CAMPBELL BIOLOGY,VOL.II >CUSTOM<
17th Edition
ISBN: 9781323803677
Author: Urry
Publisher: PEARSON
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Chapter 16, Problem 16.2CR
DRAW IT Ø Redraw the Punnett Square on The right side of Figure 14.8 as two smaller monohybrid Punnett squares, one for each gene. Below each square. list the fractions of each
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Using the Dihybrid Cross, Give the Total Number and Types of Gametes formed of MmNnOoPPQQRrssTtQq.
Show all the gametes that are formed by the following genotypes.
In com, male sterility is controlled by maternal cytoplasmic elements. However, the presence of a nuclear fertility restorer gene (F_) restores fertility to male sterile lines. Using the following cardboard chips, simulate the crosses indicated below. Present your cross to your instructor for checking. After being checked, draw your simulated crosses in the spacesprovided below. Give the genotypes and phenotypes of the offspring in each cross, and properly label the nucleus and the cytoplasm of each individual in the crosses.Big white circular chips Male sterile cytoplasmBig peach circular chips Male fertile cytoplasmSmall peach circular chips FF nucleusSmall half-white-half-peach circular chips Ff nucleusSmall white circular chips ff nucleus
a. male sterile female x FF maleExplain your results.
b. male sterile female x Ff maleExplain your results.
Here are the progeny of this cross: (Note that the categories are not in any particular order.)Fly type # of prog. Phenotype symbols Categorywt eyes black body wt wings 97 grn+ blk crv+Green eyes black body curved wings 709 ParentalGreen eyes wt body wt wings 9Green eyes black body wt wings 162wt eyes wt body wt wings 727wt eyes black body curved wings 12wt eyes wt body curved wings 179Green eyes wt body curved wings 105Total = 2000
9.) Write the phenotype symbols in the right-hand column. The first one has been done for you.10.) Next to that, label all fly categories as parental (NCOs), SCOs, and DCOs. One has been donefor you.11.) After each SCO/DCO label, write which gene got “unlinked” in these offspring.12.) Put these three genes into a genetic map in the proper order.13.) Calculate the genetic distance between the genes and label the map with these distances.14.) Calculate the cross-over interference15.) Return to questions #1-6 above. For question 6, you gave your opinion, but…
Chapter 16 Solutions
CAMPBELL BIOLOGY,VOL.II >CUSTOM<
Ch. 16.1 - Given a polynucleotide sequence such as GAATTC,...Ch. 16.1 - VISUAL SKILLS Griffith was trying to develop a...Ch. 16.2 - What role does complementary base pairing play in...Ch. 16.2 - Identify two major functions of DNA pol III in DNA...Ch. 16.2 - Prob. 3CCCh. 16.2 - Prob. 4CCCh. 16.3 - Describe the structure of a nucleosome, the basic...Ch. 16.3 - What two properties, one structural and one...Ch. 16.3 - MAKE CONNECTIONS Interphase chromosomes appear to...Ch. 16 - What does it mean wheti we say that the two DNA...
Ch. 16 - DRAW IT Redraw the Punnett Square on The right...Ch. 16 - Describe the levels of chromatin packing you'd...Ch. 16 - In his work with pneumonia-causing bacteria and...Ch. 16 - What is the basis for tlie difference in how the...Ch. 16 - In analyzing the number of different bases in a...Ch. 16 - The elongation of the leading Strand during DNA...Ch. 16 - In a nucleosome, the DNA is wrapped around (A)...Ch. 16 - E. coli cells grown on, 15N medium are transferred...Ch. 16 - A biochemist isolates, purifies, and combines in a...Ch. 16 - The spontaneous loss of amino groups from adenine...Ch. 16 - MAKE CONNECTIONS Although the proteins that cause...Ch. 16 - EVOLUTION CONNECTION Some bacteria may be able to...Ch. 16 - SCIENTIFIC INQUIRY DRAW IT Model building can be...Ch. 16 - Prob. 12TYUCh. 16 - Prob. 13TYU
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- Please explain each steparrow_forwardThe mother of a family with 10 children has blood typeRh+. She also has a very rare condition (elliptocytosis,phenotype E) that causes red blood cells to be oval rather than round in shape but that produces no adverseclinical effects. The father is Rh− (lacks the Rh+ antigen)and has normal red blood cells (phenotype e). The children are 1 Rh+ e, 4 Rh+ E, and 5 Rh− e. Information isavailable on the mother’s parents, who are Rh+ E andRh− e. One of the 10 children (who is Rh+ E) marriessomeone who is Rh+ e, and they have an Rh+ E child.a. Draw the pedigree of this whole family.b. Is the pedigree in agreement with the hypothesisthat the Rh+ allele is dominant and Rh− is recessive?c. What is the mechanism of transmission ofelliptocytosis?d. Could the genes governing the E and Rh phenotypesbe on the same chromosome? If so, estimate the mapdistance between them, and comment on your resultarrow_forwardConsider the selfed offspring of a AaBbCcDd individual: What is the probability that offspring will have the following genotypes: AABBCCDD AaBbCCDd ● • A_B_C_D_ BbCCDd ● ● ● ● ● 1/4 x 1/4 x 1/4 x 1/4= 1/256 1/2 x 1/2 x 1/4 x 1/2= 1/32 3/4 x 3/4 x 3/4 x 3/4= 81/256 1 x 1/2 x 1/4 x 1/2= 1/16 Same genotype as the parent? A.1 B. 1/1/12 C. D.1/8 E.1/16arrow_forward
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- The aldose gene is 10 map units from the fructose gene. (A = dominant allele, can produce aldose; a = recessive allele, cannot produce aldose; F = dominant allele, can produce fructose; f = recessive allele, cannot produce fructose). You cross worms with the chromosomes shown below. What is the probability that offspring will be able to produce only aldose (and not fructose)? A f a f ----- X ----- a F a f A) 10% B) 5% C) 90% D) 45% E) 0% F) 25% G) 50% H) 33%arrow_forwardShow a completed punnett square for the following Dihybrid Cross: AaBb x AAbb. A=normal; a= short; B=bright; b=dull. Show your work for full credit. Give the expected genotypic and phenotypic ratios.arrow_forwardA large ear of corn has a total of 433 grains, including 271 purple & smooth, 73 purple & shrunken, 63yellow & smooth, & 26 yellow & shrunken. Conduct a X^2 analysis to determine if this ear of corn was produced by adihybrid cross (PpRr x PpRr) resulting in a phenotypic ratio of 9:3:3:1.arrow_forward
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