(a) Interpretation: A balanced equation and equilibrium equation for given reaction needs to be determined. Concept introduction: The “law of conservation of mass” and “the law of conservation of atoms” are reflected by a chemical equation. They are balanced in nature. For this, the mass of reactants and products must be equal. Steps to Balance the chemical equation: Identify reactants and products. Write the chemical formula. Count the number of atoms on the reactant side and product side. If the number of atoms is not the same then try to balance by changing the coefficient of molecules on either one side or both sides of the equation.
(a) Interpretation: A balanced equation and equilibrium equation for given reaction needs to be determined. Concept introduction: The “law of conservation of mass” and “the law of conservation of atoms” are reflected by a chemical equation. They are balanced in nature. For this, the mass of reactants and products must be equal. Steps to Balance the chemical equation: Identify reactants and products. Write the chemical formula. Count the number of atoms on the reactant side and product side. If the number of atoms is not the same then try to balance by changing the coefficient of molecules on either one side or both sides of the equation.
Solution Summary: The author explains that a balanced equation and equilibrium equation for given reaction needs to be determined.
Definition Definition Transformation of a chemical species into another chemical species. A chemical reaction consists of breaking existing bonds and forming new ones by changing the position of electrons. These reactions are best explained using a chemical equation.
Chapter 16, Problem 16.44CP
Interpretation Introduction
(a)
Interpretation:
A balanced equation and equilibrium equation for given reaction needs to be determined.
Concept introduction:
The “law of conservation of mass” and “the law of conservation of atoms” are reflected by a chemical equation. They are balanced in nature. For this, the mass of reactants and products must be equal.
Steps to Balance the chemical equation:
Identify reactants and products.
Write the chemical formula.
Count the number of atoms on the reactant side and product side.
If the number of atoms is not the same then try to balance by changing the coefficient of molecules on either one side or both sides of the equation.
Interpretation Introduction
(b)
Interpretation:
The changes in equilibrium constant value by increasing the value of n needs to be explained.
Concept introduction:
At the equilibrium condition, the number used to express the relationship between reactants and products at the given temperature in a reversible chemical heat reaction is known as equilibrium constant.
For a reversible chemical reaction:
aA + bB →cC + dD
The equilibrium constant K is given by the following expression:
K = [C]c·[D]d/[A]a·[B]b
Where,
Equilibrium concentration of A : [A]
Equilibrium concentration of B : [B]
Equilibrium concentration of C : [C]
Equilibrium concentration of D : [D]
Interpretation Introduction
(c)
Interpretation:
The name of the strongest acid and conjugate base needs to be determined.
Concept introduction:
An acid with a maximum number of hydronium ion has maximum acidity and acid with a minimum number of hydronium ion has minimum acidity. A strong acid has a weak conjugate base and a strong base has a weak conjugate acid.
What is the conjugate base of boric acid, B(OH)3?
(A) OH–
(B) B(OH)4–
(C) B(O)(OH)22–
(D) B(H2O)(OH)2+
What is the equilibrium constant expression (Ka) for the acid dissociation of hypochlorous acid? HClO(aq)+H 2 O(l) H 3 O^ + (aq)+ClO-(aq) .
a) Ka=[H 3 O^ + ]+[ClO-]-[HClO]; b) Ka=([HClOl[H 2 O]/([H 3 O^ + ][ClO-]);
c) Ka=([H 3 O^ + ][ClO-])/([HClO][H 2 O]; d) Ka=(IH 3 O^ + ][ClO-])/[HClO]
Hypochlorous acid, HOCl, is a weak acid having a pKa = 7.46. (a) Show the balanced chemical equation for the hydrolysis of water by OCl- (aq). (b) Compute the value of pKb for aqueous hypochlorite ion. (c) If [OCl-] = 0.050 M, then what is the pH of this aqueous solution?
(a)
(b)
(c)
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