Answer x = 1 Explanation Given: 2 x + 3 = 5 Concept Used: Steps to solve a linear equation: Use distributive property to eliminate any grouping symbol. Simplify the expression in each side of the equation. Collect the variables on one side of the equation and the constants on the other side. Isolate the variable To check the solution of an equation substitute the solution in the equation and check whether it satisfies. Calculation: In order to solve the equation: 2 x + 3 = 5 Isolate the variable by first subtracting 3 from both sides, as 2 x + 3 = 5 ⇒ 2 x + 3 − 3 = 5 − 3 ⇒ 2 x + 0 = 2 ⇒ 2 x = 2 Now, further simplify this by dividing both sides by 2. 2 x = 2 ⇒ 2 x 2 = 2 2 ⇒ x = 1 Thus, solution of given equation is x = 1 , and this satisfies that x ∈ { 0 , 1 , 2 , 3 , 4 , 5 , 6 } .

(REV)00 Edition

ISBN: 9780395977224

Author: Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Publisher: McDougal Littell

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Question

Chapter 1.6, Problem 1MRE

To determine

To solve the equation:

2x+3=5

Where, x∈{0,1,2,3,4,5,6} .

Expert Solution & Answer

Answer to Problem 1MRE

x=1

Explanation of Solution

Given:

2x+3=5

Concept Used:

Steps to solve a linear equation:

Use distributive property to eliminate any grouping symbol.
Simplify the expression in each side of the equation.
Collect the variables on one side of the equation and the constants on the other side.
Isolate the variable

To check the solution of an equation substitute the solution in the equation and check whether it satisfies.

Calculation:

In order to solve the equation:

2x+3=5

Isolate the variable by first subtracting 3 from both sides, as

2x+3=5⇒2x+3−3=5−3⇒2x+0=2⇒2x=2

Now, further simplify this by dividing both sides by 2.

2x=2⇒2x2=22⇒x=1

Thus, solution of given equation is x=1 , and this satisfies that

x∈{0,1,2,3,4,5,6} .

Chapter 1.6, Problem 22P

Chapter 1.6, Problem 2MRE

Chapter 1 Solutions

Algebra: Structure And Method, Book 1

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To solve the equation: 2 x + 3 = 5 Where, x ∈ { 0 , 1 , 2 , 3 , 4 , 5 , 6 } .