(REV)00 Edition

ISBN: 9780395977224

Author: Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Publisher: McDougal Littell

Concept explainers

The word “unitary” comes from the word “unit”, which means a single and complete entity. In this method, we find the value of a unit product from the given number of products, and then we solve for the other number of products.

Speed, Time, and Distance

Imagine you and 3 of your friends are planning to go to the playground at 6 in the evening. Your house is one mile away from the playground and one of your friends named Jim must start at 5 pm to reach the playground by walk. The other two friends are 3 …

Profit and Loss

The amount earned or lost on the sale of one or more items is referred to as the profit or loss on that item.

Units and Measurements

Measurements and comparisons are the foundation of science and engineering. We, therefore, need rules that tell us how things are measured and compared. For these measurements and comparisons, we perform certain experiments, and we will need the experime…

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Question

Chapter 1.4, Problem 54WE

To determine

To find: The expression for the number of grams of carbohydrates the mix of each are one cup of peanuts, walnuts and almonds contains.

Expert Solution & Answer

Answer to Problem 54WE

The mixer contains 3w+17grams.

Explanation of Solution

Given information: A cup of peanut contains 8 more grams of carbohydrates than a cup of walnuts and a cup of peanut contains 1less gram than a cup of almonds. Then mix one cup of each peanuts, walnuts and almonds. A cup of walnuts contains ‘ w’ gams of carbohydrates.

Calculation:

It is given that a cup of walnuts contains ‘ w’ grams of carbohydrates.

Now, it says a cup of peanut contains 8 more grams of carbohydrates than a cup of walnuts.

So, the expression for grams of carbohydrates in walnut is w+8

Now, a cup of almond has 1 more grams than peanuts.

The expression for grams of carbohydrate in almond is w+8+1 , which is simplified as w+9 .

Now, it is mixing all nuts each of 1 cup, so the expression is

w+8+w+w+9

Simplify it,

3w+17

Conclusion: The mixer contains 3w+17 grams.

Chapter 1.4, Problem 53WE

Chapter 1.4, Problem 1MRE

Chapter 1 Solutions

Algebra: Structure And Method, Book 1

Ch. 1.1 - Prob. 1OE Ch. 1.1 - Prob. 2OE Ch. 1.1 - Prob. 3OE Ch. 1.1 - Prob. 4OE Ch. 1.1 - Prob. 5OE Ch. 1.1 - Prob. 6OE Ch. 1.1 - Prob. 7OE Ch. 1.1 - Prob. 8OE Ch. 1.1 - Prob. 9OE Ch. 1.1 - Prob. 10OE

