Organic Chemistry-Package(Custom)
Organic Chemistry-Package(Custom)
4th Edition
ISBN: 9781259141089
Author: SMITH
Publisher: MCG
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Chapter 16, Problem 16.6P
Interpretation Introduction

(a)

Interpretation: The second resonance structure for given species and its hybrid is to be drawn. The two resonance structure and the hybrid are to be ranked in order of increasing stability.

Concept introduction: Most of the organic structures cannot be represented using single Lewis structure. Therefore, there exists more than one Lewis structure for representing a molecule or ion. These structures are known as resonance structures. These are the hypothetical structures and do not specify the exact structure. These resonance structure combine together to give resonance hybrid that is lower in energy and is the most stable structure.

The delocalization of electrons results in the formation resonance structure.

Expert Solution
Check Mark

Answer to Problem 16.6P

The second resonance structure for given species and its hybrid are,

Organic Chemistry-Package(Custom), Chapter 16, Problem 16.6P , additional homework tip  1

The increasing order of stability for the given resonance structure is I<II<III.

Explanation of Solution

The given species is shown below.

Organic Chemistry-Package(Custom), Chapter 16, Problem 16.6P , additional homework tip  2

Figure 1

Delocalization of electrons from one position to the other position result in the formation of resonance structure. Resonance hybrid is the combination of all resonating structures. Thus, resonance structures and resonance hybrid for the given species is shown below.

Organic Chemistry-Package(Custom), Chapter 16, Problem 16.6P , additional homework tip  3

Figure 2

Better resonance structure is the one which has major contribution in the hybrid and others are minor contributors. Major contributor is the resonance structure which possesses more bonds and fewer charges.

The Figure 2 shows that the structure I does not contain double bond. Thus, the stability of structure I is less than the structure II.

Therefore, the increasing order of stability for the given resonance structure is I<II<III.

Conclusion

The second resonance structure for given species and its hybrid is shown in Figure 2. The increasing order of stability for the given resonance structure is is I<II<III.

Interpretation Introduction

(b)

Interpretation: The second resonance structure for given species and its hybrid is to be drawn. The two resonance structure and the hybrid are to be ranked in order of increasing stability.

Concept introduction: Most of the organic structures cannot be represented using single Lewis structure. Therefore, there exists more than one Lewis structure for representing a molecule or ion. These structures are known as resonance structures. These are the hypothetical structures and do not specify the exact structure. These resonance structure combine together to give resonance hybrid that is lower in energy and is the most stable structure.

The delocalization of electrons results in the formation resonance structure.

Expert Solution
Check Mark

Answer to Problem 16.6P

The second resonance structure for given species and its hybrid are,

Organic Chemistry-Package(Custom), Chapter 16, Problem 16.6P , additional homework tip  4

The increasing order of stability for the given resonance structure is I<II<III.

Explanation of Solution

The given species is shown below.

Organic Chemistry-Package(Custom), Chapter 16, Problem 16.6P , additional homework tip  5

Figure 3

Delocalization of electrons from one position to the other position result in the formation of resonance structure. Resonance hybrid is the combination of all resonating structures. Thus, resonance structures and resonance hybrid for the given species is shown below.

Organic Chemistry-Package(Custom), Chapter 16, Problem 16.6P , additional homework tip  6

Figure 4

Better resonance structure is the one which has major contribution in the hybrid and others are minor contributors. Major contributor is the resonance structure in which negative charge is on more electronegative atom. The electronegativity of oxygen is more than nitrogen.

The Figure 4 shows that structure I, negative charge is on nitrogen atom, whereas in structure II, negative charge is on oxygen atom. Thus, the stability of structure I is less than the structure II.

Therefore, the increasing order of stability for the given resonance structure is I<II<III.

Conclusion

The second resonance structure for given species and its hybrid is shown in Figure 4. The increasing order of stability for the given resonance structure is is I<II<III.

