Explanation Let there be a continuous function f ( x , y ) on R = [ a , b ] × [ c , d ] , then the below integrals are referred to as iterated integrals. ∬ R f ( x , y ) d A = ∫ a b ∫ c d f ( x , y ) d y d x = ∫ c d ∫ a b f (

4th Edition

ISBN: 9781319050733

Author: Rogawski

Publisher: MAC HIGHER

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Question

Chapter 16.1, Problem 5PQ

To determine

Between the following options (a) and (b) which is equal to $\int_{1}^{2} \int_{4}^{5} f (x, y) d y d x$

(a) $\int_{1}^{2} \int_{4}^{5} f (x, y) d x d y$ (b) $\int_{4}^{5} \int_{1}^{2} f (x, y) d x d y$

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Chapter 16.1, Problem 4PQ

Chapter 16.1, Problem 6PQ

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Chapter 16 Solutions

CALCULUS (CLOTH)

Ch. 16.1 - Prob. 1PQ Ch. 16.1 - Prob. 2PQ Ch. 16.1 - Prob. 3PQ Ch. 16.1 - Prob. 4PQ Ch. 16.1 - Prob. 5PQ Ch. 16.1 - Prob. 6PQ Ch. 16.1 - Prob. 1E Ch. 16.1 - Prob. 2E Ch. 16.1 - Prob. 3E Ch. 16.1 - Prob. 4E

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Between the following options (a) and (b) which is equal to ∫ 1 2 ∫ 4 5 f ( x , y ) d y d x (a) ∫ 1 2 ∫ 4 5 f ( x , y ) d x d y (b) ∫ 4 5 ∫ 1 2 f ( x , y ) d x d y

Solution Summary: The author explains that if there is a continuous function f (x, y) on R = [a b ] [c. d], then the below integrals are referred to

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Between the following options (a) and (b) which is equal to $\int_{1}^{2} \int_{4}^{5} f (x, y) d y d x$

(a) $\int_{1}^{2} \int_{4}^{5} f (x, y) d x d y$ (b) $\int_{4}^{5} \int_{1}^{2} f (x, y) d x d y$

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Chapter 16 Solutions

Between the following options (a) and (b) which is equal to ∫ 1 2 ∫ 4 5 f ( x , y ) d y d x (a) ∫ 1 2 ∫ 4 5 f ( x , y ) d x d y (b) ∫ 4 5 ∫ 1 2 f ( x , y ) d x d y

Solution Summary: The author explains that if there is a continuous function f (x, y) on R = [a b ] [c. d], then the below integrals are referred to

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Between the following options (a) and (b) which is equal to ∫12∫45f(x,y) dy dx (a) ∫12∫45f(x,y) dx dy (b) ∫45∫12f(x,y) dx dy

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Chapter 16 Solutions

Between the following options (a) and (b) which is equal to $\int_{1}^{2} \int_{4}^{5} f (x, y) d y d x$

(a) $\int_{1}^{2} \int_{4}^{5} f (x, y) d x d y$ (b) $\int_{4}^{5} \int_{1}^{2} f (x, y) d x d y$