Chapter 15.8, Problem 15.11SC

Interpretation Introduction

Interpretation:

The volume of 0.50 N ${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$ is needed to react with 0.250 L of 0.80 N $\text{KOH}$ should be calculated.

Concept Introduction:

Normality of the solution is equal to the ratio of equivalent weight in grams of solute to the volume of solution in litres.

The mathematical expression is given by:

Normality = $\frac{\text{gram equivalent weight}}{\text{ volume of solution in litres}}$

Now, 1 equivalent of acid consist of same number of H+ as the number of OH- ions present in 1 equivalent of base. Equal equivalents of acid and base are required for neutralization. Thus, expression is given by:

${\text{N}}_{\text{acid}}{\text{V}}_{\text{acid}}{\text{=N}}_{\text{base}}{\text{V}}_{\text{base}}$.