Chapter 16.2, Problem 3RQ

(a)

Interpretation Introduction

Interpretation:The concentration of ${\text{H}}^{+}$ of the solution if pH is 4.32 needs to be determined.

Concept introduction: $\text{pH}$ isa measure of the acidity or alkalinity of a solution. The pH scale generally varies from 0 to 14.

The equation for $\text{pH}$ is given by,

  ${\text{pH=-log[H}}^{\text{+}}\text{]}$ where, ${\text{[H}}^{+}]is\text{ concentration of hydrogen ion}\text{.}$

Answer to Problem 3RQ

The concentration of ${\text{H}}^{+}$ is $4.79\times {10}^{-5}\text{ M}$

Explanation of Solution

Here the $\text{pH}$ of the solution is 4.32.

  $\begin{array}{c}4.32=-log[H^{+}]\\ [H^{+}]=10^{-4.32}\\ =4.79\times 10^{-5}\end{array}$

(b)

Interpretation Introduction

Interpretation: The concentration of ${\text{H}}^{+}$ of the solution if pH is 11.15 needs to be determined.

Concept introduction: $\text{pH}$ is a measure of the acidity or alkalinity of a solution. The pH scale generally varies from 0 to 14.

The equation for $\text{pH}$ is given by,

  ${\text{pH=-log[H}}^{\text{+}}\text{]}$ where, ${\text{[H}}^{+}]is\text{ concentration of hydrogen ion}\text{.}$

Answer to Problem 3RQ

The concentration of ${\text{H}}^{+}$ is $7.08\times {10}^{-12}$ .

Explanation of Solution

Here the $\text{pH}$ of the solution is 11.15

  $\begin{array}{c}11.15=-log[H^{+}]\\ [H^{+}]=10^{-11.15}\\ =7.08\times 10^{-12}\end{array}$