Draw the structure of each compound. a. ( Z ) − penta − 1 , 3 − diene in the s − trans conformation. b. ( 2 E , 4 Z ) − 1 − bromo − 3 − methylhexa − 2 , 4 − diene c. ( 2 E , 4 E , 6 Z ) − octa − 2 , 4 , 6 − triene d. ( 2 E , 4 E ) − 3 − methylhexa − 2 , 4 − diene in the s − cis conformation.

Question

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Answer 1

Textbook Question

Chapter 16, Problem 16.37P

Draw the structure of each compound.

a. ( Z ) − penta − 1 , 3 − diene in the s − trans conformation.

b. ( 2 E , 4 Z ) − 1 − bromo − 3 − methylhexa − 2 , 4 − diene

c. ( 2 E , 4 E , 6 Z ) − octa − 2 , 4 , 6 − triene

d. ( 2 E , 4 E ) − 3 − methylhexa − 2 , 4 − diene in the s − cis conformation.

Expert Solution

Interpretation Introduction

(a)

Interpretation: The structure corresponding to (Z)−penta−1,3−diene in the s−trans conformation is to be drawn.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing structural formula from IUPAC are:

1. First identify the word root for the given compound.

2. The suffix used in the compound like –ene.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

The prefix E and Z depends upon the location of the higher priority groups. When two higher priority groups are present on the opposite side then it is an E isomer, whereas when two higher priority groups are present on the same side then it is Z isomer.

Answer to Problem 16.37P

The structure corresponding to (Z)−penta−1,3−diene in the s−trans conformation is,

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 1

Explanation of Solution

The given name is (Z)−penta−1,3−diene. The word root used in this is pent. It means structure contains five carbon atoms. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. The prefix used is Z. It means that two higher priority groups are present on the same side. The given compound has trans conformation. Thus, the correct structure of (Z)−penta−1,3−diene is shown below.

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 2

Figure 1

Conclusion

The structure corresponding to (Z)−penta−1,3−diene in the s−trans conformation is shown in Figure 1.

Expert Solution

Interpretation Introduction

(b)

Interpretation: The structure corresponding to (2E,4Z)−1−bromo−3−methylhexa−2,4−diene is to be drawn.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing structural formula from IUPAC are:

1. First identify the word root for the given compound.

2. The suffix used in the compound like –ene.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

The prefix E and Z depends upon the location of the higher priority groups. When two higher priority groups are present on the opposite side then it is an E or trans isomer, whereas when two higher priority groups are present on the same side then it is Z or cis isomer.

Answer to Problem 16.37P

The structure corresponding to (2E,4Z)−1−bromo−3−methylhexa−2,4−diene is,

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 3

Explanation of Solution

The given name is (2E,4Z)−1−bromo−3−methylhexa−2,4−diene. The word root used in this is hex. It means structure contains six carbon atoms. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. The prefix used are E and Z. Thus, it means that the stereochemistry at one double bond is trans and at other is cis.

Thus, the correct structure of (2E,4Z)−1−bromo−3−methylhexa−2,4−diene is shown below.

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 4

Figure 2

Conclusion

The structure corresponding to (2E,4Z)−1−bromo−3−methylhexa−2,4−diene is shown in Figure 2.

Expert Solution

Interpretation Introduction

(c)

Interpretation: The structure corresponding to (2E,4E,6Z)−octa−2,4,6−triene is to be drawn.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing structural formula from IUPAC are:

1. First identify the word root for the given compound.

2. The suffix used in the compound like –ene.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

The prefix E and Z depends upon the location of the higher priority groups. When two higher priority groups are present on the opposite side then it is an E isomer, whereas when two higher priority groups are present on the same side then it is Z isomer.

Answer to Problem 16.37P

The structure corresponding to (2E,4E,6Z)−octa−2,4,6−triene is,

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 5

Explanation of Solution

The given name is (2E,4E,6Z)−octa−2,4,6−triene. The word root used in this is dec. It means structure contains ten carbon atoms. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. The prefix used is Z. It means that two higher priority groups are present on the same side. Thus, the correct structure to (2E,4E,6Z)−octa−2,4,6−triene is shown below.

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 6

Figure 3

Conclusion

The structure corresponding to (2E,4E,6Z)−octa−2,4,6−triene is shown in Figure 3.

