(1) Explanation Given info: The length of the window is 5.0 ft , the breadth of the window is 2. 5 ft , number of windows is 10 , the rate at which four windows admit energy is 30 Btu / h ⋅ ft 2 , R factor is 0.90 , heat energy produced for every gallon of oil is 100 , 000 Btu and cost per gallon oil is $ 3.48 . Explanation: Write the expression for the rate of heat loss through the thermal conductors. H = − k A Δ T Δ x Here, H is the rate of heat loss through the thermal conductor k is the thermal conductivity of thermal conductor A is the area of the conductor Δ T is the temperature difference between two ends of the conductor Δ x is the thickness of the thermal conductor Substitute R for Δ x k in the above equation to get H H = − A Δ T R (1) Here, R is the R -factor of the conductor Write the expression for the window area. A = ( l b ) Here, l is the length of the window b is the breadth of the window Substitute 5.0 ft for l and 2. 5 ft for b in above equation to get A . A = ( 5.0 ft × 2. 5 ft ) = 12.5 ft 2 Then area of 10 windows equal to 10 × 12.5 ft 2 = 125 ft 2 . Total area of the walls is 1506 ft 2 . Area of the wall excluding windows is 1506 ft 2 − 125 ft 2 = 1381 ft 2 . Substitute 1381 ft 2 for A , 50 ° F for Δ T and 1 12.37 Btu h ⋅ ft 2 ⋅ ° F for 1 R in the equation (1) to get H walls . H walls = 1 12.37 Btu h ⋅ ft 2 ⋅ ° F ( 1381 ft 2 ) ( 50 ° F ) = 5583 Btu / h Here, H walls is the rate at which heat flows through walls of the house Area of one window is Substitute 1164 ft 2 for A , 50 ° F for Δ T and 1 31.37 Btu h ⋅ ft 2 ⋅ ° F for 1 R in the equation (1) to get H roof . H roof = 1 31.37 Btu h ⋅ ft 2 ⋅ ° F ( 1164 ft 2 ) ( 50 ° F ) = 1855 Btu / h Here, H roof is the rate at which heat flows through roof of the house In the case of windows, four windows admit solar energy at the rate of 30 Btu / h ⋅ ft 2 (b) To determine The solar gain from the south windows.

Essential University Physics Volume 1, Loose Leaf Edition (4th Edition)

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ISBN: 9780135264669

Author: Richard Wolfson

Publisher: PEARSON

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Chapter 16, Problem 69P

(1)

To determine

The total heating cost per month.

(b)

To determine

The solar gain from the south windows.

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Chapter 16, Problem 68P

Chapter 16, Problem 70P

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Chapter 16 Solutions

Essential University Physics Volume 1, Loose Leaf Edition (4th Edition)

Ch. 16.1 - Is there (a) no temperature, (b) one temperature,...Ch. 16.2 - A hot rock with mass 250 g is dropped into an...Ch. 16.3 - The figure shows three slabs with the same...Ch. 16.3 - Prob. 16.4GI Ch. 16.4 - A houses thermostat fails, leaving the furnace...Ch. 16 - If system A is not in thermodynamic equilibrium...Ch. 16 - Does a thermometer measure its own temperature or...Ch. 16 - Compare the relative sizes of the kelvin, the...Ch. 16 - If you put a thermometer in direct sunlight, what...Ch. 16 - Why does the temperature in a stone building...

