Chemistry In Focus
Chemistry In Focus
6th Edition
ISBN: 9781305084476
Author: Tro, Nivaldo J., Neu, Don.
Publisher: Cengage Learning
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Chapter 16, Problem 31E

Draw a schematic diagram of DNA. Show the double-helix structure, the molecular backbone, and the complementary nature of the base pairs.

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5. A solution of sucrose is fermented in a vessel until the evolution of CO2 ceases. Then, the product solution is analyzed and found to contain, 45% ethanol; 5% acetic acid; and 15% glycerin by weight. If the original charge is 500 kg, evaluate; e. The ratio of sucrose to water in the original charge (wt/wt). f. Moles of CO2 evolved. g. Maximum possible amount of ethanol that could be formed. h. Conversion efficiency. i. Per cent excess of excess reactant. Reactions: Inversion reaction: C12H22O11 + H2O →2C6H12O6 Fermentation reaction: C6H12O6 →→2C2H5OH + 2CO2 Formation of acetic acid and glycerin: C6H12O6 + C2H5OH + H₂O→ CH3COOH + 2C3H8O3
Show work. don't give Ai generated solution.  How many carbons and hydrogens are in the structure?
13. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B 2°C. +2°C. cleavage Bond A •CH3 + 26.← Cleavage 2°C. + Bond C +3°C• CH3 2C Cleavage E 2°C. 26. weakest bond Intact molecule Strongest 3°C 20. Gund Largest argest a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. C Weakest bond A Produces Most Bond Strongest Bond Strongest Gund produces least stable radicals Weakest Stable radical b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. 13°C. formed in bound C cleavage ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. • CH3 methyl radical Formed in Gund A Cleavage c.…

Chapter 16 Solutions

Chemistry In Focus

Ch. 16 - DNA Complementarity Draw the complementary strand...Ch. 16 - List the four major classes of biochemical...Ch. 16 - Why are fats more efficient than carbohydrates for...Ch. 16 - Prob. 3ECh. 16 - Prob. 4ECh. 16 - Prob. 5ECh. 16 - Why do carbohydrates contain less energy per gram...Ch. 16 - Prob. 7ECh. 16 - Prob. 8ECh. 16 - Prob. 9ECh. 16 - Prob. 10ECh. 16 - Prob. 11ECh. 16 - Prob. 12ECh. 16 - Prob. 13ECh. 16 - Prob. 14ECh. 16 - Prob. 15ECh. 16 - Prob. 16ECh. 16 - Prob. 17ECh. 16 - Prob. 18ECh. 16 - Prob. 19ECh. 16 - Prob. 20ECh. 16 - Prob. 21ECh. 16 - Prob. 22ECh. 16 - Prob. 23ECh. 16 - What is the difference between DNA and RNA?Ch. 16 - Prob. 25ECh. 16 - Prob. 26ECh. 16 - What are chromosomes? How many exist in humans?Ch. 16 - Prob. 28ECh. 16 - Prob. 29ECh. 16 - Prob. 30ECh. 16 - Draw a schematic diagram of DNA. Show the...Ch. 16 - Prob. 32ECh. 16 - Prob. 33ECh. 16 - Prob. 34ECh. 16 - Explain how recombinant DNA technology has made...Ch. 16 - Prob. 36ECh. 16 - Prob. 37ECh. 16 - How can genetic engineering be used to treat...Ch. 16 - Prob. 39ECh. 16 - Prob. 40ECh. 16 - Prob. 41ECh. 16 - What are the dangers inherent in applying genetic...Ch. 16 - Prob. 43ECh. 16 - Prob. 44ECh. 16 - Prob. 45ECh. 16 - Prob. 46ECh. 16 - Prob. 47ECh. 16 - Prob. 48ECh. 16 - Prob. 49ECh. 16 - Prob. 50ECh. 16 - Prob. 51ECh. 16 - Prob. 52ECh. 16 - Prob. 53ECh. 16 - Prob. 54ECh. 16 - Which molecule is an amino acid?Ch. 16 - Which molecule is an amino acid?Ch. 16 - Prob. 57ECh. 16 - Classify each molecule as a lipid, carbohydrate,...Ch. 16 - Prob. 59ECh. 16 - Draw the structure for the dipeptide Ala-Gly. How...Ch. 16 - Draw the structure for the tripeptide Leu-Leu-Leu....Ch. 16 - Draw the structure for the tripeptide Ser-Ser-Ser....Ch. 16 - Prob. 63ECh. 16 - Prob. 64ECh. 16 - Prob. 65ECh. 16 - Prob. 66ECh. 16 - Prob. 67ECh. 16 - Prob. 68ECh. 16 - Prob. 69ECh. 16 - Prob. 70ECh. 16 - Prob. 71ECh. 16 - Prob. 72E
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Biomolecules - Protein - Amino acids; Author: Tutorials Point (India) Ltd.;https://www.youtube.com/watch?v=ySNVPDHJ0ek;License: Standard YouTube License, CC-BY