a) Interpretation: What is wrong with the scheme given above is to be stated. Concept introduction: Friedal-Crafts reaction is not possible with aromatic rings that are substituted either by a strongly with-drawing group such as carbonyl, nitrile or an amino group that can be protonated. To state: What is wrong with the scheme given above.

Question

LTS Solid: AT=Te-Ti Trial 1 Trial 2 Trial 3 Average ΔΗ Mass water, g 24.096 23.976 23.975 Moles of solid, mol 0.01763 001767 0101781 Temp. change, °C 2.9°C 11700 2.0°C Heat of reaction, J -292.37J -170.473 -193.26J AH, kJ/mole 16.58K 9.647 kJ 10.85 kr 16.58K59.64701 KJ mol 12.35k Minimum AS, J/mol K 41.582 mol-k Remember: q = mCsAT (m = mass of water, Cs=4.184J/g°C) & qsin =-qrxn & Show your calculations for: AH in J and then in kJ/mole for Trial 1: qa (24.0969)(4.1845/g) (-2.9°C)=-292.37J qsin = qrxn = 292.35 292.37J AH in J = 292.375 0.2923kJ 0.01763m01 =1.65×107 AH in kJ/mol = = 16.58K 0.01763mol mol qrx Minimum AS in J/mol K (Hint: use the average initial temperature of the three trials, con Kelvin.) AS=AHIT (1.65×10(9.64×103) + (1.0 Jimai

Answer 1

Question

Chapter 16.10, Problem 23P

Interpretation Introduction

a)

Interpretation:

What is wrong with the scheme given above is to be stated.

Concept introduction:

Friedal-Crafts reaction is not possible with aromatic rings that are substituted either by a strongly with-drawing group such as carbonyl, nitrile or an amino group that can be protonated.

To state:

What is wrong with the scheme given above.

Interpretation Introduction

b)

Interpretation:

What is wrong in the scheme given above is to be stated.

Concept introduction:

Chlorine is an ortho & para director in aromatic electrophilic substitution reactions. It also deactivates the ring towards electrophiles to some extent. Alkyl groups are also ortho & para directors but they activate the ring towards electrophiles.

To show:

What is wrong with the scheme given.

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LTS Solid: AT=Te-Ti Trial 1 Trial 2 Trial 3 Average ΔΗ Mass water, g 24.096 23.976 23.975 Moles of solid, mol 0.01763 001767 0101781 Temp. change, °C 2.9°C 11700 2.0°C Heat of reaction, J -292.37J -170.473 -193.26J AH, kJ/mole 16.58K 9.647 kJ 10.85 kr 16.58K59.64701 KJ mol 12.35k Minimum AS, J/mol K 41.582 mol-k Remember: q = mCsAT (m = mass of water, Cs=4.184J/g°C) & qsin =-qrxn & Show your calculations for: AH in J and then in kJ/mole for Trial 1: qa (24.0969)(4.1845/g) (-2.9°C)=-292.37J qsin = qrxn = 292.35 292.37J AH in J = 292.375 0.2923kJ 0.01763m01 =1.65×107 AH in kJ/mol = = 16.58K 0.01763mol mol qrx Minimum AS in J/mol K (Hint: use the average initial temperature of the three trials, con Kelvin.) AS=AHIT (1.65×10(9.64×103) + (1.0 Jimai

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