Ch. 1.1 - Prob. 11OE Ch. 1.1 - Prob. 12OE Ch. 1.1 - Prob. 13OE Ch. 1.1 - Prob. 14OE Ch. 1.1 - Prob. 15OE Ch. 1.1 - Prob. 16OE Ch. 1.1 - Prob. 17OE Ch. 1.1 - Prob. 18OE Ch. 1.1 - Prob. 19OE Ch. 1.1 - Prob. 20OE Ch. 1.1 - Prob. 21OE Ch. 1.1 - Prob. 22OE Ch. 1.1 - Prob. 23OE Ch. 1.1 - Prob. 24OE Ch. 1.1 - Prob. 25OE Ch. 1.1 - Prob. 26OE Ch. 1.1 - Prob. 1WE Ch. 1.1 - Prob. 2WE Ch. 1.1 - Prob. 3WE Ch. 1.1 - Prob. 4WE Ch. 1.1 - Prob. 5WE Ch. 1.1 - Prob. 6WE Ch. 1.1 - Prob. 7WE Ch. 1.1 - Prob. 8WE Ch. 1.1 - Prob. 9WE Ch. 1.1 - Prob. 10WE Ch. 1.1 - Prob. 11WE Ch. 1.1 - Prob. 12WE Ch. 1.1 - Prob. 13WE Ch. 1.1 - Prob. 14WE Ch. 1.1 - Prob. 15WE Ch. 1.1 - Prob. 16WE Ch. 1.1 - Prob. 17WE Ch. 1.1 - Prob. 18WE Ch. 1.1 - Prob. 19WE Ch. 1.1 - Prob. 20WE Ch. 1.1 - Prob. 21WE Ch. 1.1 - Prob. 22WE Ch. 1.1 - Prob. 23WE Ch. 1.1 - Prob. 24WE Ch. 1.1 - Prob. 25WE Ch. 1.1 - Prob. 26WE Ch. 1.1 - Prob. 27WE Ch. 1.1 - Prob. 28WE Ch. 1.1 - Prob. 29WE Ch. 1.1 - Prob. 30WE Ch. 1.1 - Prob. 31WE Ch. 1.1 - Prob. 32WE Ch. 1.1 - 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Prob. 5WE Ch. 1.5 - Prob. 6WE Ch. 1.5 - Prob. 7WE Ch. 1.5 - Prob. 8WE Ch. 1.5 - Prob. 9WE Ch. 1.5 - Prob. 10WE Ch. 1.5 - Prob. 11WE Ch. 1.5 - Prob. 12WE Ch. 1.5 - Prob. 13WE Ch. 1.5 - Prob. 14WE Ch. 1.5 - Prob. 15WE Ch. 1.5 - Prob. 16WE Ch. 1.5 - Prob. 17WE Ch. 1.5 - Prob. 18WE Ch. 1.5 - Prob. 19WE Ch. 1.5 - Prob. 20WE Ch. 1.5 - Prob. 21WE Ch. 1.5 - Prob. 22WE Ch. 1.5 - Prob. 23WE Ch. 1.5 - Prob. 24WE Ch. 1.5 - Prob. 25WE Ch. 1.5 - Prob. 26WE Ch. 1.5 - Prob. 27WE Ch. 1.5 - Prob. 28WE Ch. 1.5 - Prob. 29WE Ch. 1.5 - Prob. 30WE Ch. 1.5 - Prob. 31WE Ch. 1.5 - Prob. 32WE Ch. 1.5 - Prob. 33WE Ch. 1.5 - Prob. 34WE Ch. 1.5 - Prob. 35WE Ch. 1.5 - Prob. 36WE Ch. 1.5 - Prob. 1MRE Ch. 1.5 - Prob. 2MRE Ch. 1.5 - Prob. 3MRE Ch. 1.5 - Prob. 4MRE Ch. 1.5 - Prob. 5MRE Ch. 1.5 - Prob. 6MRE Ch. 1.5 - Prob. 7MRE Ch. 1.5 - Prob. 8MRE Ch. 1.5 - Prob. 9MRE Ch. 1.5 - Prob. 10MRE Ch. 1.5 - Prob. 11MRE Ch. 1.5 - Prob. 12MRE Ch. 1.6 - Prob. 1P Ch. 1.6 - Prob. 2P Ch. 1.6 - Prob. 3P Ch. 1.6 - Prob. 4P Ch. 1.6 - Prob. 5P Ch. 1.6 - Prob. 6P Ch. 1.6 - Prob. 7P Ch. 1.6 - Prob. 8P Ch. 1.6 - Prob. 9P Ch. 1.6 - Prob. 10P Ch. 1.6 - Prob. 11P Ch. 1.6 - Prob. 12P Ch. 1.6 - Prob. 13P Ch. 1.6 - Prob. 14P Ch. 1.6 - Prob. 15P Ch. 1.6 - Prob. 16P Ch. 1.6 - Prob. 17P Ch. 1.6 - Prob. 18P Ch. 1.6 - Prob. 19P Ch. 1.6 - Prob. 20P Ch. 1.6 - Prob. 21P Ch. 1.6 - Prob. 22P Ch. 1.6 - Prob. 1MRE Ch. 1.6 - Prob. 2MRE Ch. 1.6 - Prob. 3MRE Ch. 1.6 - Prob. 4MRE Ch. 1.6 - Prob. 5MRE Ch. 1.6 - Prob. 6MRE Ch. 1.6 - Prob. 7MRE Ch. 1.6 - Prob. 8MRE Ch. 1.6 - Prob. 9MRE Ch. 1.6 - Prob. 10MRE Ch. 1.6 - Prob. 11MRE Ch. 1.6 - Prob. 12MRE Ch. 1.6 - Prob. 1E Ch. 1.6 - Prob. 2E Ch. 1.6 - Prob. 3E Ch. 1.7 - Prob. 1P Ch. 1.7 - Prob. 2P Ch. 1.7 - Prob. 3P Ch. 1.7 - Prob. 4P Ch. 1.7 - Prob. 5P Ch. 1.7 - Prob. 6P Ch. 1.7 - Prob. 7P Ch. 1.7 - Prob. 8P Ch. 1.7 - Prob. 9P Ch. 1.7 - Prob. 10P Ch. 1.7 - Prob. 11P Ch. 1.7 - Prob. 12P Ch. 1.7 - Prob. 13P Ch. 1.7 - Prob. 14P Ch. 1.7 - Prob. 15P Ch. 1.7 - Prob. 16P Ch. 1.7 - Prob. 17P Ch. 1.7 - Prob. 18P Ch. 1.7 - Prob. 1MRE Ch. 1.7 - 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