(a)
Interpretation:
The standard enthalpy change (ΔH°) for the following reaction should be determined:
Concept introduction:
The standard enthalpy of fusion refers to the amount of heat required to melt 1 mole of a solid at its melting point. In the case of ice, the melting point is 0°C.
(b)
Interpretation:
The standard free change (ΔG°) for the following reaction should be determined
Concept introduction:
The change in the Gibbs free energy, ΔG is a
where,
(c)
Interpretation:
The standard free change (?S°) for the following reaction should be determined:
Concept introduction:
Entropy (S) is a thermodynamic function which measures the disorder or the degree of randomness of a system.
A fusion reaction which involves melting of solid is accompanied by an increase in entropy. The standard molar entropy is expressed as
(d)
Interpretation:
The standard free change (ΔG°) for the following reaction at T = -20 o C should be determined:
Concept introduction:
The change in the Gibbs free energy, ΔG is a thermodynamic function which governs the spontaneity of a chemical reaction. It is the amount of energy required to perform useful work The standard Gibbs free energy
where,
(e)
Interpretation:
The standard free change (ΔG°) for the following reaction at T = 20° C should be determined:
Concept introduction:
The change in the Gibbs free energy, ΔG is a thermodynamic function which governs the spontaneity of a chemical reaction. It is the amount of energy required to perform useful work The standard Gibbs free energy
where,
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PRINCIPLES+REACTIONS
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- For a certain chemical reaction, ΔH° = -35.4 kJ andΔS° = -85.5 J/K. (a) Is the reaction exothermic or endothermic?(b) Does the reaction lead to an increase ordecrease in the randomness or disorder of the system?(c) Calculate ΔG° for the reaction at 298 K. (d) Is the reactionspontaneous at 298 K under standard conditions?arrow_forwardFor a particular reaction, ΔH = -32 kJ and ΔS = -98 J/K.Assume that ΔH and ΔS do not vary with temperature.(a) At what temperature will the reaction have ΔG = 0?(b) If T is increased from that in part (a), will the reactionbe spontaneous or nonspontaneous?arrow_forwardThe Haber process for the production of ammonia involves the equilibriumN2(g) + 3 H2(g)⇌ 2 NH3(g)For this reaction, ΔH° = -92.38 kJ and ΔS° = -198.3 J/K. Assume that ΔH° and ΔS° for this reaction do not change withtemperature. (a) Predict the direction in which ΔG for the reaction changes with increasing temperature. (b) Calculate ΔG at25 °C and at 500 °C.arrow_forward
- Which statement is true regarding the sublimation of dry ice (solid CO2)?(a) ΔH is positive, ΔS is positive, and ΔG is positive at low temperatures andnegative at high temperatures.(b) ΔH is negative, ΔS is negative, and ΔG is negative at low temperatures andpositive at high temperatures.(c) ΔH is negative, ΔS is positive, and ΔG is negative at all temperatures.(d) ΔH is positive, ΔS is negative, and ΔG is positive at all temperatures.arrow_forwardCalculate the equilibrium constant at 25 °C for each of the following reactions from the value of ΔG° given.(a) O2(g)+2F2(g)⟶2OF2(g) ΔG°=−9.2 kJ(b) I2(s)+Br2(l)⟶2IBr(g) ΔG°=7.3 kJ(c) 2LiOH(s)+CO2(g)⟶Li2CO3(s)+H2O(g) ΔG°=−79 kJarrow_forwardBromine monochloride is formed from the elements:Cl₂(g) +Br₂(g) ⇌2BrCl(g) ΔH°ᵣₙₓ =-1.35 kJ/mol ΔG°(f)=-0.88 kJ/molCalculate (a) ΔH°(f) and (b) S° of BrCl(g).arrow_forward
- For a certain chemical reaction, ΔH°= ‒40.0 kJ and ΔS°= ‒150.0 J/K.(a) Does the reaction lead to an increase or decrease in the randomness or disorder of the system?(b) Does the reaction lead to an increase or decrease in the randomness or disorder of the surroundings?(c) Calculate ΔG° for the reaction at 298 K.(d) Is the reaction spontaneous at 298 K under standard conditions?arrow_forwardCalculate the equilibrium constant at 25 °C for each of the following reactions from the value of ΔG° given.(a) O2(g) + 2F2(g) ⟶ 2OF2(g) ΔG° = −9.2 kJ(b) I2(s) + Br2(l) ⟶ 2IBr(g) ΔG° = 7.3 kJ(c) 2LiOH(s) + CO2(g) ⟶ Li2 CO3(s) + H2 O(g) ΔG° = −79 kJ(d) N2 O3(g) ⟶ NO(g) + NO2(g) ΔG° = −1.6 kJ(e) SnCl4(l) ⟶ SnCl4(l) ΔG° = 8.0 kJarrow_forwardCalculate the equilibrium constant at 25 °C for each of the following reactions from the value of ΔG° given.(a) I2(s) + Cl2(g) ⟶ 2ICl(g) ΔG° = −10.88 kJ(b) H2(g) + I2(s) ⟶ 2HI(g) ΔG° = 3.4 kJ(c) CS2(g) + 3Cl2(g) ⟶ CCl4(g) + S2 Cl2(g) ΔG° = −39 kJ(d) 2SO2(g) + O2(g) ⟶ 2SO3(g) ΔG° = −141.82 kJ(e) CS2(g) ⟶ CS2(l) ΔG° = −1.88 kJarrow_forward
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