Explanation Given: ∫ ∫ D x d A , where D is the shaded domain in the Figure. Calculation: From the figure, the given region in polar coordinates is defined as D : 0 ≤ θ ≤ π , 0 ≤ r ≤ 2 + 2 cos θ Therefore, ∫ ∫ D x d A = ∫ θ = 0 π ∫ r = 0 2 + 2 cos θ ( r cos θ ) r d r d θ = ∫ θ = 0 π ∫ r = 0 2 + 2 cos θ ( r 2 cos θ ) d r d θ = 1 3 ∫ 0 π [ r 3 ] 0 2 + 2 cos θ cos θ d θ =

4th Edition

ISBN: 9781319050733

Author: Rogawski

Publisher: MAC HIGHER

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Question

Chapter 16, Problem 24CRE

To determine

To calculate:

$\int \int_{D} x d A$ , where $D$ is the shaded domain in the given figure.

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Chapter 16, Problem 23CRE

Chapter 16, Problem 25CRE

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Chapter 16 Solutions

CALCULUS (CLOTH)

Ch. 16.1 - Prob. 1PQ Ch. 16.1 - Prob. 2PQ Ch. 16.1 - Prob. 3PQ Ch. 16.1 - Prob. 4PQ Ch. 16.1 - Prob. 5PQ Ch. 16.1 - Prob. 6PQ Ch. 16.1 - Prob. 1E Ch. 16.1 - Prob. 2E Ch. 16.1 - Prob. 3E Ch. 16.1 - Prob. 4E

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∫ ∫ D x d A , where D is the shaded domain in the given figure.

Solution Summary: The author calculates D x d A, where D is the shaded domain in the given figure.

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To calculate:

$\int \int_{D} x d A$ , where $D$ is the shaded domain in the given figure.

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Chapter 16 Solutions

∫ ∫ D x d A , where D is the shaded domain in the given figure.

Solution Summary: The author calculates D x d A, where D is the shaded domain in the given figure.

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To calculate: ∫∫DxdA, where Dis the shaded domain in the given figure.

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Chapter 16 Solutions

To calculate:

$\int \int_{D} x d A$ , where $D$ is the shaded domain in the given figure.