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Compound B
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Organic Chemistry
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- Compound I (C11H14O2) is insoluble in water, aqueous acid, and aqueous NaHCO3, but dissolves readily in 10% Na2CO3 and 10% NaOH. When these alkaline solutions are acidified with 10% HCl, compound I is recovered unchanged. Given this information and its 1H-NMR spectrum, deduce the structure of compound I.arrow_forwardPropose a structure for compound X (molecular formula C6H12O2), which gives a strong peak in its IR spectrum at 1740 cm−1. The 1H NMR spectrum of X shows only two singlets, including one at 3.5 ppm. The 13C NMR spectrum is given below. Propose a structure for X.arrow_forwardA compound with the molecular formula shown below exhibits a 1H NMR spectrum with only one signal. Deduce the structure in each case. (a) C5H10arrow_forward
- Propose a structural formula for the analgesic phenacetin, molecular formula C10H13NO2, based on its 1H-NMR spectrum.arrow_forwardCompound H (C8H6O3) gives a precipitate when treated with hydroxylamine in aqueous ethanol and a silver mirror when treated with Tollens solution. Following is its 1H-NMR spectrum. Deduce the structure of compound H.arrow_forwardThe 1H and 13C NMR spectra below belong to a compound with formula C6H10O2. Propose a structure for this compound.arrow_forward
- Propose a structure of compound C (molecular formula C10H12O) consistent with the following data. C is partly responsible for the odor and flavor of raspberries. Compound C: IR absorption at 1717 cm–1arrow_forwardAn unknown compound D exhibits a strong absorption in its IR spectrumat 1692 cm−1. The mass spectrum of D shows a molecular ion at m/z =150 and a base peak at 121. The 1H NMR spectrum of D is shown below.What is the structure of D?arrow_forwardAcid-catalyzed hydrolysis of HOCH2CH2C(CH3)2CN forms compound A (C6H10O2). A shows a strong peak in its IR spectrum at 1770 cm-1 and the following signals in its 1H NMR spectrum: 1.27 (singlet, 6 H), 2.12 (triplet, 2 H), and 4.26 (triplet, 2 H) ppm. Draw the structure for A and give a stepwise mechanism that accounts for its formation.arrow_forward
- An unknown compound has a molecular formula of C4H6O2. Its IR spectrum shows absorptions at 3095, 1762, 1254, and 1118 cm -1. It exhibits the following signals in its 1H NMR spectrum (ppm): 2.12 (singlet,3H), 4.55 (doublets of doublets, 1H), 4.85 (doublet of doublets, 1H), 7.25 (doublets of doublets, 1H); and the following signals in its 13C NMR spectrum (ppm): 20.8, 100.4, 141.2, 168.0. Draw the structure of the unknown compoundarrow_forwardAn unknown compound C of molecular formula C6H12O3 exhibits a strong absorption in its IR spectrum at 1718 cm−1 and the given 1H NMR spectrum. What is the structure of C?arrow_forwardWhen compound A (C5H12O) is treated with HBr, it forms compound B (C5H11Br). The 1H NMR spectrum of compound A has a 1H singlet, a 3H doublet, a 6H doublet, and two 1H multiplets. The 1H NMR spectrum of compound B has a 6H singlet, a 3H triplet, and a 2H quartet. Identify compounds A and B.arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning