Explanation Write the combustion reaction of methane and propane mixture with theoretical amount of air. 0 .4CH 4 + 0.6 C 3 H 8 + a th [ O 2 + 3.76 N 2 ] → B CO 2 + D CO + F N 2 (I) Write the formula to calculate the vapor mole fraction ( y v ) in the product. y v = N v N prod (II) Here, number of moles of water vapor is N v and number of moles of product is N prod . Write the expression to calculate the partial pressure of water vapor ( P v ) . P v = y v P prod (III) Here, partial pressure of the product is P prod . Write the expression to calculate the partial pressure of water vapor remaining in the product. P v = N v N total, product P prod (IV) Here, number of moles of product after condensation is N total, product . Write the expression to calculate the amount of water condensed ( N w ) . N w = N H 2 O − N v (V) Draw the T − s diagram for the water vapor that does not condense as in Figure (1). Conclusion: Balance for the carbon from Combustion reaction Equation (I). B = 0.4 + 3 × 0.6 B = 2.2 Balance for the hydrogen from Combustion reaction Equation (I). 2 D = 4 × 0.4 + 8 × 0.6 D = 3.2 Balance for the oxygen from Combustion reaction Equation (I). 2 a th = 2 B + D Substitute 2.2 for B and 3.2 for D . 2 a th = 2 ( 2.2 ) + 3.2 a th = 3.8 Balance for the nitrogen from Combustion reaction Equation (I). 3.76 a th = F Substitute 3.8 for a th . 3.76 ( 3.8 ) = F F = 14.29 Rewrite the complete balanced chemical reaction for combustion as follows: 0 .4CH 4 + 0.6 C 3 H 8 + 3.8 [ O 2 + 3.76 N 2 ] → 2.2 CO 2 + 3.2 CO + 14

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ISBN: 9780073398174

Author: Yunus A. Cengel Dr., Michael A. Boles

Publisher: McGraw-Hill Education

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Chapter 15.7, Problem 97RP

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The number of kilo moles of water condensed during the combustion process.

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Chapter 15.7, Problem 96RP

Chapter 15.7, Problem 98RP

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Thermodynamics: An Engineering Approach

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