
Interpretation:
In Figure 16-34, a line to represent the path of an ion that is too light to reach the detector is to be drawn and labeled as “too light.” The same is to be done for an ion that is too massive to reach the detector and to be labeled as “too massive.”
Concept introduction:
Mass spectrometry provides insight into the mass of a molecule and the fragments that compose it. Unlike spectroscopy, however, mass spectrometry does not involve
Once vaporized, these gaseous molecules, M (g), drift through a beam of fast moving electrons. When an electron from that beam impacts a molecule of M (g), an electron from M (g) is knocked off, producing a gaseous species that has one fewer electron and therefore has a positive charge. The process of producing this molecular ion, M+ (g), is called electron impact ionization and can be represented by Equation 16-6.
A charged species like M+ (g) can be guided into a detector through a curved tube using a magnetic field to bend the ion’s path. The extent that a given ion’s path is bent depends on the strength of the magnetic field that is applied and the mass-to-charge ratio of the particle, represented as m/z. If the magnetic field strength is held fixed, then only ions of a specific value of m/z can reach the detector. Ions with m/z different from that value will collide with the wall of the tube and will be destroyed before reaching the detector; those that are too light will be deflected too much whereas those that are too massive will not be deflected enough. If multiple ions with different m/z values are present, then the magnetic field strength can be adjusted to allow the various ions to be detected. The detector itself is designed to keep track of the number of charged species that collide with it; this number is translated into what is called the relative abundance of the ion. The greater the number of charged species detected, the greater the ion’s relative abundance. If multiple ions are produced with different values of m/z, then the magnetic field strength can be scanned to determine the relative abundance at each m/z.

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Chapter 16 Solutions
Organic Chemistry: Principles And Mechanisms (second Edition)
- Predict the major products of the following organic reaction: O O + A ? Some important notes: • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. Explanation Check Click and drag to start drawing a structure. eserved. Terms of Use | Privacy Center >arrow_forward(EXM 2, PRBLM 3) Here is this problem, can you explain it to me and show how its done. Thank you I need to see the work for like prbl solving.arrow_forwardcan someone draw out the reaction mechanism for this reaction showing all bonds, intermediates and side products Comment on the general features of the 1H-NMR spectrum of isoamyl ester provided belowarrow_forward
- What would be the best choices for the missing reagents 1 and 3 in this synthesis? 1. PPh3 3 2. n-BuLi • Draw the missing reagents in the drawing area below. You can draw them in any arrangement you like. • Do not draw the missing reagent 2. If you draw 1 correctly, we'll know what it is. • Note: if one of your reagents needs to contain a halogen, use bromine. Click and drag to start drawing a structure.arrow_forwardIdentify the missing organic reactants in the following reaction: X + Y H+ two steps Note: This chemical equation only focuses on the important organic molecules in the reaction. Additional inorganic or small-molecule reactants or products (like H2O) are not shown. In the drawing area below, draw the skeletal ("line") structures of the missing organic reactants X and Y. You may draw the structures in any arrangement that you like, so long as they aren't touching. Click and drag to start drawing a structure. Х :arrow_forwardDraw the mechanism of friedel-crafts acylation using acetyl chloride of m-Xylenearrow_forward
- Don't used hand raiting and don't used Ai solution and correct answerarrow_forwardH R Part: 1/2 :CI: is a/an electrophile Part 2 of 2 Draw the skeletal structure of the product(s) for the Lewis acid-base reaction. Include lone pairs and formal charges (if applicable) on the structures. 4-7: H ö- H Skip Part Check X :C1: $ % L Fi Click and drag to start drawing a structure. MacBook Pro & ㅁ x G 0: P Add or increase positive formal cha Save For Later Submit ©2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Centearrow_forwardDraw the friedel-crafts acylation mechanism of m-Xylenearrow_forward
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