Explanation Given information: An object of volume V is weighed in air on an equal-arm balance with the use of counterweights of density ρ . The true weight is the weight of the object that is measured in the air and the apparent weight is the weight of the object that is measured in the water. The net weight of an object can be measured in a vacuum is equal to the apparent weight is, F g − F B = F ′ g − F ′ B (I) F g is the true weight of an object. F ′ g is the apparent weight of an object. F B is the buoyant force acts on the object. F ′ B is the apparent buoyant force acts on the object. Formula to calculate the buoyant force acts on the object is, F B = ρ air g V Formula to calculate the apparent buoyant force acts on the object is, F ′ B = ρ air g ( F ′ g ρ g ) Substitute ρ air g V for F B and ρ air g ( F ′ g ρ g ) for F ′ B in equation (I)

Principles of Physics: A Calculus-Based Text, Hybrid (with Enhanced WebAssign Printed Access Card)

5th Edition

ISBN: 9781305586871

Author: Raymond A. Serway, John W. Jewett

Publisher: Cengage Learning

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Chapter 15, Problem 54P

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To show: The true weight of the object is Fg=F′g+(V−F′gρg)ρairg .

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Chapter 15, Problem 53P

Chapter 15, Problem 55P

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Chapter 15 Solutions

Principles of Physics: A Calculus-Based Text, Hybrid (with Enhanced WebAssign Printed Access Card)

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Ch. 15 - A solid iron sphere and a solid lead sphere of the...Ch. 15 - Prob. 6OQ Ch. 15 - Prob. 7OQ Ch. 15 - Prob. 8OQ Ch. 15 - An ideal fluid flows through a horizontal pipe...Ch. 15 - Prob. 10OQ Ch. 15 - Prob. 11OQ Ch. 15 - A small piece of steel is tied to a block of wood....Ch. 15 - A piece of unpainted porous wood barely floats in...Ch. 15 - Prob. 14OQ Ch. 15 - A water supply maintains a constant rate of flow...Ch. 15 - Prob. 1CQ Ch. 15 - Because atmospheric pressure is about 105 N/m2 and...Ch. 15 - Two thin-walled drinking glasses having equal base...Ch. 15 - Prob. 4CQ Ch. 15 - Prob. 5CQ Ch. 15 - Prob. 6CQ Ch. 15 - Prob. 7CQ Ch. 15 - Prob. 8CQ Ch. 15 - Prob. 9CQ Ch. 15 - Prob. 10CQ Ch. 15 - Prob. 11CQ Ch. 15 - Prob. 12CQ Ch. 15 - (a) Is the buoyant force a conservative force? (b)...Ch. 15 - An empty metal soap dish barely floats in water. A...Ch. 15 - Prob. 15CQ Ch. 15 - How would you determine the density of an...Ch. 15 - Prob. 17CQ Ch. 15 - Place two cans of soft drinks, one regular and one...Ch. 15 - Prob. 19CQ Ch. 15 - Prob. 1P Ch. 15 - A 50.0-kg woman wearing high-heeled shoes is...Ch. 15 - Prob. 3P Ch. 15 - Prob. 4P Ch. 15 - Prob. 5P Ch. 15 - The small piston of a hydraulic lift (Fig. P15.6)...Ch. 15 - A container is filled to a depth of 20.0 cm with...Ch. 15 - Prob. 8P Ch. 15 - (a) Calculate the absolute pressure at an ocean...Ch. 15 - (a) A very powerful vacuum cleaner has a hose 2.86...Ch. 15 - What must be the contact area between a suction...Ch. 15 - Prob. 12P Ch. 15 - Review. The tank in Figure P15.13 is filled with...Ch. 15 - Review. The tank in Figure P15.13 is filled with...Ch. 15 - Prob. 15P Ch. 15 - Prob. 16P Ch. 15 - Mercury is poured into a U-tube as shown in Figure...Ch. 15 - Prob. 18P Ch. 15 - A backyard swimming pool with a circular base of...Ch. 15 - A tank with a flat bottom of area A and vertical...Ch. 15 - Prob. 21P Ch. 15 - A Styrofoam slab has thickness h and density s....Ch. 15 - A table-tennis ball has a diameter of 3.80 cm and...Ch. 15 - The gravitational force exerted on a solid object...Ch. 15 - A 10.0-kg block of metal measuring 12.0 cm by 10.0...Ch. 15 - Prob. 26P Ch. 15 - Prob. 27P Ch. 15 - Prob. 28P Ch. 15 - How many cubic meters of helium are required to...Ch. 15 - Prob. 30P Ch. 15 - A plastic sphere floats in water with 50.0% of its...Ch. 15 - The weight of a rectangular block of low-density...Ch. 15 - Decades ago, it was thought that huge herbivorous...Ch. 15 - Prob. 34P Ch. 15 - Prob. 35P Ch. 15 - A light balloon is filled with 400 m3 of helium at...Ch. 15 - A horizontal pipe 10.0 cm in diameter has a smooth...Ch. 15 - Prob. 38P Ch. 15 - A large storage tank with an open top is filled to...Ch. 15 - Review. Old Faithful Geyser in Yellowstone...Ch. 15 - (a) A water hose 2.00 cm in diameter is used to...Ch. 15 - Water flows through a fire hose of diameter 6.35...Ch. 15 - Prob. 43P Ch. 15 - Prob. 44P Ch. 15 - A village maintains a large tank with an open top,...Ch. 15 - Prob. 46P Ch. 15 - Figure P15.47 shows a stream of water in steady...Ch. 15 - An airplane is cruising at altitude 10 km. The...Ch. 15 - The Bernoulli effect can have important...Ch. 15 - Prob. 50P Ch. 15 - Prob. 51P Ch. 15 - Prob. 52P Ch. 15 - Prob. 53P Ch. 15 - Prob. 54P Ch. 15 - Prob. 55P Ch. 15 - Prob. 56P Ch. 15 - Prob. 57P Ch. 15 - Prob. 58P Ch. 15 - Review. A copper cylinder hangs at the bottom of a...Ch. 15 - Prob. 60P Ch. 15 - An incompressible, nonviscous fluid is initially...Ch. 15 - In about 1657, Otto von Guericke, inventor of the...Ch. 15 - A 1.00-kg beaker containing 2.00 kg of oil...Ch. 15 - A beaker of mass mb containing oil of mass mo and...Ch. 15 - Prob. 65P Ch. 15 - Prob. 66P Ch. 15 - A U-tube open at both ends is partially filled...Ch. 15 - Prob. 68P Ch. 15 - Prob. 69P Ch. 15 - The spirit-in-glass thermometer, invented in...

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The true weight of the object is F g = F ′ g + ( V − F ′ g ρ g ) ρ air g .

Solution Summary: The author explains that an object of volume V is weighed in air on an equal-arm balance with the use of counterweights of density rho

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To show: The true weight of the object is Fg=F′g+(V−F′gρg)ρairg .

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Chapter 15 Solutions