Ch. 16 - Why do large bodies of water exert a...Ch. 16 - A Thermos bottle consists of an evacuated,...Ch. 16 - Stainless-steel cookware often has a layer of...Ch. 16 - Prob. 9FTD Ch. 16 - Prob. 10FTD Ch. 16 - Glass and fiberglass are made from the same...Ch. 16 - To keep your hands warm while skiing, you should...Ch. 16 - Since Earth is exposed to solar radiation, why...Ch. 16 - Global warming at Earths surface is generally...Ch. 16 - In its 2014 report, the Intergovernmental Panel on...Ch. 16 - A Canadian meteorologist predicts an overnight low...Ch. 16 - Normal room temperature is 68F. Whats this in...Ch. 16 - Prob. 18E Ch. 16 - At what temperature do the Fahrenheit and Celsius...Ch. 16 - The normal boiling point of nitrogen is 77.3 K....Ch. 16 - Prob. 21E Ch. 16 - Prob. 22E Ch. 16 - Prob. 23E Ch. 16 - Whats the specific heat of a material if it takes...Ch. 16 - The average human diet contains about 2000 kcal...Ch. 16 - Prob. 26E Ch. 16 - You bring a 350-g wrench into the house from your...Ch. 16 - Prob. 28E Ch. 16 - Building heat loss in the United States is usually...Ch. 16 - Find the heat-loss rate through a slab of (a) wood...Ch. 16 - The top of a steel wood stove measures 90 cm by 40...Ch. 16 - Youre a builder whos advising a homeowner to have...Ch. 16 - An 8.0 m by 12 m house is built on a concrete slab...Ch. 16 - Find the -factor for a wall that loses 0.040 Btu...Ch. 16 - Compute the -factors for 1-inch thicknesses of...Ch. 16 - A horseshoe has surface area 50 cm2, and a...Ch. 16 - An oven loses energy at the rate of 14 W per C...Ch. 16 - Youre having your homes heating system replaced,...Ch. 16 - The filament of a 100-W lightbulb is at 3.0 kK....Ch. 16 - A typical human body has surface area 1.4 nr and...Ch. 16 - A constant-volume gas thermometer is filled with...Ch. 16 - A constant-volume gas thermometer is at 55-kPa...Ch. 16 - In Fig. 16.2s gas thermometer, the height h is...Ch. 16 - Prob. 44P Ch. 16 - Typical fats contain about 9 kcal per gram. If the...Ch. 16 - A circular lake 1.0 km in diameter is 10 m deep...Ch. 16 - How much heat is required to raise an 800-g copper...Ch. 16 - Initially, 100 g of water and 100 g of another...Ch. 16 - Prob. 49P Ch. 16 - Two neighbors return from Florida to find their...Ch. 16 - Prob. 51P Ch. 16 - Prob. 52P Ch. 16 - Prob. 53P Ch. 16 - The temperature of the eardrum provides a reliable...Ch. 16 - Prob. 55P Ch. 16 - Your young niece complains that her cocoa, at 90C,...Ch. 16 - A piece of copper at 300C is dropped into 1.0 kg...Ch. 16 - While camping, you boil water to make spaghetti....Ch. 16 - A biology labs walk-in cooler measures 3.0 m by...Ch. 16 - One end of an iron rod 40 cm long and 3.0 cm in...Ch. 16 - Prob. 61P Ch. 16 - An electric stove burner has surface area 325 cm2...Ch. 16 - An electric current passes through a metal strip...Ch. 16 - Youre considering purchasing a new sleeping bag...Ch. 16 - A blacksmith heats a 1.1-kg iron horseshoe to...Ch. 16 - Whats the power output of a microwave oven that...Ch. 16 - A cylindrical log 15 cm in diameter and 65 cm long...Ch. 16 - A blue giant star whose surface temperature is 23...Ch. 16 - Prob. 69P Ch. 16 - A black wood stove with surface area 4.6 nr is...Ch. 16 - Estimate the average temperature on Pluto,...Ch. 16 - Prob. 72P Ch. 16 - Prob. 73P Ch. 16 - Prob. 74P Ch. 16 - Prob. 75P Ch. 16 - In a cylindrical pipe where area isnt constant....Ch. 16 - Prob. 77P Ch. 16 - Prob. 78P Ch. 16 - Prob. 79P Ch. 16 - Use the method outlined in Problem 76 to show that...Ch. 16 - A house is at 20C on a winter night when the...Ch. 16 - A more realistic approach to the solar greenhouse...Ch. 16 - Fiberglass is a popular, economical, and fairly...Ch. 16 - Fiberglass is a popular, economical, and fairly...Ch. 16 - Fiberglass is a popular, economical, and fairly...Ch. 16 - Fiberglass is a popular, economical, and fairly...

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The total heating cost per month.

Solution Summary: The author explains the calculation of the total heating cost per month, which is 322/mo.

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The total heating cost per month.

The solar gain from the south windows.

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Chapter 16 Solutions