Expert Solution

Interpretation Introduction

(d)

Interpretation: The structure corresponding to (2E,4E)−3−methylhexa−2,4−diene s−cis is to be drawn.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing structural formula from IUPAC are:

4. First identify the word root for the given compound.

5. The suffix used in the compound like –ene.

6. Identify the position, location, and number of the substituent bonded to the carbon chain.

The prefix E and Z depends upon the location of the higher priority groups. When two higher priority groups are present on the opposite side then it is an E isomer, whereas when two higher priority groups are present on the same side then it is Z isomer.

Answer to Problem 16.37P

The structure corresponding to (2E,4E)−3−methylhexa−2,4−diene in s−cis is,

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 7

Explanation of Solution

The given name is (2E,4E)−3−methylhexa−2,4−diene. The word root used in this is hex. It means structure contains six carbon atoms. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One methyl substituent is attached to the third carbon atom. The prefix used is E. It means that two higher priority groups are present on the opposite side. Thus, the correct structure to (2E,4E)−3−methylhexa−2,4−diene is shown below.

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 8

Figure 4

Conclusion

The structure corresponding to (2E,4E)−3−methylhexa−2,4−diene in s−cis is shown in Figure 4.

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Students have asked these similar questions

Draw the structure of each compound.a. (Z)-penta-1,3-diene in the s-trans conformationb. (2E,4Z)-1-bromo-3-methylhexa-2,4-dienec. (2E,4E,6E)-octa-2,4,6-triened. (2E,4E)-3-methylhexa-2,4-diene in the s-cis conformation

Rank the following groups in order of decreasing priority. a.−COOH, −H, −NH2, −OH b.−H, −CH3, −Cl, −CH2Cl c. −CH2CH3, −CH3, −H, −CH(CH3)2 d.−CH=CH2, −CH3, −C≡CH, −H

Order the following in increasing priority A. -C, -CH, -OL B. -CH3, -CH2OH, -CH2CH3 C. -C≡CH, -CH゠CH2, -CH゠O

Answer 2

Textbook Question

Chapter 16, Problem 16.37P

Draw the structure of each compound.

a. ( Z ) − penta − 1 , 3 − diene in the s − trans conformation.

b. ( 2 E , 4 Z ) − 1 − bromo − 3 − methylhexa − 2 , 4 − diene

c. ( 2 E , 4 E , 6 Z ) − octa − 2 , 4 , 6 − triene

d. ( 2 E , 4 E ) − 3 − methylhexa − 2 , 4 − diene in the s − cis conformation.

Expert Solution

Interpretation Introduction

(a)

Interpretation: The structure corresponding to (Z)−penta−1,3−diene in the s−trans conformation is to be drawn.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing structural formula from IUPAC are:

1. First identify the word root for the given compound.

2. The suffix used in the compound like –ene.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

The prefix E and Z depends upon the location of the higher priority groups. When two higher priority groups are present on the opposite side then it is an E isomer, whereas when two higher priority groups are present on the same side then it is Z isomer.

Answer to Problem 16.37P

The structure corresponding to (Z)−penta−1,3−diene in the s−trans conformation is,

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 1

Explanation of Solution

The given name is (Z)−penta−1,3−diene. The word root used in this is pent. It means structure contains five carbon atoms. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. The prefix used is Z. It means that two higher priority groups are present on the same side. The given compound has trans conformation. Thus, the correct structure of (Z)−penta−1,3−diene is shown below.

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 2

Figure 1

Conclusion

The structure corresponding to (Z)−penta−1,3−diene in the s−trans conformation is shown in Figure 1.

Expert Solution

Interpretation Introduction

(b)

Interpretation: The structure corresponding to (2E,4Z)−1−bromo−3−methylhexa−2,4−diene is to be drawn.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing structural formula from IUPAC are:

1. First identify the word root for the given compound.

2. The suffix used in the compound like –ene.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

The prefix E and Z depends upon the location of the higher priority groups. When two higher priority groups are present on the opposite side then it is an E or trans isomer, whereas when two higher priority groups are present on the same side then it is Z or cis isomer.

Answer to Problem 16.37P

The structure corresponding to (2E,4Z)−1−bromo−3−methylhexa−2,4−diene is,

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 3

Explanation of Solution

The given name is (2E,4Z)−1−bromo−3−methylhexa−2,4−diene. The word root used in this is hex. It means structure contains six carbon atoms. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. The prefix used are E and Z. Thus, it means that the stereochemistry at one double bond is trans and at other is cis.

