Owlv2 With Mindtap Reader, 1 Term (6 Months) Printed Access Card For Tro's Chemistry In Focus: A Molecular View Of Our World, 7th
7th Edition
ISBN: 9781337399807
Author: Tro, Nivaldo J.
Publisher: Cengage Learning
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Chapter 16, Problem 33E
Interpretation Introduction
Interpretation:
The recombinant DNA is to be explained.
Concept Introduction:
DNA contains the genetic material in living organisms.
It is stored in the nucleus and the proteins are synthesized from the amino acids in ribosomes. mRNA carries a copy of the DNA base sequence of a specific gene to the ribosome, where protein synthesis takes place.
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Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard
the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.
For the decomposition reaction of N2O5(g): 2 N2O5(g) · 4 NO2(g) + O2(g), the following mechanism has been proposed:
N2O5
-> NO2 + NO3_(K1)
NO2 + NO3 →> N2O5 (k-1)
→
NO2 + NO3
→
NO2 + O2 + NO (K2)
NO + N2O5
→ NO2 + NO2 + NO2 (K3)
Give the expression for the acceptable rate.
(A).
d[N₂O]
dt
=
-1
2k,k₂[N205]
k₁+k₂
d[N₂O5]
(B).
dt
=-k₁[N₂O₂] + k₁[NO2][NO3] - k₂[NO2]³
(C).
d[N₂O]
dt
=-k₁[N₂O] + k₁[N205] - K3 [NO] [N205]
(D).
d[N2O5]
=-k₁[NO] - K3[NO] [N₂05]
dt
A 0.10 M solution of acetic acid (CH3COOH, Ka = 1.8 x 10^-5) is titrated with a 0.0250 M solution of magnesium hydroxide (Mg(OH)2). If 10.0 mL of the acid solution is titrated with 20.0 mL of the base solution, what is the pH of the resulting solution?
For the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed:
N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3)
→
Give the expression for the acceptable rate.
→
→
(A).
d[N205]
dt
==
2k,k₂[N₂O₂]
k₁+k₁₂
(B).
d[N2O5]
=-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³
dt
(C).
d[N2O5]
=-k₁[N₂O] + k [NO] - k₂[NO] [NO]
d[N2O5]
(D).
=
dt
= -k₁[N2O5] - k¸[NO][N₂05]
dt
Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard
the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.
Chapter 16 Solutions
Owlv2 With Mindtap Reader, 1 Term (6 Months) Printed Access Card For Tro's Chemistry In Focus: A Molecular View Of Our World, 7th
Ch. 16 - Prob. 1SCCh. 16 - Prob. 2SCCh. 16 - Prob. 3SCCh. 16 - Prob. 4SCCh. 16 - Prob. 16.1YTCh. 16 - Saturated and Unsaturated Fats Which of the...Ch. 16 - Prob. 16.3YTCh. 16 - Prob. 16.4YTCh. 16 - Identifying Amino Acids Which of the following...Ch. 16 - Drawing Peptide Structures Draw the tripeptide...
Ch. 16 - DNA Complementarity Draw the complementary strand...Ch. 16 - List the four major classes of biochemical...Ch. 16 - Why are fats more efficient than carbohydrates for...Ch. 16 - Prob. 3ECh. 16 - Prob. 4ECh. 16 - Prob. 5ECh. 16 - Why do carbohydrates contain less energy per gram...Ch. 16 - Prob. 7ECh. 16 - Prob. 8ECh. 16 - Prob. 9ECh. 16 - Prob. 10ECh. 16 - Prob. 11ECh. 16 - Prob. 12ECh. 16 - Prob. 13ECh. 16 - Prob. 14ECh. 16 - Prob. 15ECh. 16 - Prob. 16ECh. 16 - Prob. 17ECh. 16 - Prob. 18ECh. 16 - Prob. 19ECh. 16 - Prob. 20ECh. 16 - Prob. 21ECh. 16 - Prob. 22ECh. 16 - Prob. 23ECh. 16 - What is the difference between DNA and RNA?Ch. 16 - Prob. 25ECh. 16 - Prob. 26ECh. 16 - What are chromosomes? How many exist in humans?Ch. 16 - Prob. 28ECh. 16 - Prob. 29ECh. 16 - Prob. 30ECh. 16 - Draw a schematic diagram of DNA. Show the...Ch. 16 - Prob. 32ECh. 16 - Prob. 33ECh. 16 - Prob. 34ECh. 16 - Explain how recombinant DNA technology has made...Ch. 16 - Prob. 36ECh. 16 - Prob. 37ECh. 16 - How can genetic engineering be used to treat...Ch. 16 - Prob. 39ECh. 16 - Prob. 40ECh. 16 - Prob. 41ECh. 16 - What are the dangers inherent in applying genetic...Ch. 16 - Prob. 43ECh. 16 - Prob. 44ECh. 16 - Prob. 45ECh. 16 - Prob. 46ECh. 16 - Prob. 47ECh. 16 - Prob. 48ECh. 16 - Prob. 49ECh. 16 - Prob. 50ECh. 16 - Prob. 51ECh. 16 - Prob. 52ECh. 16 - Prob. 53ECh. 16 - Prob. 54ECh. 16 - Which molecule is an amino acid?Ch. 16 - Which molecule is an amino acid?Ch. 16 - Prob. 57ECh. 16 - Classify each molecule as a lipid, carbohydrate,...Ch. 16 - Prob. 59ECh. 16 - Draw the structure for the dipeptide Ala-Gly. How...Ch. 16 - Draw the structure for the tripeptide Leu-Leu-Leu....Ch. 16 - Draw the structure for the tripeptide Ser-Ser-Ser....Ch. 16 - Prob. 63ECh. 16 - Prob. 64ECh. 16 - Prob. 65ECh. 16 - Prob. 66ECh. 16 - Prob. 67ECh. 16 - Prob. 68ECh. 16 - Prob. 69ECh. 16 - Prob. 70ECh. 16 - Prob. 71ECh. 16 - Prob. 72ECh. 16 - Prob. 73E
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- For the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed: N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3) → Give the expression for the acceptable rate. → → (A). d[N205] dt == 2k,k₂[N₂O₂] k₁+k₁₂ (B). d[N2O5] =-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³ dt (C). d[N2O5] =-k₁[N₂O] + k [NO] - k₂[NO] [NO] d[N2O5] (D). = dt = -k₁[N2O5] - k¸[NO][N₂05] dt Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.arrow_forwardR lactam or lactone considering as weak acid or weak base and whyarrow_forward81. a. Propose a mechanism for the following reaction: OH CH2=CHCHC=N b. What is the product of the following reaction? HO H₂O N=CCH2CH2CH OH HO CH3CCH=CH2 H₂O C=N 82. Unlike a phosphonium ylide that reacts with an aldehyde or a ketone to form an alkene a sulfonium uliaarrow_forward
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