FOUND.OF COLLEGE CHEMISTRY
FOUND.OF COLLEGE CHEMISTRY
15th Edition
ISBN: 9781119234555
Author: Hein
Publisher: WILEY
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Chapter 15, Problem 21RQ
Interpretation Introduction

Interpretation:

The reason behind insolubility of HCl in hexane but solubility in water has to be explained.

Concept Introduction:

An electrolyte refers to an ionic compound that on solvation in polar protic solvents ionizes to yield cationic and anionic species. The free movement of such ionic species results in the conduction of electricity.

Three subcategories exist for electrolyte namely strong electrolyte, weak electrolyte and non-electrolyte. The strong electrolytes on dissolution exhibit 100 % dissociation; The acids such as HCl , CH3COOH, H2SO4, HNO3 that has ability to furnish hydronium ions and bases such as NaOH, KOH ionize fully to yield hydroxide ions are strong electrolytes.

 In contrast, the weak electrolytes are not 100 % dissociated, theses may include weak acids and bases such as carbonic acid, nitrous acid, boric acid, HClO, NH3.

The principle of “like dissolves like” holds true and suggests that ionic or polar substances are more soluble in similar polar solvent such as water.

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Part C – Acid–base and solubility equilibria 1. Rinse 4 regular size test tubes and a 10 mL measuring cylinder thoroughly with water. Number the test-tubes from 1 to 4 in a test tube rack. 2. Into each of test tubes 1 – 3 put a small amount of solid benzoic acid (put the same amount – about the size of a pea – in each test tube). 3. Add 2 mL (use the measuring cylinder) of water to tube 1 and shake to mix the contents. 4. Add 2 mL (measuring cylinder) of 2 M HNO3 to tube 2 and shake to mix the contents. 5. Rinse the measuring cylinder with water, then use it to add 2 mL of 2 M NaOH to tube 3 and shake for about 10 seconds to mix the contents. Rinse the measuring cylinder. 6. Pour about half of the solution from tube 3 into tube 4, than add 2 mL of 2 M HNO3 to tube 4. 7. Allow the test tubes to stand for 2 or 3 minutes then record the appearance of the mixtures in each test tube. 8. Answer the questions on the results page relating to this equilibrium system.
Arrange the compounds in increasing order according to its solubility in NaOH
A 0.5 g of a sample of an acid was dissolved in water and neutralized to 25 mL of 0.025 N NaOH. Calculate Equivalent mass of the acid.

Chapter 15 Solutions

FOUND.OF COLLEGE CHEMISTRY

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