Thus, the correct structure of (2E,4Z)−1−bromo−3−methylhexa−2,4−diene is shown below.

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 4

Figure 2

Conclusion

The structure corresponding to (2E,4Z)−1−bromo−3−methylhexa−2,4−diene is shown in Figure 2.

Expert Solution

Interpretation Introduction

(c)

Interpretation: The structure corresponding to (2E,4E,6Z)−octa−2,4,6−triene is to be drawn.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing structural formula from IUPAC are:

1. First identify the word root for the given compound.

2. The suffix used in the compound like –ene.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

The prefix E and Z depends upon the location of the higher priority groups. When two higher priority groups are present on the opposite side then it is an E isomer, whereas when two higher priority groups are present on the same side then it is Z isomer.

Answer to Problem 16.37P

The structure corresponding to (2E,4E,6Z)−octa−2,4,6−triene is,

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 5

Explanation of Solution

The given name is (2E,4E,6Z)−octa−2,4,6−triene. The word root used in this is dec. It means structure contains ten carbon atoms. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. The prefix used is Z. It means that two higher priority groups are present on the same side. Thus, the correct structure to (2E,4E,6Z)−octa−2,4,6−triene is shown below.

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 6

Figure 3

Conclusion

The structure corresponding to (2E,4E,6Z)−octa−2,4,6−triene is shown in Figure 3.

Expert Solution

Interpretation Introduction

(d)

Interpretation: The structure corresponding to (2E,4E)−3−methylhexa−2,4−diene s−cis is to be drawn.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing structural formula from IUPAC are:

4. First identify the word root for the given compound.

5. The suffix used in the compound like –ene.

6. Identify the position, location, and number of the substituent bonded to the carbon chain.

The prefix E and Z depends upon the location of the higher priority groups. When two higher priority groups are present on the opposite side then it is an E isomer, whereas when two higher priority groups are present on the same side then it is Z isomer.

Answer to Problem 16.37P

The structure corresponding to (2E,4E)−3−methylhexa−2,4−diene in s−cis is,

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 7

Explanation of Solution

The given name is (2E,4E)−3−methylhexa−2,4−diene. The word root used in this is hex. It means structure contains six carbon atoms. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One methyl substituent is attached to the third carbon atom. The prefix used is E. It means that two higher priority groups are present on the opposite side. Thus, the correct structure to (2E,4E)−3−methylhexa−2,4−diene is shown below.

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 8

Figure 4

Conclusion

The structure corresponding to (2E,4E)−3−methylhexa−2,4−diene in s−cis is shown in Figure 4.

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Answer 3

Textbook Question

Chapter 16, Problem 16.37P

Draw the structure of each compound.

a. ( Z ) − penta − 1 , 3 − diene in the s − trans conformation.

b. ( 2 E , 4 Z ) − 1 − bromo − 3 − methylhexa − 2 , 4 − diene

c. ( 2 E , 4 E , 6 Z ) − octa − 2 , 4 , 6 − triene

d. ( 2 E , 4 E ) − 3 − methylhexa − 2 , 4 − diene in the s − cis conformation.

Expert Solution

Interpretation Introduction

(a)

Interpretation: The structure corresponding to (Z)−penta−1,3−diene in the s−trans conformation is to be drawn.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing structural formula from IUPAC are:

1. First identify the word root for the given compound.

2. The suffix used in the compound like –ene.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

The prefix E and Z depends upon the location of the higher priority groups. When two higher priority groups are present on the opposite side then it is an E isomer, whereas when two higher priority groups are present on the same side then it is Z isomer.

Answer to Problem 16.37P

The structure corresponding to (Z)−penta−1,3−diene in the s−trans conformation is,

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 1

Explanation of Solution

The given name is (Z)−penta−1,3−diene. The word root used in this is pent. It means structure contains five carbon atoms. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. The prefix used is Z. It means that two higher priority groups are present on the same side. The given compound has trans conformation. Thus, the correct structure of (Z)−penta−1,3−diene is shown below.

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 2

Figure 1

Conclusion

The structure corresponding to (Z)−penta−1,3−diene in the s−trans conformation is shown in Figure 1.

Expert Solution

Interpretation Introduction

(b)

Interpretation: The structure corresponding to (2E,4Z)−1−bromo−3−methylhexa−2,4−diene is to be drawn.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing structural formula from IUPAC are:

1. First identify the word root for the given compound.

2. The suffix used in the compound like –ene.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

The prefix E and Z depends upon the location of the higher priority groups. When two higher priority groups are present on the opposite side then it is an E or trans isomer, whereas when two higher priority groups are present on the same side then it is Z or cis isomer.

