Answer Required equation: 7 + x + x + 1 = 30 . The value of x is 11. . Explanation Given information: The length of sides of triangle is 7, x and x + 1 . And the perimeter of triangle = 30. Calculation: let sketch the triangle The perimeter of triangle = side1 +side2 +side3. Therefore, the perimeter of given triangle is 7 + x + x + 1 = 30 Now combine like terms 2 x + 8 = 30 Subtracting 8 both sides 2 x + 8 − 8 = 30 − 8 ⇒ 2 x = 22 Dividing by 2 on both sides 2 x 2 = 22 2 ⇒ x = 11 Therefore, the value of x = 11 .

(REV)00 Edition

ISBN: 9780395977224

Author: Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Publisher: McDougal Littell

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Question

Polygon with three sides, three angles, and three vertices. Based on the properties of each side, the types of triangles are scalene (triangle with three three different lengths and three different angles), isosceles (angle with two equal sides and two equal angles), and equilateral (three equal sides and three angles of 60°). The types of angles are acute (less than 90°); obtuse (greater than 90°); and right (90°).

Chapter 1.6, Problem 17P

To determine

To translate each problem into an equation. Draw a sketch for the given shape to get help from to get the value of x .

Expert Solution & Answer

Answer to Problem 17P

Required equation: 7+x+x+1=30 .

The value of x is 11. .

Explanation of Solution

Given information: The length of sides of triangle is 7, x and x+1 .

And the perimeter of triangle = 30.

Calculation: let sketch the triangle

Algebra: Structure And Method, Book 1, Chapter 1.6, Problem 17P

The perimeter of triangle = side1 +side2 +side3.

Therefore, the perimeter of given triangle is

7+x+x+1=30

Now combine like terms

2x+8=30

Subtracting 8 both sides

2x+8−8=30−8⇒2x=22

Dividing by 2 on both sides

2x2=222⇒x=11

Therefore, the value of x=11 .

Chapter 1.6, Problem 16P

Chapter 1.6, Problem 18P

Chapter 1 Solutions

Algebra: Structure And Method, Book 1

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