To determine The total rate of heat loss from the person. Explanation Given: Surface area of the person ( A s ) is 1.7 m 2 . Surface temperature of the person ( T s ) is 32 ° C . Convective heat transfer coefficient ( h ) is 5 W / m 2 ⋅ K . Emissivity between the man and air ( ε ) is 0.9 . Calculation: Determine the radiation heat loss. Q ˙ rad = ε α A s ( T s 4 − T surr 4 ) = ( 0.90 ) ( 5.67 × 10 − 8 W / m 2 ⋅ K 4 ) ( 1.7 m 2 ) [ ( 32 ° C + 273 K ) 4 − ( 18 ° C + 273 K ) 4 ] = 128

Fundamentals Of Thermal-fluid Sciences In Si Units

5th Edition

ISBN: 9789814720953

Author: Yunus Cengel, Robert Turner, John Cimbala

Publisher: McGraw-Hill Education

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Chapter 16, Problem 65P

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The total rate of heat loss from the person.

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Chapter 16, Problem 64P

Chapter 16, Problem 66P

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Chapter 16 Solutions

Fundamentals Of Thermal-fluid Sciences In Si Units

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