Answer to Problem 16.37P

The structure corresponding to (2E,4Z)−1−bromo−3−methylhexa−2,4−diene is,

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 3

Explanation of Solution

The given name is (2E,4Z)−1−bromo−3−methylhexa−2,4−diene. The word root used in this is hex. It means structure contains six carbon atoms. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. The prefix used are E and Z. Thus, it means that the stereochemistry at one double bond is trans and at other is cis.

Thus, the correct structure of (2E,4Z)−1−bromo−3−methylhexa−2,4−diene is shown below.

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 4

Figure 2

Conclusion

The structure corresponding to (2E,4Z)−1−bromo−3−methylhexa−2,4−diene is shown in Figure 2.

Expert Solution

Interpretation Introduction

(c)

Interpretation: The structure corresponding to (2E,4E,6Z)−octa−2,4,6−triene is to be drawn.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing structural formula from IUPAC are:

1. First identify the word root for the given compound.

2. The suffix used in the compound like –ene.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

The prefix E and Z depends upon the location of the higher priority groups. When two higher priority groups are present on the opposite side then it is an E isomer, whereas when two higher priority groups are present on the same side then it is Z isomer.

Answer to Problem 16.37P

The structure corresponding to (2E,4E,6Z)−octa−2,4,6−triene is,

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 5

Explanation of Solution

The given name is (2E,4E,6Z)−octa−2,4,6−triene. The word root used in this is dec. It means structure contains ten carbon atoms. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. The prefix used is Z. It means that two higher priority groups are present on the same side. Thus, the correct structure to (2E,4E,6Z)−octa−2,4,6−triene is shown below.

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 6

Figure 3

Conclusion

The structure corresponding to (2E,4E,6Z)−octa−2,4,6−triene is shown in Figure 3.

Expert Solution

Interpretation Introduction

(d)

Interpretation: The structure corresponding to (2E,4E)−3−methylhexa−2,4−diene s−cis is to be drawn.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing structural formula from IUPAC are:

4. First identify the word root for the given compound.

5. The suffix used in the compound like –ene.

6. Identify the position, location, and number of the substituent bonded to the carbon chain.

The prefix E and Z depends upon the location of the higher priority groups. When two higher priority groups are present on the opposite side then it is an E isomer, whereas when two higher priority groups are present on the same side then it is Z isomer.

Answer to Problem 16.37P

The structure corresponding to (2E,4E)−3−methylhexa−2,4−diene in s−cis is,

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 7

Explanation of Solution

The given name is (2E,4E)−3−methylhexa−2,4−diene. The word root used in this is hex. It means structure contains six carbon atoms. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One methyl substituent is attached to the third carbon atom. The prefix used is E. It means that two higher priority groups are present on the opposite side. Thus, the correct structure to (2E,4E)−3−methylhexa−2,4−diene is shown below.

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 8

Figure 4

Conclusion

The structure corresponding to (2E,4E)−3−methylhexa−2,4−diene in s−cis is shown in Figure 4.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Textbook Question

Chapter 16, Problem 16.37P

Draw the structure of each compound.

a. ( Z ) − penta − 1 , 3 − diene in the s − trans conformation.

b. ( 2 E , 4 Z ) − 1 − bromo − 3 − methylhexa − 2 , 4 − diene

c. ( 2 E , 4 E , 6 Z ) − octa − 2 , 4 , 6 − triene

d. ( 2 E , 4 E ) − 3 − methylhexa − 2 , 4 − diene in the s − cis conformation.

Expert Solution

Interpretation Introduction

(a)

Interpretation: The structure corresponding to (Z)−penta−1,3−diene in the s−trans conformation is to be drawn.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing structural formula from IUPAC are:

1. First identify the word root for the given compound.

2. The suffix used in the compound like –ene.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

The prefix E and Z depends upon the location of the higher priority groups. When two higher priority groups are present on the opposite side then it is an E isomer, whereas when two higher priority groups are present on the same side then it is Z isomer.

Answer to Problem 16.37P

The structure corresponding to (Z)−penta−1,3−diene in the s−trans conformation is,

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 1

Explanation of Solution

The given name is (Z)−penta−1,3−diene. The word root used in this is pent. It means structure contains five carbon atoms. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. The prefix used is Z. It means that two higher priority groups are present on the same side. The given compound has trans conformation. Thus, the correct structure of (Z)−penta−1,3−diene is shown below.

