Chapter 16, Problem 79E

Interpretation Introduction

Interpretation: The plot of $\ln K$ versus $1/T$ and a relation of $\ln K$ with $\Delta H°,\Delta S°$ is given. The values of $\Delta H°,\Delta S°$ is to be calculated from the given plot. Any difference in the plot of $\ln K$ versus $1/T$ for endothermic and exothermic reaction is to be stated.

Concept introduction: The plot of $\ln K$ versus $1/T$ is a straight line. If the slope of this plot is negative, then the reaction will be endothermic, whereas if the slope of this plot is positive, then the reaction will be exothermic.

The expression for free equilibrium constant is,

$\ln \left(K\right)=\frac{-\Delta H°}{RT}+\frac{\Delta S°}{R}$