Chapter 15, Problem 15.18P

a)

Interpretation Introduction

Interpretation:

The equilibrium constant of the net cell reaction has to be calculated.

Concept introduction:

Nernst equation:

${\text{E=E}}^{\text{0}}\text{-}\frac{\text{0}\text{.05916}}{\text{n}}\text{logK}$

When $\text{E}$ is zero, the equilibrium constant is

${\text{0=E}}^{\text{0}}\text{-}\frac{\text{0}\text{.05916}}{\text{n}}\text{logK}$

Equilibrium constant $\text{K=}{\text{10}}^{\raisebox{1ex}{${\text{nE}}^{\text{0}}$}\!\left/ \!\raisebox{-1ex}{$\text{0}\text{.05916}$}\right.}$

b)

Interpretation Introduction

Interpretation:

The percentage increase in equilibrium constant of the net cell reaction was calculated.

Concept introduction:

Nernst equation:

${\text{E=E}}^{\text{0}}\text{-}\frac{\text{0}\text{.05916}}{\text{n}}\text{logK}$

When $\text{E}$ is zero, the equilibrium constant is

${\text{0=E}}^{\text{0}}\text{-}\frac{\text{0}\text{.05916}}{\text{n}}\text{logK}$

Equilibrium constant $\text{K=}{\text{10}}^{\raisebox{1ex}{${\text{nE}}^{\text{0}}$}\!\left/ \!\raisebox{-1ex}{$\text{0}\text{.05916}$}\right.}$

c)

Interpretation Introduction

Interpretation:

The equilibrium constant and percentage change when, ${\text{E}}^{\text{0}}$ for the cell reaction is changed has to be calculated.

Concept introduction:

Nernst equation:

${\text{E=E}}^{\text{0}}\text{-}\frac{\text{0}\text{.05916}}{\text{n}}\text{logK}$

When $\text{E}$ is zero, the equilibrium constant is

${\text{0=E}}^{\text{0}}\text{-}\frac{\text{0}\text{.05916}}{\text{n}}\text{logK}$

Equilibrium constant $\text{K=}{\text{10}}^{\raisebox{1ex}{${\text{nE}}^{\text{0}}$}\!\left/ \!\raisebox{-1ex}{$\text{0}\text{.05916}$}\right.}$