EBK BASIC CHEMISTRY
5th Edition
ISBN: 8220101472335
Author: Timberlake
Publisher: PEARSON
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Chapter 15.1, Problem 15.13QAP
Interpretation Introduction
(a)
Interpretation:
The oxidation number of the specified element in the following:
N in HNO3
Concept Introduction:
The rules for assigning oxidation number to elements are:
- For an element in its free state it is assigned an oxidation number of zero.
- Monatomic ions have oxidation number that is equal to charge of the monatomic ion.
- Alkali metals have +1 oxidation number, alkaline earth metals have +2 oxidation number and halogens are assigned -1 oxidation number.
- In most compounds H is assigned a +1 oxidation number and O is assigned a -2 oxidation number.
- For a neutral compound the summation of oxidation numbers of all elements in the compound is zero.
If the oxidation number of an element increases then it undergoes oxidation and if the oxidation number of the element decreases then it undergoes reduction.
Interpretation Introduction
(b)
Interpretation:
The oxidation number of the specified element in the following:
C in C3H6
Concept Introduction:
The rules for assigning oxidation number to elements are:
- For an element in its free state it is assigned an oxidation number of zero.
- Monatomic ions have oxidation number that is equal to charge of the monatomic ion.
- Alkali metals have +1 oxidation number, alkaline earth metals have +2 oxidation number and halogens are assigned -1 oxidation number.
- In most compounds H is assigned a +1 oxidation number and O is assigned a -2 oxidation number.
- For a neutral compound the summation of oxidation numbers of all elements in the compound is zero.
If the oxidation number of an element increases then it undergoes oxidation and if the oxidation number of the element decreases then it undergoes reduction.
Interpretation Introduction
(c)
Interpretation:
The oxidation number of the specified element in the following:
P in K3PO4
Concept Introduction:
The rules for assigning oxidation number to elements are:
- For an element in its free state it is assigned an oxidation number of zero.
- Monatomic ions have oxidation number that is equal to charge of the monatomic ion.
- Alkali metals have +1 oxidation number, alkaline earth metals have +2 oxidation number and halogens are assigned -1 oxidation number.
- In most compounds H is assigned a +1 oxidation number and O is assigned a -2 oxidation number.
- For a neutral compound the summation of oxidation numbers of all elements in the compound is zero.
If the oxidation number of an element increases then it undergoes oxidation and if the oxidation number of the element decreases then it undergoes reduction.
Interpretation Introduction
(d)
Interpretation:
The oxidation number of the specified element in the following:
Cr in CrO42-
Concept Introduction:
The rules for assigning oxidation number to elements are:
- For an element in its free state it is assigned an oxidation number of zero.
- Monatomic ions have oxidation number that is equal to charge of the monatomic ion.
- Alkali metals have +1 oxidation number, alkaline earth metals have +2 oxidation number and halogens are assigned -1 oxidation number.
- In most compounds H is assigned a +1 oxidation number and O is assigned a -2 oxidation number.
- For a neutral compound the summation of oxidation numbers of all elements in the compound is zero.
If the oxidation number of an element increases then it undergoes oxidation and if the oxidation number of the element decreases then it undergoes reduction.
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Chapter 15 Solutions
EBK BASIC CHEMISTRY
Ch. 15.1 - Prob. 15.1QAPCh. 15.1 - Prob. 15.2QAPCh. 15.1 - Prob. 15.3QAPCh. 15.1 - Prob. 15.4QAPCh. 15.1 - Prob. 15.5QAPCh. 15.1 - Prob. 15.6QAPCh. 15.1 - Prob. 15.7QAPCh. 15.1 - Prob. 15.8QAPCh. 15.1 - Prob. 15.9QAPCh. 15.1 - Prob. 15.10QAP
Ch. 15.1 - Prob. 15.11QAPCh. 15.1 - Prob. 15.12QAPCh. 15.1 - Prob. 15.13QAPCh. 15.1 - Prob. 15.14QAPCh. 15.1 - Prob. 15.15QAPCh. 15.1 - Prob. 15.16QAPCh. 15.1 - Prob. 15.17QAPCh. 15.1 - Prob. 15.18QAPCh. 15.1 - Prob. 15.19QAPCh. 15.1 - Prob. 15.20QAPCh. 15.2 - Prob. 15.21QAPCh. 15.2 - Prob. 15.22QAPCh. 15.2 - Use the half-reaction method to balance each of...Ch. 15.2 - Prob. 15.24QAPCh. 15.2 - Use the halt-reaction method to balance each of...Ch. 15.2 - Prob. 15.26QAPCh. 15.3 - Prob. 15.27QAPCh. 15.3 - Prob. 15.28QAPCh. 15.3 - Prob. 15.29QAPCh. 15.3 - Prob. 15.30QAPCh. 15.3 - Prob. 15.31QAPCh. 15.3 - Prob. 15.32QAPCh. 15.3 - Prob. 15.33QAPCh. 15.3 - Prob. 15.34QAPCh. 15.3 - Prob. 15.35QAPCh. 15.3 - Prob. 15.36QAPCh. 15.4 - Prob. 15.37QAPCh. 15.4 - Prob. 15.38QAPCh. 15.4 - Prob. 15.39QAPCh. 15.4 - Prob. 15.40QAPCh. 15 - Prob. 15.41FUCh. 15 - Prob. 15.42FUCh. 15 - Prob. 15.43UTCCh. 15 - Prob. 15.44UTCCh. 15 - Prob. 15.45UTCCh. 15 - Prob. 15.46UTCCh. 15 - Prob. 15.47UTCCh. 15 - Prob. 15.48UTCCh. 15 - Prob. 15.49AUTCCh. 15 - Prob. 15.50AUTCCh. 15 - Prob. 15.51AUTCCh. 15 - Prob. 15.52AUTCCh. 15 - Prob. 15.53AUTCCh. 15 - Prob. 15.54AUTCCh. 15 - Which of the following are notation-reduction...Ch. 15 - Prob. 15.56AQAPCh. 15 - Prob. 15.57AQAPCh. 15 - Prob. 15.58AQAPCh. 15 - 15.59 Assign oxidation numbers to all the elements...Ch. 15 - Prob. 15.60AQAPCh. 15 - Assign oxidation numbers to all the elements in...Ch. 15 - Assign oxidation numbers to all the elements in...Ch. 15 - Prob. 15.63AQAPCh. 15 - Prob. 15.64AQAPCh. 15 - 15.65 Use the activity series in Table 15.3 to...Ch. 15 - Prob. 15.66AQAPCh. 15 - Prob. 15.67AQAPCh. 15 - In a voltaic cell, one half-cell consists of zinc...Ch. 15 - Prob. 15.69AQAPCh. 15 - 15.70 Use the activity series in Table 15.3 to...Ch. 15 - 15.71 In a lead storage battery. the following...Ch. 15 - Prob. 15.72AQAPCh. 15 - Prob. 15.73AQAPCh. 15 - Prob. 15.74AQAPCh. 15 - Prob. 15.75CQCh. 15 - Prob. 15.76CQCh. 15 - Prob. 15.77CQCh. 15 - Prob. 15.78CQCh. 15 - Prob. 15.79CQCh. 15 - Prob. 15.80CQCh. 15 - Prob. 15.81CQCh. 15 - The following unbalanced reaction takes place in...Ch. 15 - Prob. 15.83CQCh. 15 - Prob. 15.84CQCh. 15 - Using the activity series in Table 15.3, indicate...Ch. 15 - Using the activity series in Table 15.3, indicate...Ch. 15 - Prob. 15.87CQCh. 15 - Prob. 15.88CQ
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