Interpretation Introduction

(c)

Interpretation: The second resonance structure for given species and its hybrid is to be drawn. The two resonance structure and the hybrid are to be ranked in order of increasing stability.

Concept introduction: Most of the organic structures cannot be represented using single Lewis structure. Therefore, there exists more than one Lewis structure for representing a molecule or ion. These structures are known as resonance structures. These are the hypothetical structures and do not specify the exact structure. These resonance structure combine together to give resonance hybrid that is lower in energy and is the most stable structure.

The delocalization of electrons results in the formation resonance structure.

Expert Solution
Check Mark

Answer to Problem 16.6P

The second resonance structure for given carbocation and its hybrid are,

Organic Chemistry-Package(Custom), Chapter 16, Problem 16.6P , additional homework tip  7

The increasing order of stability for the given resonance structure is,

Organic Chemistry-Package(Custom), Chapter 16, Problem 16.6P , additional homework tip  8

Explanation of Solution

The given species is shown below.

Organic Chemistry-Package(Custom), Chapter 16, Problem 16.6P , additional homework tip  9

Figure 5

Delocalization of electrons from one position to the other position result in the formation of resonance structure. The resonance structure for the given species is shown below.

Organic Chemistry-Package(Custom), Chapter 16, Problem 16.6P , additional homework tip  10

Figure 6

Resonance hybrid is the combination of all resonating structures. Thus, resonance hybrid for the given species is shown below.

Organic Chemistry-Package(Custom), Chapter 16, Problem 16.6P , additional homework tip  11

Figure 7

Better resonance structure is the one which has major contribution in the hybrid and others are minor contributors. Major contributor is the resonance structure which possesses more bonds and fewer charges.

Therefore, the increasing order of stability for the given resonance structure is shown below.

Organic Chemistry-Package(Custom), Chapter 16, Problem 16.6P , additional homework tip  12

Figure 8

Conclusion

The second resonance structure for given carbocation and its hybrid is shown in Figure 6 and 7. The increasing order of stability for the given resonance structure is shown in Figure 8.

Interpretation Introduction

(d)

Interpretation: The second resonance structure for given species and its hybrid is to be drawn. The two resonance structure and the hybrid are to be ranked in order of increasing stability.

Concept introduction: Most of the organic structures cannot be represented using single Lewis structure. Therefore, there exists more than one Lewis structure for representing a molecule or ion. These structures are known as resonance structures. These are the hypothetical structures and do not specify the exact structure. These resonance structure combine together to give resonance hybrid that is lower in energy and is the most stable structure.

The delocalization of electrons results in the formation resonance structure.

Expert Solution
Check Mark

Answer to Problem 16.6P

The second resonance structure for given carbocation and its hybrid are,

Organic Chemistry-Package(Custom), Chapter 16, Problem 16.6P , additional homework tip  13

The increasing order of stability for the given resonance structure is,

Organic Chemistry-Package(Custom), Chapter 16, Problem 16.6P , additional homework tip  14

Explanation of Solution

The given species is shown below.

Organic Chemistry-Package(Custom), Chapter 16, Problem 16.6P , additional homework tip  15

Figure 9

Delocalization of electrons from one position to the other position result in the formation of resonance structure. The resonance structure for the given species is shown below.

Organic Chemistry-Package(Custom), Chapter 16, Problem 16.6P , additional homework tip  16

Figure 10

Resonance hybrid is the combination of all resonating structures. Thus, resonance hybrid for the given species is shown below.

Organic Chemistry-Package(Custom), Chapter 16, Problem 16.6P , additional homework tip  17

Figure 11

Better resonance structure is the one which has major contribution in the hybrid and others are minor contributors. Major contributor is the resonance structure which possesses more bonds and fewer charges.

The given Figure 2 shows that the left side structure does not contain double bond. Thus, the stability of left side structure is less than the right side structure.

Therefore, the increasing order of stability for the given resonance structure is shown below.

