Chapter 15, Problem 36PE

Interpretation Introduction

Interpretation:

Percent of $\text{NaCl}$ in $1.0\text{ g}$ sample that requires $\text{49}\text{.90 mL}$ of $\text{0}\text{.466 M HCl}$ has to be calculated.

Concept Introduction:

Molarity is quantitatively defined as moles of solute in one liter of solution. For example $\text{0}{\text{.070 M AlCl}}_3$ indicates that in $1\text{ L}$ the moles of ${\text{AlCl}}_3$ is $\text{0}\text{.070 mol}$.

The formula to calculate mass percent is as follows:

  $\text{Mass percent}=\left(\frac{\text{Given mass}}{\text{Molar mass}}\right)\left(100\text{ \%}\right)$