Explanation Given information: Four solutions are given. In every solution volume of solvent is 1 litre and it will be the volume of solution. 100.0 gm of caesium chloride is dissolved in 1.0 L of water. 100.0 gm of sodium sulphate is dissolved in 1.0 L of water. 100.0 gm caesium fluoride dissolved in 1.0 L of water. 100.0 gm of sodium phosphate is dissolved in 1.0 L of water. Grams of solute and volume of solvent is given for calculating the concentration of solution, we will calculate their molarity to check which one is having highest concentration. Molarity is defined as moles of solute per litre of solution. Following can be used to calculate molarity. Molarity= Moles of solute Litres of solution Solution 1: 100.0 gm of caesium chloride is dissolved in 1.0 L of water. Molecular weight of caesium chloride=168 .36 g/mol Moles of caesium chloride=100× 1 Mole of CsCl 168 .36 Moles of caesium chloride=0 .59 moles Molarity= Moles of solute Litres of solution Molarity= 0 .59 1 =0 .59 M Solution 2: 100.0 gm of sodium sulphate is dissolved in 1.0 L of water. Molecular weight of sodium sulphate=142 .04 g/mol Moles of sodium sulphate=100× 1 Mole of Na 2 SO 4 142 .04 Moles of sodium sulphate=0 .70 moles Molarity= Moles of solute Litres of solution Molarity= 0

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ISBN: 9781285199030

Author: Steven S. Zumdahl, Donald J. DeCoste

Publisher: Cengage Learning

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Chapter 15, Problem 135AP

Interpretation Introduction

Interpretation:

From the given solutions, which solution is having highest concentration of solute is to be determined.

Concept Introduction:

Number of moles of solute per litre of solution is called molarity. Molarity is the way of expressing concentration of solution.

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Chapter 15, Problem 134AP

Chapter 15, Problem 136AP

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Chapter 15 Solutions

Introductory Chemistry: A Foundation

Ch. 15.3 - ercise 15.1 A 1 35-g sample of seawater is...Ch. 15.3 - Prob. 15.2SC Ch. 15.4 - ercise 15.3 Calculate the molarity of a solution...Ch. 15.4 - ercise 15.4 Give the concentrations of the ions in...Ch. 15.4 - ercise 15.5 Calculate the number of moles of Cl...Ch. 15.4 - ercise 15.6 Formalin is an aqueous solution of...Ch. 15.5 - ercise 15.7 What volume of 12 M HCI must be taken...Ch. 15.6 - at if all ionic solids were soluble in water? How...Ch. 15.6 - Exercise 15.8 When aqueous solutions of Na2SO3 and...Ch. 15.7 - ercise 15.9 Calculate the volume of 0.10 M HNO3...

Ch. 15.8 - ercise 15.10 Calculate the normality of a solution...Ch. 15.8 - Prob. 15.11SC Ch. 15 - ou have a solution of table sail in water. What...Ch. 15 - onsider a sugar solution (solution A) with...Ch. 15 - You need to make 150.0 mL of a 0.10 M NaCI...Ch. 15 - ou have two solutions containing solute A. To...Ch. 15 - m>5. Which of the following do you need to know to...Ch. 15 - onsider separate aqueous solutions of HCI and...Ch. 15 - Prob. 7ALQ Ch. 15 - an one solution have a greater concentration than...Ch. 15 - Prob. 9ALQ Ch. 15 - You have equal masses of different solutes...Ch. 15 - Which of the following solutions contains the...Ch. 15 - As with all quantitative problems in chemistry,...Ch. 15 - Prob. 13ALQ Ch. 15 - Prob. 14ALQ Ch. 15 - solution is a homogeneous mixture. Can you give an...Ch. 15 - ow do the properties of a nonhomogeneous...Ch. 15 - Prob. 3QAP Ch. 15 - Prob. 4QAP Ch. 15 - n Chapter 14. you learned that the bonding forces...Ch. 15 - n oil spill spreads out on the surface of water,...Ch. 15 - . The “Chemistry in Focus” segment Water, Water...Ch. 15 - Prob. 8QAP Ch. 15 - Prob. 9QAP Ch. 15 - Prob. 10QAP Ch. 15 - A solution is a homogeneous mixture and, unlike a...Ch. 15 - Prob. 12QAP Ch. 15 - How do we define the mass percent composition of a...Ch. 15 - Prob. 14QAP Ch. 15 - Calculate the percent by mass of solute in each of...Ch. 15 - Calculate the percent by mass of solute in each of...Ch. 15 - Prob. 17QAP Ch. 15 - Prob. 18QAP Ch. 15 - A sample of an iron alloy contains 92.1 g Fe. 2.59...Ch. 15 - Consider the iron alloy described in Question 19....Ch. 15 - An aqueous solution is to be prepared that will be...Ch. 15 - Prob. 22QAP Ch. 15 - A solution is to be prepared that will be 4.50% by...Ch. 15 - Prob. 24QAP Ch. 15 - Prob. 25QAP Ch. 15 - Hydrogen peroxide solutions sold in drugstores as...Ch. 15 - Prob. 27QAP Ch. 15 - A solvent sold for use in the laboratory contains...Ch. 15 - Prob. 29QAP Ch. 15 - Prob. 30QAP Ch. 15 - What is a standard solution? Describe the steps...Ch. 15 - Prob. 32QAP Ch. 15 - 33. For each of the following solutions, the...Ch. 15 - 34. For each of the following solutions, the...Ch. 15 - 35. For each of the following solutions, the mass...Ch. 15 - Prob. 36QAP Ch. 15 - 37. A laboratory assistant needs to prepare 225 mL...Ch. 15 - Prob. 38QAP Ch. 15 - 39. Standard solutions of calcium ion used to test...Ch. 15 - Prob. 40QAP Ch. 15 - 41. If 42.5 g of NaOH is dissolved in water and...Ch. 15 - 42. Standard silver nitrate solutions are used in...Ch. 15 - Prob. 43QAP Ch. 15 - Prob. 44QAP Ch. 15 - Prob. 45QAP Ch. 15 - Prob. 46QAP Ch. 15 - Prob. 47QAP Ch. 15 - 48. What mass of solute is present in 225 mL of...Ch. 15 - Prob. 49QAP Ch. 15 - Prob. 50QAP Ch. 15 - Prob. 51QAP Ch. 15 - Strong acid solutions may have their concentration...Ch. 15 - Prob. 53QAP Ch. 15 - Prob. 54QAP Ch. 15 - Prob. 55QAP Ch. 15 - Prob. 56QAP Ch. 15 - Prob. 57QAP Ch. 15 - Prob. 58QAP Ch. 15 - Prob. 59QAP Ch. 15 - 60. Suppose 325 in L of 0.150 M NaOH is needed for...Ch. 15 - 61. How much water must be added w 500. mL of...Ch. 15 - An experiment calls for 100. mL of 1.25 M HC1. All...Ch. 15 - Prob. 63QAP Ch. 15 - 64. Generally only the carbonates of the Group I...Ch. 15 - 65. Many metal ions are precipitated from solution...Ch. 15 - 66. Calcium oxalate, CaCO4, is very insoluble in...Ch. 15 - 67. When aqueous solutions of lead(II) ion are...Ch. 15 - 68. Aluminum ion may be precipitated from aqueous...Ch. 15 - 69. What volume of 0.502 M NaOH solution would be...Ch. 15 - 70. What volume of a 0.500 M NaOH solution would...Ch. 15 - 71. A sample of sodium hydrogen carbonate solid...Ch. 15 - 72. The total acidity in water samples can be...Ch. 15 - Prob. 73QAP Ch. 15 - Prob. 74QAP Ch. 15 - Prob. 75QAP Ch. 15 - Prob. 76QAP Ch. 15 - 77. Explain why the equivalent weight of H2SO4 is...Ch. 15 - Prob. 78QAP Ch. 15 - Prob. 79QAP Ch. 15 - Prob. 80QAP Ch. 15 - Prob. 81QAP Ch. 15 - Prob. 82QAP Ch. 15 - Prob. 83QAP Ch. 15 - Prob. 84QAP Ch. 15 - 85. How many milliliters of 0.50 N NaOH are...Ch. 15 - 86. What volume of 0.104 N H2SO4is required to...Ch. 15 - 87. What volume of 0.151 N NaOH is required to...Ch. 15 - Prob. 88QAP Ch. 15 - 89. A mixture is prepared by mixing 50.0 g of...Ch. 15 - Prob. 90AP Ch. 15 - 91. Suppose 50.0 mL of 0.250 M CoCl2 solution is...Ch. 15 - Prob. 92AP Ch. 15 - 93. Calculate the mass of AgCl formed, and the...Ch. 15 - 94. Baking soda (sodium hydrogen carbonate....Ch. 15 - 95. Many metal ions form insoluble sulfide...Ch. 15 - Prob. 96AP Ch. 15 - Prob. 97AP Ch. 15 - Prob. 98AP Ch. 15 - Prob. 99AP Ch. 15 - Prob. 100AP Ch. 15 - Prob. 101AP Ch. 15 - You mix 225.0 mL of a 2.5 M HCl solution with...Ch. 15 - A solution is 0.1% by mass calcium chloride....Ch. 15 - Prob. 104AP Ch. 15 - Prob. 105AP Ch. 15 - A certain grade of steel is made by dissolving 5.0...Ch. 15 - Prob. 107AP Ch. 15 - Prob. 108AP Ch. 15 - Prob. 109AP Ch. 15 - Prob. 110AP Ch. 15 - How many moles of each ion are present in 11.7 mL...Ch. 15 - Prob. 112AP Ch. 15 - Prob. 113AP Ch. 15 - Prob. 114AP Ch. 15 - Concentrated hydrochloric acid is made by pumping...Ch. 15 - A large beaker contains 1.50 L of a 2.00 M...Ch. 15 - Prob. 117AP Ch. 15 - Prob. 118AP Ch. 15 - If 10. g of AgNO3 is available, what volume of...Ch. 15 - Prob. 120AP Ch. 15 - Calcium carbonate, CaCO3, can be obtained in a...Ch. 15 - Prob. 122AP Ch. 15 - How many milliliters of 18.0 M H2SO4 are required...Ch. 15 - Prob. 124AP Ch. 15 - When 10. 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From the given solutions, which solution is having highest concentration of solute is to be determined. Concept Introduction: Number of moles of solute per litre of solution is called molarity. Molarity is the way of expressing concentration of solution.

Solution Summary: The author explains that the number of moles of solute per litre of solution is called molarity.

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Interpretation: From the given solutions, which solution is having highest concentration of solute is to be determined. Concept Introduction: Number of moles of solute per litre of solution is called molarity. Molarity is the way of expressing concentration of solution.

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Chapter 15 Solutions

Interpretation:

From the given solutions, which solution is having highest concentration of solute is to be determined.

Concept Introduction:

Number of moles of solute per litre of solution is called molarity. Molarity is the way of expressing concentration of solution.