 16.5, Problem 59E

(a)

To determine

To prove:

That the vertical component of force on a point P due to a small polar rectangle of size $Δ r \times Δ θ$ located at distance r.

(b)

To determine

To explain:

Why the force on the point P due to entire circular disk is given by the integral

$F = k Q ρ d \int_{0}^{2 π} \int_{0}^{R} \frac{r d r d θ}{{(r^{2} + d^{2})}^{\frac{3}{2}}}$

Expert Solution & Answer

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Answer 3

Question

Chapter 16.5, Problem 59E

(a)

To determine

To prove:

That the vertical component of force on a point P due to a small polar rectangle of size $Δ r \times Δ θ$ located at distance r.

(b)

To determine

To explain:

Why the force on the point P due to entire circular disk is given by the integral

$F = k Q ρ d \int_{0}^{2 π} \int_{0}^{R} \frac{r d r d θ}{{(r^{2} + d^{2})}^{\frac{3}{2}}}$

Expert Solution & Answer

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Answer 4

Question

Chapter 16.5, Problem 59E

(a)

To determine

To prove:

That the vertical component of force on a point P due to a small polar rectangle of size $Δ r \times Δ θ$ located at distance r.

(b)

To determine

To explain:

Why the force on the point P due to entire circular disk is given by the integral

$F = k Q ρ d \int_{0}^{2 π} \int_{0}^{R} \frac{r d r d θ}{{(r^{2} + d^{2})}^{\frac{3}{2}}}$

Expert Solution & Answer

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Answer 5

Chapter 16.5, Problem 59E

(a)

To determine

To prove:

That the vertical component of force on a point P due to a small polar rectangle of size $Δ r \times Δ θ$ located at distance r.

(b)

To determine

To explain:

Why the force on the point P due to entire circular disk is given by the integral

$F = k Q ρ d \int_{0}^{2 π} \int_{0}^{R} \frac{r d r d θ}{{(r^{2} + d^{2})}^{\frac{3}{2}}}$

Answer 6

Chapter 16.5, Problem 59E

(a)

To determine

To prove:

That the vertical component of force on a point P due to a small polar rectangle of size $Δ r \times Δ θ$ located at distance r.

Answer 7

Chapter 16.5, Problem 59E

(a)

To determine

To prove:

That the vertical component of force on a point P due to a small polar rectangle of size $Δ r \times Δ θ$ located at distance r.

Answer 8

(b)

To determine

To explain:

Why the force on the point P due to entire circular disk is given by the integral

$F = k Q ρ d \int_{0}^{2 π} \int_{0}^{R} \frac{r d r d θ}{{(r^{2} + d^{2})}^{\frac{3}{2}}}$

Answer 9

(b)

To determine

To explain:

Why the force on the point P due to entire circular disk is given by the integral

$F = k Q ρ d \int_{0}^{2 π} \int_{0}^{R} \frac{r d r d θ}{{(r^{2} + d^{2})}^{\frac{3}{2}}}$

Answer 10

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Answer 11

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Answer 12

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Answer 13

Ch. 16.1 - Prob. 1PQ Ch. 16.1 - Prob. 2PQ Ch. 16.1 - Prob. 3PQ Ch. 16.1 - Prob. 4PQ Ch. 16.1 - Prob. 5PQ Ch. 16.1 - Prob. 6PQ Ch. 16.1 - Prob. 1E Ch. 16.1 - Prob. 2E Ch. 16.1 - Prob. 3E Ch. 16.1 - Prob. 4E

To prove: That the vertical component of force on a point P due to a small polar rectangle of size Δ r × Δ θ located at distance r .

Solution Summary: The author explains how the vertical component of force exerted by the polar rectangle on the point P can be written as follows:

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To prove:

That the vertical component of force on a point P due to a small polar rectangle of size $Δ r \times Δ θ$ located at distance r.

To explain:

Why the force on the point P due to entire circular disk is given by the integral

$F = k Q ρ d \int_{0}^{2 π} \int_{0}^{R} \frac{r d r d θ}{{(r^{2} + d^{2})}^{\frac{3}{2}}}$

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Chapter 16 Solutions

To prove: That the vertical component of force on a point P due to a small polar rectangle of size Δ r × Δ θ located at distance r .

Solution Summary: The author explains how the vertical component of force exerted by the polar rectangle on the point P can be written as follows:

Concept explainers

Videos