Starting Out with Programming Logic and Design (5th Edition) (What's New in Computer Science)
5th Edition
ISBN: 9780134801155
Author: Tony Gaddis
Publisher: PEARSON
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Textbook Question
Chapter 15, Problem 7MC
An _____ is an action that takes place within a
- a. event handler
- b. anomaly
- c. event
- d. exception
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4. Suppose we have a perfect binary tree with height h 0 representing a heap, meaning it
=
has n 2+1 1 keys indexed from 1 to 2+1 1. When we run convertomaxheap we run
maxheapify in reverse order on every key with children.
Let's examine the worst-case - In the worst-case every single key gets swapped all the way to
the leaf level.
(a) For each level in the tree there are a certain number of nodes and each of those nodes [10 pts]
requires a certain number of swaps. Fill in the appropriate values/expressions in the
table:
Level
Number of Keys
Number of Swaps per Key
0
2
..
(b) Write down a sum for the total number of swaps required. This should involve h, not n.
[10 pts]
Total
The next problem concerns the following C code:
/copy input string x to buf */
void foo (char *x) {
char buf [8];
strcpy((char *) buf, x);
}
void callfoo() {
}
foo("ZYXWVUTSRQPONMLKJIHGFEDCBA");
Here is the corresponding machine code on a Linux/x86 machine:
0000000000400530 :
400530:
48 83 ec 18
sub
$0x18,%rsp
400534:
48 89 fe
mov
%rdi, %rsi
400537:
48 89 e7
mov
%rsp,%rdi
40053a:
e8 di fe ff ff
callq
400410
40053f:
48 83 c4 18
add
$0x18,%rsp
400543:
c3
retq
400544:
0000000000400544 :
48 83 ec 08
sub
$0x8,%rsp
400548:
bf 00 06 40 00
mov
$0x400600,%edi
40054d:
e8 de ff ff ff
callq 400530
400552:
48 83 c4 08
add
$0x8,%rsp
400556:
c3
This problem tests your understanding of the program stack. Here are some notes to
help you work the problem:
⚫ strcpy(char *dst, char *src) copies the string at address src (including
the terminating '\0' character) to address dst. It does not check the size of
the destination buffer.
• You will need to know the hex values of the following characters:
1234
3. Which line prevents compiler optimization? Circle one: 1234
Suggested solution:
Store strlen(str) in a variable before the if statement.
⚫ Remove the if statement.
Replace index 0 && index < strlen(str)) {
5 }
}
=
str [index] = val;
Chapter 15 Solutions
Starting Out with Programming Logic and Design (5th Edition) (What's New in Computer Science)
Ch. 15.1 - What is a user interface?Ch. 15.1 - How does a command line interface work?Ch. 15.1 - Prob. 15.3CPCh. 15.1 - Prob. 15.4CPCh. 15.1 - Prob. 15.5CPCh. 15.2 - Prob. 15.6CPCh. 15.2 - In an IDE that allows you to visually construct a...Ch. 15.2 - Prob. 15.8CPCh. 15.2 - Prob. 15.9CPCh. 15.2 - Prob. 15.10CP
Ch. 15.3 - Prob. 15.11CPCh. 15.3 - Prob. 15.12CPCh. 15.3 - Look at the following pseudocode and then answer...Ch. 15.3 - Prob. 15.14CPCh. 15.4 - Prob. 15.15CPCh. 15.4 - Prob. 15.16CPCh. 15.4 - Prob. 15.17CPCh. 15.4 - Prob. 15.18CPCh. 15.4 - Prob. 15.19CPCh. 15.4 - Prob. 15.20CPCh. 15.4 - Prob. 15.21CPCh. 15 - The _________ is the part of a computer with which...Ch. 15 - Before GUIs became popular, the _____ interface...Ch. 15 - Prob. 3MCCh. 15 - A type of program that is typically event-driven...Ch. 15 - An item that appears in a programs graphical user...Ch. 15 - By specifying characteristics such as color, size,...Ch. 15 - An _____ is an action that takes place within a...Ch. 15 - A(n) _____ is a module that automatically executes...Ch. 15 - In our pseudocode, the _____ module executes...Ch. 15 - The ______________ component that we discussed in...Ch. 15 - Many computer users, especially beginners, find...Ch. 15 - Writing a GUI program today is complex and time...Ch. 15 - A components Text property typically holds string...Ch. 15 - Predefined names are given to all of the events...Ch. 15 - A user interface flow diagram shows how a GUI...Ch. 15 - Prob. 6TFCh. 15 - When developing GUTs for mobile devices and...Ch. 15 - Prob. 1SACh. 15 - What determines how a component appears on the...Ch. 15 - Prob. 3SACh. 15 - Prob. 4SACh. 15 - What is a non-visual component? Give an example of...Ch. 15 - Design an event handler that will execute when the...Ch. 15 - Design an event handler that will execute when the...Ch. 15 - The GUI for a mobile app has a Label component...Ch. 15 - The GUI for a mobile app has a Label component...Ch. 15 - Name and Address Design a GUI program that...Ch. 15 - Latin Translator Look at the following list of...Ch. 15 - Miles-per-Gallon Calculator Design a GUI program...Ch. 15 - Celsius to Fahrenheit Design a GUI program that...Ch. 15 - Property Tax A county collects property taxes on...
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- Character Hex value | Character Hex value Character Hex value 'A' 0x41 'J' Ox4a 'S' 0x53 'B' 0x42 'K' 0x4b "T" 0x54 0x43 'L' Ox4c 'U' 0x55 0x44 'M' 0x4d 'V' 0x56 0x45 'N' Ox4e 'W' 0x57 0x46 '0' Ox4f 'X' 0x58 0x47 'P' 0x50 'Y' 0x59 0x48 'Q' 0x51 'Z' Ox5a 'T' 0x49 'R' 0x52 '\0' 0x00 Now consider what happens on a Linux/x86 machine when callfoo calls foo with the input string "ZYXWVUTSRQPONMLKJIHGFEDCBA". A. On the left draw the state of the stack just before the execution of the instruction at address Ox40053a; make sure to show the frames for callfoo and foo and the exact return address, in Hex at the bottom of the callfoo frame. Then, on the right, draw the state of the stack just after the instruction got executed; make sure to show where the string "ZYXWVUTSRQPONMLKJIHGFEDCBA" is placed and what part, if any, of the above return address has been overwritten. B. Immediately after the ret instruction at address 0x400543 executes, what is the value of the program counter register %rip?…arrow_forward1 typedef struct node* { 2 struct node* next; 3 char* key; 4 char* val; 5} node_t; 6 7 char* find_node (node_t* node, char* key_to_find) { while(strcmp (node->key, key_to_find ) != 0 ) { node = node->next; 8 9 10 } 11 return node->val; 12 }arrow_forwardMatch each of the assembler routines on the left with the equivalent C function on the right. Write the name of the label (e.g., foo) to the right of the corresponding function. Note: shrq is the logical right shift instruction, and sarq is the arithmetic right shift instruction. foo1: leaq 0(,%rdi, 8), %rax long choice1 (long x) { ret return x - 8 >8; foo3: } movq sarq %rdi, %rax $8, %rax long choice4 (long x) ret { return x*256; } foo4: long choice5 (long x) leaq -8 (%rdi), %rax { ret return x-8; } long choice6 (long x) foo5: { leaq -8 (%rdi), %rax return x+8; shrq $63, %rax } retarrow_forward
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