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 2

Figure 1

Conclusion

The structure corresponding to (Z)−penta−1,3−diene in the s−trans conformation is shown in Figure 1.

Expert Solution

Interpretation Introduction

(b)

Interpretation: The structure corresponding to (2E,4Z)−1−bromo−3−methylhexa−2,4−diene is to be drawn.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing structural formula from IUPAC are:

1. First identify the word root for the given compound.

2. The suffix used in the compound like –ene.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

The prefix E and Z depends upon the location of the higher priority groups. When two higher priority groups are present on the opposite side then it is an E or trans isomer, whereas when two higher priority groups are present on the same side then it is Z or cis isomer.

Answer to Problem 16.37P

The structure corresponding to (2E,4Z)−1−bromo−3−methylhexa−2,4−diene is,

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 3

Explanation of Solution

The given name is (2E,4Z)−1−bromo−3−methylhexa−2,4−diene. The word root used in this is hex. It means structure contains six carbon atoms. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. The prefix used are E and Z. Thus, it means that the stereochemistry at one double bond is trans and at other is cis.

Thus, the correct structure of (2E,4Z)−1−bromo−3−methylhexa−2,4−diene is shown below.

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 4

Figure 2

Conclusion

The structure corresponding to (2E,4Z)−1−bromo−3−methylhexa−2,4−diene is shown in Figure 2.

Expert Solution

Interpretation Introduction

(c)

Interpretation: The structure corresponding to (2E,4E,6Z)−octa−2,4,6−triene is to be drawn.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing structural formula from IUPAC are:

1. First identify the word root for the given compound.

2. The suffix used in the compound like –ene.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

The prefix E and Z depends upon the location of the higher priority groups. When two higher priority groups are present on the opposite side then it is an E isomer, whereas when two higher priority groups are present on the same side then it is Z isomer.

Answer to Problem 16.37P

The structure corresponding to (2E,4E,6Z)−octa−2,4,6−triene is,

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 5

Explanation of Solution

The given name is (2E,4E,6Z)−octa−2,4,6−triene. The word root used in this is dec. It means structure contains ten carbon atoms. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. The prefix used is Z. It means that two higher priority groups are present on the same side. Thus, the correct structure to (2E,4E,6Z)−octa−2,4,6−triene is shown below.

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 6

Figure 3

Conclusion

The structure corresponding to (2E,4E,6Z)−octa−2,4,6−triene is shown in Figure 3.

Expert Solution

Interpretation Introduction

(d)

Interpretation: The structure corresponding to (2E,4E)−3−methylhexa−2,4−diene s−cis is to be drawn.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing structural formula from IUPAC are:

4. First identify the word root for the given compound.

5. The suffix used in the compound like –ene.

6. Identify the position, location, and number of the substituent bonded to the carbon chain.

The prefix E and Z depends upon the location of the higher priority groups. When two higher priority groups are present on the opposite side then it is an E isomer, whereas when two higher priority groups are present on the same side then it is Z isomer.

Answer to Problem 16.37P

The structure corresponding to (2E,4E)−3−methylhexa−2,4−diene in s−cis is,

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 7

Explanation of Solution

The given name is (2E,4E)−3−methylhexa−2,4−diene. The word root used in this is hex. It means structure contains six carbon atoms. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One methyl substituent is attached to the third carbon atom. The prefix used is E. It means that two higher priority groups are present on the opposite side. Thus, the correct structure to (2E,4E)−3−methylhexa−2,4−diene is shown below.

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 8

Figure 4

Conclusion

The structure corresponding to (2E,4E)−3−methylhexa−2,4−diene in s−cis is shown in Figure 4.

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Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution

Interpretation Introduction

(a)

Interpretation: The structure corresponding to (Z)−penta−1,3−diene in the s−trans conformation is to be drawn.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing structural formula from IUPAC are:

1. First identify the word root for the given compound.

2. The suffix used in the compound like –ene.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

The prefix E and Z depends upon the location of the higher priority groups. When two higher priority groups are present on the opposite side then it is an E isomer, whereas when two higher priority groups are present on the same side then it is Z isomer.

