Chapter 15, Problem 15.11P

Interpretation Introduction

Interpretation:

The molarity and pH of the $\text{KOH}$ solution and concentrations of $\left[{\text{CN}}^{\text{-}}\right]\left[\text{KOH}\right]$  has to be calculated.

Concept introduction:

Cell Voltage:

Cell voltage is the difference between cathode potential and anode potential.

${\text{E}}_{\text{cell}}\text{=}{\text{E}}_{\text{+}}\text{-}{\text{E}}_{\text{-}}$

Molarity

Molarity of a solution can be defined as number of moles soluble per one litre of the solution

$\text{molarity=}\frac{\text{moles}\text{of}\text{the}\text{solute}}{\text{litre}\text{of}\text{the}\text{solution}}$

pH can be calculated using the formula

${\text{pH=pK}}_{\text{a}}\text{(HCN)+log}\frac{\left[{\text{CN}}^{\text{-}}\right]}{\left[\text{HCN}\right]}$