Chapter 15.6, Problem 3TY

Interpretation Introduction

Interpretation:

The change in potential when $\text{1}{\text{.0×10}}^{\text{-4}}\text{M}$ at pH $\text{5}\text{.5}$ is raised to pH $\text{9}\text{.5}$ has to be calculated.

Concept Introduction:-

Response of ion-selective electrode:

The response of an ion-selective electrode to its primary ion (A) and to interfering ions of the same charge, when the response to every ion is Nernstian.

$\text{E=}\text{constant+}\frac{\text{0}\text{.05916}}{{\text{z}}_{\text{A}}}\text{log}\left[{\text{A}}_{\text{A}}\text{+}{\displaystyle \sum _{\text{X}}^{}{\text{K}}_{\text{A,X}}^{\text{Pot}}}{\text{A}}_{\text{X}}\right]$