Answer to Problem 16.37P

The structure corresponding to (Z)−penta−1,3−diene in the s−trans conformation is,

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 1

Explanation of Solution

The given name is (Z)−penta−1,3−diene. The word root used in this is pent. It means structure contains five carbon atoms. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. The prefix used is Z. It means that two higher priority groups are present on the same side. The given compound has trans conformation. Thus, the correct structure of (Z)−penta−1,3−diene is shown below.

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 2

Figure 1

Conclusion

The structure corresponding to (Z)−penta−1,3−diene in the s−trans conformation is shown in Figure 1.

Expert Solution

Interpretation Introduction

(b)

Interpretation: The structure corresponding to (2E,4Z)−1−bromo−3−methylhexa−2,4−diene is to be drawn.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing structural formula from IUPAC are:

1. First identify the word root for the given compound.

2. The suffix used in the compound like –ene.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

The prefix E and Z depends upon the location of the higher priority groups. When two higher priority groups are present on the opposite side then it is an E or trans isomer, whereas when two higher priority groups are present on the same side then it is Z or cis isomer.

Answer to Problem 16.37P

The structure corresponding to (2E,4Z)−1−bromo−3−methylhexa−2,4−diene is,

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 3

Explanation of Solution

The given name is (2E,4Z)−1−bromo−3−methylhexa−2,4−diene. The word root used in this is hex. It means structure contains six carbon atoms. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. The prefix used are E and Z. Thus, it means that the stereochemistry at one double bond is trans and at other is cis.

Thus, the correct structure of (2E,4Z)−1−bromo−3−methylhexa−2,4−diene is shown below.

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 4

Figure 2

Conclusion

The structure corresponding to (2E,4Z)−1−bromo−3−methylhexa−2,4−diene is shown in Figure 2.

Expert Solution

Interpretation Introduction

(c)

Interpretation: The structure corresponding to (2E,4E,6Z)−octa−2,4,6−triene is to be drawn.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing structural formula from IUPAC are:

1. First identify the word root for the given compound.

2. The suffix used in the compound like –ene.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

The prefix E and Z depends upon the location of the higher priority groups. When two higher priority groups are present on the opposite side then it is an E isomer, whereas when two higher priority groups are present on the same side then it is Z isomer.

Answer to Problem 16.37P

The structure corresponding to (2E,4E,6Z)−octa−2,4,6−triene is,

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 5

Explanation of Solution

The given name is (2E,4E,6Z)−octa−2,4,6−triene. The word root used in this is dec. It means structure contains ten carbon atoms. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. The prefix used is Z. It means that two higher priority groups are present on the same side. Thus, the correct structure to (2E,4E,6Z)−octa−2,4,6−triene is shown below.

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 6

Figure 3

Conclusion

The structure corresponding to (2E,4E,6Z)−octa−2,4,6−triene is shown in Figure 3.

Expert Solution

Interpretation Introduction

(d)

Interpretation: The structure corresponding to (2E,4E)−3−methylhexa−2,4−diene s−cis is to be drawn.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing structural formula from IUPAC are:

4. First identify the word root for the given compound.

5. The suffix used in the compound like –ene.

6. Identify the position, location, and number of the substituent bonded to the carbon chain.

The prefix E and Z depends upon the location of the higher priority groups. When two higher priority groups are present on the opposite side then it is an E isomer, whereas when two higher priority groups are present on the same side then it is Z isomer.

Answer to Problem 16.37P

The structure corresponding to (2E,4E)−3−methylhexa−2,4−diene in s−cis is,

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 7

Explanation of Solution

The given name is (2E,4E)−3−methylhexa−2,4−diene. The word root used in this is hex. It means structure contains six carbon atoms. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One methyl substituent is attached to the third carbon atom. The prefix used is E. It means that two higher priority groups are present on the opposite side. Thus, the correct structure to (2E,4E)−3−methylhexa−2,4−diene is shown below.

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 8

Figure 4

Conclusion

The structure corresponding to (2E,4E)−3−methylhexa−2,4−diene in s−cis is shown in Figure 4.

Answer 8

Expert Solution

Interpretation Introduction

(a)

Interpretation: The structure corresponding to (Z)−penta−1,3−diene in the s−trans conformation is to be drawn.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing structural formula from IUPAC are:

1. First identify the word root for the given compound.

2. The suffix used in the compound like –ene.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

The prefix E and Z depends upon the location of the higher priority groups. When two higher priority groups are present on the opposite side then it is an E isomer, whereas when two higher priority groups are present on the same side then it is Z isomer.

