Fill in the blanks: (a) At equilibrium, ΔG is. (b) For C 6 H 6 ( l ) ⇌ C 6 H 6 ( g ) , Δ H ° is. ( + , − , 0 ) (c) When a pure solid melts, the temperature at which liquid and solid are in equilibrium and Δ G ° = 0 is called.
Fill in the blanks: (a) At equilibrium, ΔG is. (b) For C 6 H 6 ( l ) ⇌ C 6 H 6 ( g ) , Δ H ° is. ( + , − , 0 ) (c) When a pure solid melts, the temperature at which liquid and solid are in equilibrium and Δ G ° = 0 is called.
Solution Summary: The author explains the relationship between the value of Delta G and K (equilibrium constant) as follows: if heat is given to the system, the reaction is endothermic.
Fill in the blanks: (a) At equilibrium, ΔG is. (b) For
C
6
H
6
(
l
)
⇌
C
6
H
6
(
g
)
,
Δ
H
°
is.
(
+
,
−
,
0
)
(c) When a pure solid melts, the temperature at which liquid and solid are in equilibrium and
Δ
G
°
=
0
is called.
The Haber process for the production of ammonia involves the equilibriumN2(g) + 3 H2(g)⇌ 2 NH3(g)For this reaction, ΔH° = -92.38 kJ and ΔS° = -198.3 J/K. Assume that ΔH° and ΔS° for this reaction do not change withtemperature. (a) Predict the direction in which ΔG for the reaction changes with increasing temperature. (b) Calculate ΔG at25 °C and at 500 °C.
The evaporation of one mole of water at 298 K has a standard free energy change of 8.58 kJ.H2O(l) ⇌ H2O(g) ΔG°298 = 8.58 kJ(a) Is the evaporation of water under standard thermodynamic conditions spontaneous?(b) Determine the equilibrium constant, KP, for this physical process.(c) By calculating ΔG, determine if the evaporation of water at 298 K is spontaneous when the partial pressure of water, PH2 O, is 0.011 atm.(d) If the evaporation of water were always nonspontaneous at room temperature, wet laundry would never dry when placed outside. In order for laundry to dry, what must be the value of PH2 O in the air?
A key step in the metabolism of glucose for energy is theisomerization of glucose-6-phosphate (G6P) to fructose-6- phosphate (F6P): G6P⇌F6P; K=0.510 at 298 K.(a) Calculate ΔG° at 298 K.(b) Calculate ΔG when Q, the [F6P]/[G6P] ratio, equals 10.0.(c) Calculate ΔG when Q=0.100.(d) Calculate Q if ΔG =-2.50 kJ/mol.
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
The Laws of Thermodynamics, Entropy, and Gibbs Free Energy; Author: Professor Dave Explains;https://www.youtube.com/watch?v=8N1BxHgsoOw;License: Standard YouTube License, CC-BY