The concentration of the given bases with a pH of 11.04 at 25 ∘ C has to be calculated Concept Introduction: In strong acids, the ionization of acid is complete. This implies that the concentration of the hydrogen ion or hydronium ion will be equal to the initial concentration of the acid at equilibrium. Strong bases: Strong bases are formed from alkali metals and alkaline earth metals of Group IA and IIA respectively. Strong base dissociates into its constituent ions. pOH : The pOH of a solution is defined as the negative base-10 logarithm of the hydroxide ion [OH - ] concentration. pOH scale is analogous to pH scale. pOH = -log[OH - ] Relationship between pH and pOH : pOH is similar to pH . The only difference is that in pOH the concentration of hydroxide ion is used as a scale while in pH , the concentration of hydronium ion is used. The relationship between the hydronium ion concentration and the hydroxide ion concentration is given by the equation, pH + pOH = 14, at 25 o C As pOH and pH are opposite scale, the total of both has to be equal to 14.
The concentration of the given bases with a pH of 11.04 at 25 ∘ C has to be calculated Concept Introduction: In strong acids, the ionization of acid is complete. This implies that the concentration of the hydrogen ion or hydronium ion will be equal to the initial concentration of the acid at equilibrium. Strong bases: Strong bases are formed from alkali metals and alkaline earth metals of Group IA and IIA respectively. Strong base dissociates into its constituent ions. pOH : The pOH of a solution is defined as the negative base-10 logarithm of the hydroxide ion [OH - ] concentration. pOH scale is analogous to pH scale. pOH = -log[OH - ] Relationship between pH and pOH : pOH is similar to pH . The only difference is that in pOH the concentration of hydroxide ion is used as a scale while in pH , the concentration of hydronium ion is used. The relationship between the hydronium ion concentration and the hydroxide ion concentration is given by the equation, pH + pOH = 14, at 25 o C As pOH and pH are opposite scale, the total of both has to be equal to 14.
The concentration of the given bases with a pH of 11.04 at 25∘C has to be calculated
Concept Introduction:
In strong acids, the ionization of acid is complete. This implies that the concentration of the hydrogen ion or hydronium ion will be equal to the initial concentration of the acid at equilibrium.
Strong bases: Strong bases are formed from alkali metals and alkaline earth metals of Group IA and IIA respectively.
Strong base dissociates into its constituent ions.
pOH: The pOH of a solution is defined as the negative base-10 logarithm of the hydroxide ion [OH-] concentration. pOH scale is analogous to pH scale.
pOH=-log[OH-]
Relationship between pH and pOH:
pOH is similar to pH. The only difference is that in pOH the concentration of hydroxide ion is used as a scale while in pH, the concentration of hydronium ion is used.
The relationship between the hydronium ion concentration and the hydroxide ion concentration is given by the equation,
pH+pOH=14,at25oC
As pOH and pH are opposite scale, the total of both has to be equal to 14.
(b)
Interpretation Introduction
Interpretation:
The concentration of the given bases with a pH of 11.04 at 25∘C has to be calculated
Concept Introduction:
In strong acids, the ionization of acid is complete. This implies that the concentration of the hydrogen ion or hydronium ion will be equal to the initial concentration of the acid at equilibrium.
Strong bases: Strong bases are formed from alkali metals and alkaline earth metals of Group IA and IIA respectively.
Strong base dissociates into its constituent ions.
pOH: The pOH of a solution is defined as the negative base-10 logarithm of the hydroxide ion [OH-] concentration. pOH scale is analogous to pH scale.
pOH=-log[OH-]
Relationship between pH and pOH:
pOH is similar to pH. The only difference is that in pOH the concentration of hydroxide ion is used as a scale while in pH, the concentration of hydronium ion is used.
The relationship between the hydronium ion concentration and the hydroxide ion concentration is given by the equation,
pH+pOH=14,at25oC
As pOH and pH are opposite scale, the total of both has to be equal to 14.
Part 1. Draw monomer units of the following products and draw their reaction mechanism
1) Bakelite like polymer
Using: Resorcinol + NaOH + Formalin
2) Polyester fiber
Using a) pthalic anhydride + anhydrous sodium acetate + ethylene glycol
B)pthalic anhydride + anhydrous sodium acetate + glycerol
3) Temporary cross-linked polymer
Using: 4% polyvinyl alcohol+ methyl red + 4% sodium borate
Using the table of Reactants and Products provided provide the correct letter that
corresponds with the Carboxylic acid that is formed in the reaction below.
6 M NaOH
Acid-workup
WRITE THE CORRECT LETTER ONLY DO NOT WRITE EXTRA WORDS OR
PHRASES
A)
Pool of Reagents for Part B
CI
B)
OH
C)
E)
CI
J)
racemic
F)
K)
OH
N)
OH
P)
G)
OH
D)
HO
H)
L)
M)
HO
Q)
R)
CI
A
In the table below, the exact chemical structures for Methyl salicylate can be
represented by the letter
WRITE THE CORRECT LETTER ONLY DO NOT WRITE EXTRA WORDS OR
PHRASES
CI
B)
A)
E)
Cl
racemic
F)
J)
CI
K)
N)
OH
P)
Pool of Reagents for Part B
OH
OH
G)
L)
OH
D)
HO
H)
M)
HO
Q)
R)
CI