Answer to Problem 16.37P

The structure corresponding to (Z)−penta−1,3−diene in the s−trans conformation is,

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 1

Explanation of Solution

The given name is (Z)−penta−1,3−diene. The word root used in this is pent. It means structure contains five carbon atoms. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. The prefix used is Z. It means that two higher priority groups are present on the same side. The given compound has trans conformation. Thus, the correct structure of (Z)−penta−1,3−diene is shown below.

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 2

Figure 1

Conclusion

The structure corresponding to (Z)−penta−1,3−diene in the s−trans conformation is shown in Figure 1.

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Interpretation Introduction

(a)

Interpretation: The structure corresponding to (Z)−penta−1,3−diene in the s−trans conformation is to be drawn.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing structural formula from IUPAC are:

1. First identify the word root for the given compound.

2. The suffix used in the compound like –ene.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

The prefix E and Z depends upon the location of the higher priority groups. When two higher priority groups are present on the opposite side then it is an E isomer, whereas when two higher priority groups are present on the same side then it is Z isomer.

Answer 13

Answer to Problem 16.37P

The structure corresponding to (Z)−penta−1,3−diene in the s−trans conformation is,

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 1

Answer 14

Explanation of Solution

The given name is (Z)−penta−1,3−diene. The word root used in this is pent. It means structure contains five carbon atoms. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. The prefix used is Z. It means that two higher priority groups are present on the same side. The given compound has trans conformation. Thus, the correct structure of (Z)−penta−1,3−diene is shown below.

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 2

Figure 1

Answer 15

Conclusion

The structure corresponding to (Z)−penta−1,3−diene in the s−trans conformation is shown in Figure 1.

Answer 16

Expert Solution

Interpretation Introduction

(b)

Interpretation: The structure corresponding to (2E,4Z)−1−bromo−3−methylhexa−2,4−diene is to be drawn.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing structural formula from IUPAC are:

1. First identify the word root for the given compound.

2. The suffix used in the compound like –ene.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

The prefix E and Z depends upon the location of the higher priority groups. When two higher priority groups are present on the opposite side then it is an E or trans isomer, whereas when two higher priority groups are present on the same side then it is Z or cis isomer.

Answer to Problem 16.37P

The structure corresponding to (2E,4Z)−1−bromo−3−methylhexa−2,4−diene is,

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 3

Explanation of Solution

The given name is (2E,4Z)−1−bromo−3−methylhexa−2,4−diene. The word root used in this is hex. It means structure contains six carbon atoms. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. The prefix used are E and Z. Thus, it means that the stereochemistry at one double bond is trans and at other is cis.

Thus, the correct structure of (2E,4Z)−1−bromo−3−methylhexa−2,4−diene is shown below.

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 4

Figure 2

Conclusion

The structure corresponding to (2E,4Z)−1−bromo−3−methylhexa−2,4−diene is shown in Figure 2.

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Expert Solution

Answer 20

Interpretation Introduction

(b)

Interpretation: The structure corresponding to (2E,4Z)−1−bromo−3−methylhexa−2,4−diene is to be drawn.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing structural formula from IUPAC are:

1. First identify the word root for the given compound.

2. The suffix used in the compound like –ene.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

The prefix E and Z depends upon the location of the higher priority groups. When two higher priority groups are present on the opposite side then it is an E or trans isomer, whereas when two higher priority groups are present on the same side then it is Z or cis isomer.

Answer 21

Answer to Problem 16.37P

The structure corresponding to (2E,4Z)−1−bromo−3−methylhexa−2,4−diene is,

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 3

Answer 22

Explanation of Solution

The given name is (2E,4Z)−1−bromo−3−methylhexa−2,4−diene. The word root used in this is hex. It means structure contains six carbon atoms. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. The prefix used are E and Z. Thus, it means that the stereochemistry at one double bond is trans and at other is cis.

Thus, the correct structure of (2E,4Z)−1−bromo−3−methylhexa−2,4−diene is shown below.

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 4

Figure 2

Answer 23

Conclusion

The structure corresponding to (2E,4Z)−1−bromo−3−methylhexa−2,4−diene is shown in Figure 2.

Answer 24

Expert Solution

Interpretation Introduction

(c)

Interpretation: The structure corresponding to (2E,4E,6Z)−octa−2,4,6−triene is to be drawn.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing structural formula from IUPAC are:

1. First identify the word root for the given compound.

2. The suffix used in the compound like –ene.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

The prefix E and Z depends upon the location of the higher priority groups. When two higher priority groups are present on the opposite side then it is an E isomer, whereas when two higher priority groups are present on the same side then it is Z isomer.