Organic Chemistry-Package(Custom), Chapter 16, Problem 16.6P , additional homework tip  18

Figure 12

Conclusion

The second resonance structure for given carbocation and its hybrid is shown in Figure 10 and 11. The increasing order of stability for the given resonance structure is shown in Figure 12.

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d. b. e o C. a. O 6. Draw at least 3 additional (l.e., in addition to the structure provided) valid resonance (major contributors only) forms of the following ions: Ⓒ
Draw a second resonance structure for each ion. Then, draw the resonance hybrid.
Draw all reasonable resonance structures for each species.

Chapter 16 Solutions

Organic Chemistry-Package(Custom)

Ch. 16 - Problem 16.12 Using hybridization, predict how the...Ch. 16 - Problem 16.13 Use resonance theory to explain why...Ch. 16 - Prob. 16.13PCh. 16 - Prob. 16.14PCh. 16 - Prob. 16.15PCh. 16 - Problem 16.17 Draw a stepwise mechanism for the...Ch. 16 - Prob. 16.17PCh. 16 - Problem 16.19 Draw the product formed when each...Ch. 16 - Prob. 16.19PCh. 16 - Prob. 16.20PCh. 16 - Rank the following dienophiles in order of...Ch. 16 - Prob. 16.22PCh. 16 - Prob. 16.23PCh. 16 - Prob. 16.24PCh. 16 - Prob. 16.25PCh. 16 - Problem 16.27 Which compound in each pair absorbs...Ch. 16 - Prob. 16.27PCh. 16 - 16.29 Name each diene and state whether the...Ch. 16 - Prob. 16.29PCh. 16 - Prob. 16.30PCh. 16 - Prob. 16.31PCh. 16 - Prob. 16.32PCh. 16 - Prob. 16.33PCh. 16 - Prob. 16.34PCh. 16 - 16.35 Explain why the cyclopentadienide anion A...Ch. 16 - Explain each statement using resonance theory. a....Ch. 16 - 16.37 Draw the structure of each compound. a. in...Ch. 16 - Draw and name all dienes of molecular formula...Ch. 16 - Prob. 16.39PCh. 16 - 16.39 Label each pair of compounds as...Ch. 16 - Prob. 16.41PCh. 16 - 16.41 Draw the products formed when each compound...Ch. 16 - Prob. 16.43PCh. 16 - 16.43 Treatment of alkenes A and B with gives the...Ch. 16 - 16.44 Draw a stepwise mechanism for the following...Ch. 16 - Prob. 16.46PCh. 16 - 16.46 Explain, with reference to the mechanism,...Ch. 16 - Prob. 16.48PCh. 16 - Prob. 16.49PCh. 16 - Prob. 16.50PCh. 16 - Prob. 16.51PCh. 16 - Prob. 16.52PCh. 16 - Prob. 16.53PCh. 16 - 16.53 Diels–Alder reaction of a monosubstituted...Ch. 16 - Prob. 16.55PCh. 16 - Prob. 16.56PCh. 16 - 16.55 Devise a stepwise synthesis of each compound...Ch. 16 - Prob. 16.58PCh. 16 - 16.57 A transannular Diels–Alder reaction is an...Ch. 16 - Draw a stepwise mechanism for the following...Ch. 16 - Draw the products of each reaction. Indicate the...Ch. 16 - Prob. 16.62PCh. 16 - Prob. 16.63PCh. 16 - Prob. 16.64PCh. 16 - 16.65 The treatment of isoprene with one...Ch. 16 - 16.66 The treatment of with forms B (molecular...Ch. 16 - Rank the following compounds in the order of...Ch. 16 - Prob. 16.68PCh. 16 - Prob. 16.69PCh. 16 - Prob. 16.70PCh. 16 - Prob. 16.71PCh. 16 - Prob. 16.72PCh. 16 - Prob. 16.73PCh. 16 - Prob. 16.74P
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