Problem Solving with C++ (10th Edition)
10th Edition
ISBN: 9780134448282
Author: Walter Savitch, Kenrick Mock
Publisher: PEARSON
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Textbook Question
Chapter 16.1, Problem 9STE
What is the output produced by the
| sampleFunction(98.6); in the try block to sampleFunction(212); |
8. What is the output produced by the following program?
| #include <iostream> using namespace std; void sampleFunction(double test) throw (int); int main() { try { cout << "Trying.\n"; sampleFunction(98.6); cout << "Trying after call.\n"; } catch(int) { cout << "Catching.\n"; } cout << "End of program.\n"; return 0; } void sampleFunction(double test) throw (int) { cout << "Starting sampleFunction.\n"; if (test < 100) throw 42; } |
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2- Trace the following code and write the output:
class Test1 {
Test1(int x)
{
System.out.println("Test Calls " + x);
class
Test2 {
Testi t1 = new Test1(10);
Test2(int i) { t1 = new Test1(i); }
public static void main(String[]
args)
{
Test2 t2 = new Test2(5);
You are working on problem set: HW2 - loops (Pause)
Pause)
? variableScope ♡
Language/Type:
Java expressions for %
A variable's scope is the part of a program in which it exists. In Java, the scope of a
variable starts when it is declared and ends when the closing curly brace for the block
that contains it is reached. A variable is said to be in scope where it is accessible.
Consider the following program:
public class Example {
public static void main(String[] args) {
performTest ();
}
}
public static void performTest() {
int count = 12:
for (int i = 1; i <= 12; i++) {
runSample();
K
}
}
}
System.out.print(count);
public static void runSample() {
System.out.print("sample");
7
с
M
31
In which of these blocks is the variable count in scope for the entirety of the block?
runSample method
a.
b.
main method
c.
for loop
d. O performTest method
(order shuffled)
In which of these blocks is the variable i in scope for the entirety of the block?
a. O main method
b. O runSample method
c. O…
QUESTION 4
Analyze the following code:
public class Test {
public static void main (String [] args) {
int i = 0;
while (i ++ < 10);
System.out.println(i + 4);
The program compiles despite the semicolon () on the for loop line, and displays 15.
The program has a compile error because of the semicolon (;) on the while loop line.
The program compiles despite the semicolon (:) on the while loop line, and displays 4.
Chapter 16 Solutions
Problem Solving with C++ (10th Edition)
Ch. 16.1 - Prob. 1STECh. 16.1 - What would be the output produced by the code in...Ch. 16.1 - Prob. 3STECh. 16.1 - What happens when a throw statement is executed?...Ch. 16.1 - In the code given in Self-Test Exercise 1, what is...Ch. 16.1 - Prob. 6STECh. 16.1 - Prob. 7STECh. 16.1 - What is the output produced by the following...Ch. 16.1 - What is the output produced by the program in...Ch. 16.2 - Prob. 10STE
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