Chapter 15.5, Problem 15.7P

Interpretation Introduction

Interpretation:

Molarity of $\text{50}\text{.0 mL}$$\text{HCl}$ required for neutralization of $\text{24}\text{.81 mL}$ of $\text{0}\text{.1250 }M\text{ NaOH}$ has to be calculated.

Concept Introduction:

The dilution formula is given as follows:

  $M_1{V}_1=M_2{V}_2$        (1)

Here,

$M_1$ denotes molarity of  initial solution before dilution.

$V_1$ denotes the volume before dilution.

$M_2$ denotes the molarity of final solution after dilution.

$V_2$ denotes the volume after dilution.