Answer to Problem 16.37P

The structure corresponding to (2E,4E,6Z)−octa−2,4,6−triene is,

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 5

Explanation of Solution

The given name is (2E,4E,6Z)−octa−2,4,6−triene. The word root used in this is dec. It means structure contains ten carbon atoms. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. The prefix used is Z. It means that two higher priority groups are present on the same side. Thus, the correct structure to (2E,4E,6Z)−octa−2,4,6−triene is shown below.

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 6

Figure 3

Conclusion

The structure corresponding to (2E,4E,6Z)−octa−2,4,6−triene is shown in Figure 3.

Answer 25

Expert Solution

Answer 26

Expert Solution

Answer 27

Expert Solution

Answer 28

Interpretation Introduction

(c)

Interpretation: The structure corresponding to (2E,4E,6Z)−octa−2,4,6−triene is to be drawn.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing structural formula from IUPAC are:

1. First identify the word root for the given compound.

2. The suffix used in the compound like –ene.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

The prefix E and Z depends upon the location of the higher priority groups. When two higher priority groups are present on the opposite side then it is an E isomer, whereas when two higher priority groups are present on the same side then it is Z isomer.

Answer 29

Answer to Problem 16.37P

The structure corresponding to (2E,4E,6Z)−octa−2,4,6−triene is,

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 5

Answer 30

Explanation of Solution

The given name is (2E,4E,6Z)−octa−2,4,6−triene. The word root used in this is dec. It means structure contains ten carbon atoms. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. The prefix used is Z. It means that two higher priority groups are present on the same side. Thus, the correct structure to (2E,4E,6Z)−octa−2,4,6−triene is shown below.

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 6

Figure 3

Answer 31

Conclusion

The structure corresponding to (2E,4E,6Z)−octa−2,4,6−triene is shown in Figure 3.

Answer 32

Expert Solution

Interpretation Introduction

(d)

Interpretation: The structure corresponding to (2E,4E)−3−methylhexa−2,4−diene s−cis is to be drawn.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing structural formula from IUPAC are:

4. First identify the word root for the given compound.

5. The suffix used in the compound like –ene.

6. Identify the position, location, and number of the substituent bonded to the carbon chain.

The prefix E and Z depends upon the location of the higher priority groups. When two higher priority groups are present on the opposite side then it is an E isomer, whereas when two higher priority groups are present on the same side then it is Z isomer.

Answer to Problem 16.37P

The structure corresponding to (2E,4E)−3−methylhexa−2,4−diene in s−cis is,

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 7

Explanation of Solution

The given name is (2E,4E)−3−methylhexa−2,4−diene. The word root used in this is hex. It means structure contains six carbon atoms. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One methyl substituent is attached to the third carbon atom. The prefix used is E. It means that two higher priority groups are present on the opposite side. Thus, the correct structure to (2E,4E)−3−methylhexa−2,4−diene is shown below.

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 8

Figure 4

Conclusion

The structure corresponding to (2E,4E)−3−methylhexa−2,4−diene in s−cis is shown in Figure 4.

Answer 33

Expert Solution

Answer 34

Expert Solution

Answer 35

Expert Solution

Answer 36

Interpretation Introduction

(d)

Interpretation: The structure corresponding to (2E,4E)−3−methylhexa−2,4−diene s−cis is to be drawn.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing structural formula from IUPAC are:

4. First identify the word root for the given compound.

5. The suffix used in the compound like –ene.

6. Identify the position, location, and number of the substituent bonded to the carbon chain.

The prefix E and Z depends upon the location of the higher priority groups. When two higher priority groups are present on the opposite side then it is an E isomer, whereas when two higher priority groups are present on the same side then it is Z isomer.

Answer 37

Answer to Problem 16.37P

The structure corresponding to (2E,4E)−3−methylhexa−2,4−diene in s−cis is,

Organic Chemistry, Chapter 16, Problem 16.37P , additional homework tip 7

Answer 38

Explanation of Solution

The given name is (2E,4E)−3−methylhexa−2,4−diene. The word root used in this is hex. It means structure contains six carbon atoms. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One methyl substituent is attached to the third carbon atom. The prefix used is E. It means that two higher priority groups are present on the opposite side. Thus, the correct structure to (2E,4E)−3−methylhexa−2,4−diene is shown below.