Chapter 16.1, Problem 2PPB

(a)

Interpretation Introduction

Interpretation:

1. (a) An equation for the reaction of ${\text{HSO}}_{\text{3}}{}^{\text{-}}$ with water to form its conjugate base has to be written

1. (b) An equation for the reaction of ${\text{HSO}}_{\text{3}}{}^{\text{-}}$ with water to form its conjugate acid has to be written

Concept Information:

When a Bronsted acid donates a proton, what remains of the acid is known as a conjugate base; when a Bronsted base accepts a proton, the newly formed protonated species is known as a conjugate acid.  This can be given by the below equation as shown in Figure 1.

Figure 1

The reactant that loses a proton is the acid and the reactant that gains a proton is the base.

Each product is the conjugate of one of the reactant.

Two species that differ only by a proton constitute a conjugate pair

Addition of proton to a species gives its conjugate acid whereas removal of proton from a species gives its conjugate base.

To Write: An equation for the reaction of ${\text{HSO}}_{\text{3}}{}^{\text{-}}$ with water to form its conjugate base

(b)

Interpretation Introduction

Interpretation:

1. (a) An equation for the reaction of ${\text{HSO}}_{\text{3}}{}^{\text{-}}$ with water to form its conjugate base has to be written

1. (b) An equation for the reaction of ${\text{HSO}}_{\text{3}}{}^{\text{-}}$ with water to form its conjugate acid has to be written

Concept Information:

When a Bronsted acid donates a proton, what remains of the acid is known as a conjugate base; when a Bronsted base accepts a proton, the newly formed protonated species is known as a conjugate acid.  This can be given by the below equation as shown in Figure 1.

Figure 1

The reactant that loses a proton is the acid and the reactant that gains a proton is the base.

Each product is the conjugate of one of the reactant.

Two species that differ only by a proton constitute a conjugate pair

Addition of proton to a species gives its conjugate acid whereas removal of proton from a species gives its conjugate base.

To Write: An equation for the reaction of ${\text{HSO}}_{\text{3}}{}^{\text{-}}$ with water to form its conjugate acid