Chapter 16, Problem 9A

(a)

Interpretation Introduction

Interpretation:

The conjugate acid of ${\text{HSO}}_{\text{4}}{}^{\text{-}}$ is to be written.

Concept Introduction :

The conjugate acid is the compound that is formed by the gaining of a proton by a base.

Answer to Problem 9A

The conjugate acid of ${\text{HSO}}_{\text{4}}{}^{\text{-}}$ is ${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$ .

Explanation of Solution

The given ion ${\text{HSO}}_{\text{4}}{}^{\text{-}}$ has one negative charge which means that it has the capacity of accepts one hydrogen ion. So, the conjugate acid of this acid is ${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$ .

  ${\text{HSO}}_{\text{4}}{}^{\text{-}}\text{+}{\text{H}}^{\text{+}}\to {\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$

(b)

Interpretation Introduction

Interpretation:

The conjugate acid of ${\text{ClO}}_{\text{4}}{}^{\text{-}}$ is to be written.

Concept Introduction :

The conjugate acid is the compound that is formed by the gaining of a proton by a base.

Answer to Problem 9A

The conjugate acid of ${\text{ClO}}_{\text{4}}{}^{\text{-}}$ is ${\text{HClO}}_{\text{4}}$ .

Explanation of Solution

The given ion ${\text{ClO}}_{\text{4}}{}^{\text{-}}$ has one negative charge which means that it has the capacity of accepts one hydrogen ion. So, the conjugate acid of this acid is ${\text{HClO}}_{\text{4}}$ .

  ${\text{ClO}}_{\text{4}}{}^{\text{-}}\text{+}{\text{H}}^{\text{+}}\to {\text{HClO}}_{\text{4}}$

(c)

Interpretation Introduction

Interpretation:

The conjugate acid of ${\text{SO}}_{\text{3}}{}^{\text{-2}}$ is to be written.

Concept Introduction :

The conjugate acid is the compound that is formed by gaining of a proton by a base.

Answer to Problem 9A

The conjugate acid of ${\text{SO}}_{\text{3}}{}^{\text{-2}}$ is ${\text{HSO}}_3{}^{-}$ .

Explanation of Solution

The given ion ${\text{SO}}_{\text{3}}{}^{\text{-2}}$ has one negative charge which means that it has the capacity of accepts one hydrogen ion. So, the conjugate acid of this acid is ${\text{HSO}}_3{}^{-}$ .

  ${\text{SO}}_{\text{3}}{}^{\text{-2}}\text{+}{\text{H}}^{\text{+}}\to {\text{HSO}}_{\text{3}}{}^{\text{-}}$

(d)

Interpretation Introduction

Interpretation:

The conjugate acid of ${\text{H}}_{\text{2}}{\text{PO}}_{\text{4}}{}^{\text{-}}$ is to be written.

Concept Introduction :

The conjugate acid is the compound that is formed by the gaining of a proton by a base.

Answer to Problem 9A

The conjugate acid of ${\text{H}}_{\text{2}}{\text{PO}}_{\text{4}}{}^{\text{-}}$ is ${\text{H}}_{\text{3}}{\text{PO}}_{\text{4}}{}^{\text{-}}$ .

Explanation of Solution

The given ion ${\text{H}}_{\text{2}}{\text{PO}}_{\text{4}}{}^{\text{-}}$ has one negative charge which means that it has the capacity of accepts one hydrogen ion. So, the conjugate acid of this acid is ${\text{H}}_{\text{3}}{\text{PO}}_{\text{4}}{}^{\text{-}}$ .

  ${\text{H}}_{\text{2}}{\text{PO}}_{\text{4}}{}^{\text{-}}\text{+}{\text{H}}^{\text{+}}\to {\text{H}}_{\text{3}}{\text{PO}}_{\text{4}}$