
Concept explainers
Interpretation:
The formula of the ion responsible for the base peak is to be determined.
Concept introduction:
In a mass spectrometer, the molecules of the compound are bombarded with high energy electrons. This generally results in one electron from the molecule being knocked out. The resulting ion is a radical ion with an odd number of electrons, called the molecular ion. Since the mass of an electron is negligible, the mass of the molecule and the molecular ion are essentially the same.
The molecular ion is a high energy species and breaks up into a number of fragments, one of which carries the charge. Another source of fragmentation is the bombarding electrons themselves. These electrons often have energies sufficient to not just knock out an electron but also enough to break bonds.
The only species detected in the mass spectrometer are the charged species and their separation is based on the
The mass spectrum shows the distribution of the relative abundance of various ion fragments as a function of their
This means the
The most abundant ion, however, is not the molecular ion. In most cases, it is of a lower mass. The peak for this ion is called the base peak. The spectrum is scaled so that the base peak is 100% relative abundance.

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Chapter 16 Solutions
Organic Chemistry: Principles And Mechanisms (second Edition)
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- The crystal field splitting energy, Δ, of a complex is determined to be 2.9 × 10-19 What wavelength of light would this complex absorb? What color of light is this? What color would the compound be in solution?arrow_forwardA key component of a monochromator is the exit slit. As the exit slit is narrowed, the bandwidth of light (i.e., the range of wavelengths) exiting the slit gets smaller, leading to higher resolution. What is a possible disadvantage of narrowing the exit slit? (Hint: why might a narrower slit lower the sensitivity of the measurement?).arrow_forwardAn x-ray has a frequency of 3.33 × 1018 What is the wavelength of this light?arrow_forward
- Choose the Lewis structure for the compound below: H2CCHOCH2CH(CH3)2 HH H :d H H H C. Η H H HH H H H H. H H H HH H H H H H- H H H C-H H H HHHHarrow_forwardEach of the highlighted carbon atoms is connected to hydrogen atoms.arrow_forwardく Complete the reaction in the drawing area below by adding the major products to the right-hand side. If there won't be any products, because nothing will happen under these reaction conditions, check the box under the drawing area instead. Note: if the products contain one or more pairs of enantiomers, don't worry about drawing each enantiomer with dash and wedge bonds. Just draw one molecule to represent each pair of enantiomers, using line bonds at the chiral center. More... No reaction. Explanation Check O + G 1. Na O Me Click and drag to start drawing a structure. 2. H + 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility 000 Ar Parrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning

