(a) Interpretation: The number of moles of the indicated ion present in the given solution is to be calculated. Concept Introduction: The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element. The number of moles is calculated by the formula, Moles = Mass g Molar mass The molarity is calculated by the formula, Molarity = Number of moles of solute Volume of solution in Liters .

Question

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Answer 1

Question

Chapter 15, Problem 49QAP

Interpretation Introduction

(a)

Interpretation:

The number of moles of the indicated ion present in the given solution is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solutionin Liters$ .

Expert Solution

Answer to Problem 49QAP

The number of moles of $Na+$ ions in solution is $0.502 moles$ .

Explanation of Solution

The volume and molarity of $Na2SO4$ solution is given to be $1.00 L$ and $0.251 M$ respectively.

The number of moles of a solute is calculated by the formula,

$Number of moles of solute=Volume of solution×Molarity$

Substitute the values of volume of solution and molarity of $Na2SO4$ solution in the above expression.

$Number of moles of solute=1.00 L×0.251 M=0.251 moles$

The solution of $Na2SO4$ consists of $Na+$ and $SO42−$ ions. The compound $Na2SO4$ has two $Na+$ ions.

The number of moles of $Na+$ is calculated as shown below.

$Moles of Na+=2×0.251 moles=0.502 moles$

Therefore, the number of moles of $Na+$ ions in solution is $0.502 moles$ .

Interpretation Introduction

(b)

Interpretation:

The number of moles of the indicated ion present in the given solution is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solutionin Liters$ .

Expert Solution

Answer to Problem 49QAP

The number of moles of $Cl−$ ions in solution is $1.65 moles$ .

Explanation of Solution

The volume and molarity of $FeCl3$ solution is given to be $5.50 L$ and $0.10 M$ respectively.

The number of moles of a solute is calculated by the formula,

$Number of moles of solute=Volume of solution×Molarity$

Substitute the values of volume of solution and molarity of $FeCl3$ solution in the above expression.

$Number of moles of solute=5.50 L×0.10 M=0.55 moles$

The solution of $FeCl3$ consists of $Fe3+$ and $Cl−$ ions. The compound $FeCl3$ has three $Cl−$ ions.

Thus, the number of moles of $Cl−$ is calculated as shown below.

$Moles of Cl−=3×0.55 moles=1.65 moles$

Therefore, the number of moles of $Cl−$ ions in solution is $1.65 moles$ .

Interpretation Introduction

(c)

Interpretation:

The number of moles of the indicated ion present in the given solution is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solutionin Liters$ .

Expert Solution

Answer to Problem 49QAP

The number of moles of $NO3−$ ions in solution is $0.11 moles$ .

Explanation of Solution

The volume and molarity of $BaNO32$ solution is given to be $100 mL$ and $0.55 M$ respectively.

The conversion of units of volume into $L$ is done as,

$100 mL=1001000 L=0.1 L$

The number of moles of a solute is calculated by the formula,

$Number of moles of solute=Volume of solution×Molarity$

Substitute the values of volume of solution and molarity of $BaNO32$ solution in the above expression.

$Number of moles of solute=0.1 L×0.55 M=0.055 moles$

The solution of $BaNO32$ consists of $Ba2+$ and $NO3−$ ions. The compound $BaNO32$ has two $NO3−$ ions.

Thus, the number of moles of $NO3−$ is calculated as shown below.

$Moles of NO3−=2×0.055 moles=0.11 moles$

Therefore, the number of moles of $NO3−$ ions in solution is $0.11 moles$ .

Interpretation Introduction

(d)

Interpretation:

The number of moles of the indicated ion present in the given solution is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solutionin Liters$ .

Expert Solution

Answer to Problem 49QAP

The number of moles of $NH4+$ ions in solution is $0.175 moles$ .

Explanation of Solution

The volume and molarity of $NH42SO4$ solution is given to be $250 mL$ and $0.350 M$ respectively.

The conversion of units of volume into $L$ is done as,

$250 mL=2501000 L=0.250 L$

The number of moles of a solute is calculated by the formula,

$Number of moles of solute=Volume of solution×Molarity$

Substitute the values of volume of solution and molarity of $NH42SO4$ solution in the above expression.

$Number of moles of solute=0.250 L×0.350 M=0.0875 moles$

The solution of $NH42SO4$ consists of $NH4+$ and $SO42−$ ions. The compound $NH42SO4$ has two $NH4+$ ions.

Thus, the number of moles of $NH4+$ is calculated as shown below.

$Moles of NH4+=2×0.0875 moles=0.175 moles$

Therefore, the number of moles of $NH4+$ ions in solution is $0.175 moles$ .

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Answer 2

Question

Chapter 15, Problem 49QAP

Interpretation Introduction

(a)

Interpretation:

The number of moles of the indicated ion present in the given solution is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solutionin Liters$ .

Expert Solution

Answer to Problem 49QAP

The number of moles of $Na+$ ions in solution is $0.502 moles$ .

Explanation of Solution

The volume and molarity of $Na2SO4$ solution is given to be $1.00 L$ and $0.251 M$ respectively.

The number of moles of a solute is calculated by the formula,

$Number of moles of solute=Volume of solution×Molarity$

Substitute the values of volume of solution and molarity of $Na2SO4$ solution in the above expression.

$Number of moles of solute=1.00 L×0.251 M=0.251 moles$

The solution of $Na2SO4$ consists of $Na+$ and $SO42−$ ions. The compound $Na2SO4$ has two $Na+$ ions.

The number of moles of $Na+$ is calculated as shown below.

$Moles of Na+=2×0.251 moles=0.502 moles$

Therefore, the number of moles of $Na+$ ions in solution is $0.502 moles$ .

Interpretation Introduction

(b)

Interpretation:

The number of moles of the indicated ion present in the given solution is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solutionin Liters$ .

Expert Solution

Answer to Problem 49QAP

The number of moles of $Cl−$ ions in solution is $1.65 moles$ .

Explanation of Solution

The volume and molarity of $FeCl3$ solution is given to be $5.50 L$ and $0.10 M$ respectively.

The number of moles of a solute is calculated by the formula,

$Number of moles of solute=Volume of solution×Molarity$

Substitute the values of volume of solution and molarity of $FeCl3$ solution in the above expression.

$Number of moles of solute=5.50 L×0.10 M=0.55 moles$

The solution of $FeCl3$ consists of $Fe3+$ and $Cl−$ ions. The compound $FeCl3$ has three $Cl−$ ions.

Thus, the number of moles of $Cl−$ is calculated as shown below.

$Moles of Cl−=3×0.55 moles=1.65 moles$

Therefore, the number of moles of $Cl−$ ions in solution is $1.65 moles$ .

Interpretation Introduction

(c)

Interpretation:

The number of moles of the indicated ion present in the given solution is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solutionin Liters$ .

Expert Solution

Answer to Problem 49QAP

The number of moles of $NO3−$ ions in solution is $0.11 moles$ .

Explanation of Solution

The volume and molarity of $BaNO32$ solution is given to be $100 mL$ and $0.55 M$ respectively.

The conversion of units of volume into $L$ is done as,

$100 mL=1001000 L=0.1 L$

The number of moles of a solute is calculated by the formula,

$Number of moles of solute=Volume of solution×Molarity$

Substitute the values of volume of solution and molarity of $BaNO32$ solution in the above expression.

$Number of moles of solute=0.1 L×0.55 M=0.055 moles$

The solution of $BaNO32$ consists of $Ba2+$ and $NO3−$ ions. The compound $BaNO32$ has two $NO3−$ ions.

Thus, the number of moles of $NO3−$ is calculated as shown below.

$Moles of NO3−=2×0.055 moles=0.11 moles$

Therefore, the number of moles of $NO3−$ ions in solution is $0.11 moles$ .

Interpretation Introduction

(d)

Interpretation:

The number of moles of the indicated ion present in the given solution is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solutionin Liters$ .

Expert Solution

Answer to Problem 49QAP

The number of moles of $NH4+$ ions in solution is $0.175 moles$ .

Explanation of Solution

The volume and molarity of $NH42SO4$ solution is given to be $250 mL$ and $0.350 M$ respectively.

The conversion of units of volume into $L$ is done as,

$250 mL=2501000 L=0.250 L$

The number of moles of a solute is calculated by the formula,

$Number of moles of solute=Volume of solution×Molarity$

Substitute the values of volume of solution and molarity of $NH42SO4$ solution in the above expression.

$Number of moles of solute=0.250 L×0.350 M=0.0875 moles$

The solution of $NH42SO4$ consists of $NH4+$ and $SO42−$ ions. The compound $NH42SO4$ has two $NH4+$ ions.

Thus, the number of moles of $NH4+$ is calculated as shown below.

$Moles of NH4+=2×0.0875 moles=0.175 moles$

Therefore, the number of moles of $NH4+$ ions in solution is $0.175 moles$ .

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Answer 3

Question

Chapter 15, Problem 49QAP

Interpretation Introduction

(a)

Interpretation:

The number of moles of the indicated ion present in the given solution is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solutionin Liters$ .

Expert Solution

Answer to Problem 49QAP

The number of moles of $Na+$ ions in solution is $0.502 moles$ .

Explanation of Solution

The volume and molarity of $Na2SO4$ solution is given to be $1.00 L$ and $0.251 M$ respectively.

The number of moles of a solute is calculated by the formula,

$Number of moles of solute=Volume of solution×Molarity$

Substitute the values of volume of solution and molarity of $Na2SO4$ solution in the above expression.

$Number of moles of solute=1.00 L×0.251 M=0.251 moles$

The solution of $Na2SO4$ consists of $Na+$ and $SO42−$ ions. The compound $Na2SO4$ has two $Na+$ ions.

The number of moles of $Na+$ is calculated as shown below.

$Moles of Na+=2×0.251 moles=0.502 moles$

Therefore, the number of moles of $Na+$ ions in solution is $0.502 moles$ .

Interpretation Introduction

(b)

Interpretation:

The number of moles of the indicated ion present in the given solution is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solutionin Liters$ .

Expert Solution

Answer to Problem 49QAP

The number of moles of $Cl−$ ions in solution is $1.65 moles$ .

Explanation of Solution

The volume and molarity of $FeCl3$ solution is given to be $5.50 L$ and $0.10 M$ respectively.

The number of moles of a solute is calculated by the formula,

$Number of moles of solute=Volume of solution×Molarity$

Substitute the values of volume of solution and molarity of $FeCl3$ solution in the above expression.

$Number of moles of solute=5.50 L×0.10 M=0.55 moles$

The solution of $FeCl3$ consists of $Fe3+$ and $Cl−$ ions. The compound $FeCl3$ has three $Cl−$ ions.

Thus, the number of moles of $Cl−$ is calculated as shown below.

$Moles of Cl−=3×0.55 moles=1.65 moles$

Therefore, the number of moles of $Cl−$ ions in solution is $1.65 moles$ .

Interpretation Introduction

(c)

Interpretation:

The number of moles of the indicated ion present in the given solution is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solutionin Liters$ .

Expert Solution

Answer to Problem 49QAP

The number of moles of $NO3−$ ions in solution is $0.11 moles$ .

Explanation of Solution

The volume and molarity of $BaNO32$ solution is given to be $100 mL$ and $0.55 M$ respectively.

The conversion of units of volume into $L$ is done as,

$100 mL=1001000 L=0.1 L$

The number of moles of a solute is calculated by the formula,

$Number of moles of solute=Volume of solution×Molarity$

Substitute the values of volume of solution and molarity of $BaNO32$ solution in the above expression.

$Number of moles of solute=0.1 L×0.55 M=0.055 moles$

The solution of $BaNO32$ consists of $Ba2+$ and $NO3−$ ions. The compound $BaNO32$ has two $NO3−$ ions.

Thus, the number of moles of $NO3−$ is calculated as shown below.

$Moles of NO3−=2×0.055 moles=0.11 moles$

Therefore, the number of moles of $NO3−$ ions in solution is $0.11 moles$ .

Interpretation Introduction

(d)

Interpretation:

The number of moles of the indicated ion present in the given solution is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solutionin Liters$ .

Expert Solution

Answer to Problem 49QAP

The number of moles of $NH4+$ ions in solution is $0.175 moles$ .

Explanation of Solution

The volume and molarity of $NH42SO4$ solution is given to be $250 mL$ and $0.350 M$ respectively.

The conversion of units of volume into $L$ is done as,

$250 mL=2501000 L=0.250 L$

The number of moles of a solute is calculated by the formula,

$Number of moles of solute=Volume of solution×Molarity$

Substitute the values of volume of solution and molarity of $NH42SO4$ solution in the above expression.

$Number of moles of solute=0.250 L×0.350 M=0.0875 moles$

The solution of $NH42SO4$ consists of $NH4+$ and $SO42−$ ions. The compound $NH42SO4$ has two $NH4+$ ions.

Thus, the number of moles of $NH4+$ is calculated as shown below.

$Moles of NH4+=2×0.0875 moles=0.175 moles$

Therefore, the number of moles of $NH4+$ ions in solution is $0.175 moles$ .

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Answer 4

Question

Chapter 15, Problem 49QAP

Interpretation Introduction

(a)

Interpretation:

The number of moles of the indicated ion present in the given solution is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solutionin Liters$ .

Expert Solution

Answer to Problem 49QAP

The number of moles of $Na+$ ions in solution is $0.502 moles$ .

Explanation of Solution

The volume and molarity of $Na2SO4$ solution is given to be $1.00 L$ and $0.251 M$ respectively.

The number of moles of a solute is calculated by the formula,

$Number of moles of solute=Volume of solution×Molarity$

Substitute the values of volume of solution and molarity of $Na2SO4$ solution in the above expression.

$Number of moles of solute=1.00 L×0.251 M=0.251 moles$

The solution of $Na2SO4$ consists of $Na+$ and $SO42−$ ions. The compound $Na2SO4$ has two $Na+$ ions.

The number of moles of $Na+$ is calculated as shown below.

$Moles of Na+=2×0.251 moles=0.502 moles$

Therefore, the number of moles of $Na+$ ions in solution is $0.502 moles$ .

Interpretation Introduction

(b)

Interpretation:

The number of moles of the indicated ion present in the given solution is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solutionin Liters$ .

Expert Solution

Answer to Problem 49QAP

The number of moles of $Cl−$ ions in solution is $1.65 moles$ .

Explanation of Solution

The volume and molarity of $FeCl3$ solution is given to be $5.50 L$ and $0.10 M$ respectively.

The number of moles of a solute is calculated by the formula,

$Number of moles of solute=Volume of solution×Molarity$

Substitute the values of volume of solution and molarity of $FeCl3$ solution in the above expression.

$Number of moles of solute=5.50 L×0.10 M=0.55 moles$

The solution of $FeCl3$ consists of $Fe3+$ and $Cl−$ ions. The compound $FeCl3$ has three $Cl−$ ions.

Thus, the number of moles of $Cl−$ is calculated as shown below.

$Moles of Cl−=3×0.55 moles=1.65 moles$

Therefore, the number of moles of $Cl−$ ions in solution is $1.65 moles$ .

Interpretation Introduction

(c)

Interpretation:

The number of moles of the indicated ion present in the given solution is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solutionin Liters$ .

Expert Solution

Answer to Problem 49QAP

The number of moles of $NO3−$ ions in solution is $0.11 moles$ .

Explanation of Solution

The volume and molarity of $BaNO32$ solution is given to be $100 mL$ and $0.55 M$ respectively.

The conversion of units of volume into $L$ is done as,

$100 mL=1001000 L=0.1 L$

The number of moles of a solute is calculated by the formula,

$Number of moles of solute=Volume of solution×Molarity$

Substitute the values of volume of solution and molarity of $BaNO32$ solution in the above expression.

$Number of moles of solute=0.1 L×0.55 M=0.055 moles$

The solution of $BaNO32$ consists of $Ba2+$ and $NO3−$ ions. The compound $BaNO32$ has two $NO3−$ ions.

Thus, the number of moles of $NO3−$ is calculated as shown below.

$Moles of NO3−=2×0.055 moles=0.11 moles$

Therefore, the number of moles of $NO3−$ ions in solution is $0.11 moles$ .

Interpretation Introduction

(d)

Interpretation:

The number of moles of the indicated ion present in the given solution is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solutionin Liters$ .

Expert Solution

Answer to Problem 49QAP

The number of moles of $NH4+$ ions in solution is $0.175 moles$ .

Explanation of Solution

The volume and molarity of $NH42SO4$ solution is given to be $250 mL$ and $0.350 M$ respectively.

The conversion of units of volume into $L$ is done as,

$250 mL=2501000 L=0.250 L$

The number of moles of a solute is calculated by the formula,

$Number of moles of solute=Volume of solution×Molarity$

Substitute the values of volume of solution and molarity of $NH42SO4$ solution in the above expression.

$Number of moles of solute=0.250 L×0.350 M=0.0875 moles$

The solution of $NH42SO4$ consists of $NH4+$ and $SO42−$ ions. The compound $NH42SO4$ has two $NH4+$ ions.

Thus, the number of moles of $NH4+$ is calculated as shown below.

$Moles of NH4+=2×0.0875 moles=0.175 moles$

Therefore, the number of moles of $NH4+$ ions in solution is $0.175 moles$ .

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Answer 5

Chapter 15, Problem 49QAP

Interpretation Introduction

(a)

Interpretation:

The number of moles of the indicated ion present in the given solution is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solutionin Liters$ .

Expert Solution

Answer to Problem 49QAP

The number of moles of $Na+$ ions in solution is $0.502 moles$ .

Explanation of Solution

The volume and molarity of $Na2SO4$ solution is given to be $1.00 L$ and $0.251 M$ respectively.

The number of moles of a solute is calculated by the formula,

$Number of moles of solute=Volume of solution×Molarity$

Substitute the values of volume of solution and molarity of $Na2SO4$ solution in the above expression.

$Number of moles of solute=1.00 L×0.251 M=0.251 moles$

The solution of $Na2SO4$ consists of $Na+$ and $SO42−$ ions. The compound $Na2SO4$ has two $Na+$ ions.

The number of moles of $Na+$ is calculated as shown below.

$Moles of Na+=2×0.251 moles=0.502 moles$

Therefore, the number of moles of $Na+$ ions in solution is $0.502 moles$ .

Interpretation Introduction

(b)

Interpretation:

The number of moles of the indicated ion present in the given solution is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solutionin Liters$ .

Expert Solution

Answer to Problem 49QAP

The number of moles of $Cl−$ ions in solution is $1.65 moles$ .

Explanation of Solution

The volume and molarity of $FeCl3$ solution is given to be $5.50 L$ and $0.10 M$ respectively.

The number of moles of a solute is calculated by the formula,

$Number of moles of solute=Volume of solution×Molarity$

Substitute the values of volume of solution and molarity of $FeCl3$ solution in the above expression.

$Number of moles of solute=5.50 L×0.10 M=0.55 moles$

The solution of $FeCl3$ consists of $Fe3+$ and $Cl−$ ions. The compound $FeCl3$ has three $Cl−$ ions.

Thus, the number of moles of $Cl−$ is calculated as shown below.

$Moles of Cl−=3×0.55 moles=1.65 moles$

Therefore, the number of moles of $Cl−$ ions in solution is $1.65 moles$ .

Interpretation Introduction

(c)

Interpretation:

The number of moles of the indicated ion present in the given solution is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solutionin Liters$ .

Expert Solution

Answer to Problem 49QAP

The number of moles of $NO3−$ ions in solution is $0.11 moles$ .

Explanation of Solution

The volume and molarity of $BaNO32$ solution is given to be $100 mL$ and $0.55 M$ respectively.

The conversion of units of volume into $L$ is done as,

$100 mL=1001000 L=0.1 L$

The number of moles of a solute is calculated by the formula,

$Number of moles of solute=Volume of solution×Molarity$

Substitute the values of volume of solution and molarity of $BaNO32$ solution in the above expression.

$Number of moles of solute=0.1 L×0.55 M=0.055 moles$

The solution of $BaNO32$ consists of $Ba2+$ and $NO3−$ ions. The compound $BaNO32$ has two $NO3−$ ions.

Thus, the number of moles of $NO3−$ is calculated as shown below.

$Moles of NO3−=2×0.055 moles=0.11 moles$

Therefore, the number of moles of $NO3−$ ions in solution is $0.11 moles$ .

Interpretation Introduction

(d)

Interpretation:

The number of moles of the indicated ion present in the given solution is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solutionin Liters$ .

Expert Solution

Answer to Problem 49QAP

The number of moles of $NH4+$ ions in solution is $0.175 moles$ .

Explanation of Solution

The volume and molarity of $NH42SO4$ solution is given to be $250 mL$ and $0.350 M$ respectively.

The conversion of units of volume into $L$ is done as,

$250 mL=2501000 L=0.250 L$

The number of moles of a solute is calculated by the formula,

$Number of moles of solute=Volume of solution×Molarity$

Substitute the values of volume of solution and molarity of $NH42SO4$ solution in the above expression.

$Number of moles of solute=0.250 L×0.350 M=0.0875 moles$

The solution of $NH42SO4$ consists of $NH4+$ and $SO42−$ ions. The compound $NH42SO4$ has two $NH4+$ ions.

Thus, the number of moles of $NH4+$ is calculated as shown below.

$Moles of NH4+=2×0.0875 moles=0.175 moles$

Therefore, the number of moles of $NH4+$ ions in solution is $0.175 moles$ .

Answer 6

Chapter 15, Problem 49QAP

Interpretation Introduction

(a)

Interpretation:

The number of moles of the indicated ion present in the given solution is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solutionin Liters$ .

Expert Solution

Answer to Problem 49QAP

The number of moles of $Na+$ ions in solution is $0.502 moles$ .

Explanation of Solution

The volume and molarity of $Na2SO4$ solution is given to be $1.00 L$ and $0.251 M$ respectively.

The number of moles of a solute is calculated by the formula,

$Number of moles of solute=Volume of solution×Molarity$

Substitute the values of volume of solution and molarity of $Na2SO4$ solution in the above expression.

$Number of moles of solute=1.00 L×0.251 M=0.251 moles$

The solution of $Na2SO4$ consists of $Na+$ and $SO42−$ ions. The compound $Na2SO4$ has two $Na+$ ions.

The number of moles of $Na+$ is calculated as shown below.

$Moles of Na+=2×0.251 moles=0.502 moles$

Therefore, the number of moles of $Na+$ ions in solution is $0.502 moles$ .

Answer 7

Chapter 15, Problem 49QAP

Interpretation Introduction

(a)

Interpretation:

The number of moles of the indicated ion present in the given solution is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solutionin Liters$ .

Answer 8

Expert Solution

Answer to Problem 49QAP

The number of moles of $Na+$ ions in solution is $0.502 moles$ .

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

The volume and molarity of $Na2SO4$ solution is given to be $1.00 L$ and $0.251 M$ respectively.

The number of moles of a solute is calculated by the formula,

$Number of moles of solute=Volume of solution×Molarity$

Substitute the values of volume of solution and molarity of $Na2SO4$ solution in the above expression.

$Number of moles of solute=1.00 L×0.251 M=0.251 moles$

The solution of $Na2SO4$ consists of $Na+$ and $SO42−$ ions. The compound $Na2SO4$ has two $Na+$ ions.

The number of moles of $Na+$ is calculated as shown below.

$Moles of Na+=2×0.251 moles=0.502 moles$

Therefore, the number of moles of $Na+$ ions in solution is $0.502 moles$ .

Answer 13

Interpretation Introduction

(b)

Interpretation:

The number of moles of the indicated ion present in the given solution is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solutionin Liters$ .

Expert Solution

Answer to Problem 49QAP

The number of moles of $Cl−$ ions in solution is $1.65 moles$ .

Explanation of Solution

The volume and molarity of $FeCl3$ solution is given to be $5.50 L$ and $0.10 M$ respectively.

The number of moles of a solute is calculated by the formula,

$Number of moles of solute=Volume of solution×Molarity$

Substitute the values of volume of solution and molarity of $FeCl3$ solution in the above expression.

$Number of moles of solute=5.50 L×0.10 M=0.55 moles$

The solution of $FeCl3$ consists of $Fe3+$ and $Cl−$ ions. The compound $FeCl3$ has three $Cl−$ ions.

Thus, the number of moles of $Cl−$ is calculated as shown below.

$Moles of Cl−=3×0.55 moles=1.65 moles$

Therefore, the number of moles of $Cl−$ ions in solution is $1.65 moles$ .

Answer 14

Interpretation Introduction

(b)

Interpretation:

The number of moles of the indicated ion present in the given solution is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solutionin Liters$ .

Answer 15

Expert Solution

Answer to Problem 49QAP

The number of moles of $Cl−$ ions in solution is $1.65 moles$ .

Answer 16

Expert Solution

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

The volume and molarity of $FeCl3$ solution is given to be $5.50 L$ and $0.10 M$ respectively.

The number of moles of a solute is calculated by the formula,

$Number of moles of solute=Volume of solution×Molarity$

Substitute the values of volume of solution and molarity of $FeCl3$ solution in the above expression.

$Number of moles of solute=5.50 L×0.10 M=0.55 moles$

The solution of $FeCl3$ consists of $Fe3+$ and $Cl−$ ions. The compound $FeCl3$ has three $Cl−$ ions.

Thus, the number of moles of $Cl−$ is calculated as shown below.

$Moles of Cl−=3×0.55 moles=1.65 moles$

Therefore, the number of moles of $Cl−$ ions in solution is $1.65 moles$ .

Answer 20

Interpretation Introduction

(c)

Interpretation:

The number of moles of the indicated ion present in the given solution is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solutionin Liters$ .

Expert Solution

Answer to Problem 49QAP

The number of moles of $NO3−$ ions in solution is $0.11 moles$ .

Explanation of Solution

The volume and molarity of $BaNO32$ solution is given to be $100 mL$ and $0.55 M$ respectively.

The conversion of units of volume into $L$ is done as,

$100 mL=1001000 L=0.1 L$

The number of moles of a solute is calculated by the formula,

$Number of moles of solute=Volume of solution×Molarity$

Substitute the values of volume of solution and molarity of $BaNO32$ solution in the above expression.

$Number of moles of solute=0.1 L×0.55 M=0.055 moles$

The solution of $BaNO32$ consists of $Ba2+$ and $NO3−$ ions. The compound $BaNO32$ has two $NO3−$ ions.

Thus, the number of moles of $NO3−$ is calculated as shown below.

$Moles of NO3−=2×0.055 moles=0.11 moles$

Therefore, the number of moles of $NO3−$ ions in solution is $0.11 moles$ .

Answer 21

Interpretation Introduction

(c)

Interpretation:

The number of moles of the indicated ion present in the given solution is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solutionin Liters$ .

Answer 22

Expert Solution

Answer to Problem 49QAP

The number of moles of $NO3−$ ions in solution is $0.11 moles$ .

Answer 23

Expert Solution

Answer 24

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

The volume and molarity of $BaNO32$ solution is given to be $100 mL$ and $0.55 M$ respectively.

The conversion of units of volume into $L$ is done as,

$100 mL=1001000 L=0.1 L$

The number of moles of a solute is calculated by the formula,

$Number of moles of solute=Volume of solution×Molarity$

Substitute the values of volume of solution and molarity of $BaNO32$ solution in the above expression.

$Number of moles of solute=0.1 L×0.55 M=0.055 moles$

The solution of $BaNO32$ consists of $Ba2+$ and $NO3−$ ions. The compound $BaNO32$ has two $NO3−$ ions.

Thus, the number of moles of $NO3−$ is calculated as shown below.

$Moles of NO3−=2×0.055 moles=0.11 moles$

Therefore, the number of moles of $NO3−$ ions in solution is $0.11 moles$ .

Answer 27

Interpretation Introduction

(d)

Interpretation:

The number of moles of the indicated ion present in the given solution is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solutionin Liters$ .

Expert Solution

Answer to Problem 49QAP

The number of moles of $NH4+$ ions in solution is $0.175 moles$ .

Explanation of Solution

The volume and molarity of $NH42SO4$ solution is given to be $250 mL$ and $0.350 M$ respectively.

The conversion of units of volume into $L$ is done as,

$250 mL=2501000 L=0.250 L$

The number of moles of a solute is calculated by the formula,

$Number of moles of solute=Volume of solution×Molarity$

Substitute the values of volume of solution and molarity of $NH42SO4$ solution in the above expression.

$Number of moles of solute=0.250 L×0.350 M=0.0875 moles$

The solution of $NH42SO4$ consists of $NH4+$ and $SO42−$ ions. The compound $NH42SO4$ has two $NH4+$ ions.

Thus, the number of moles of $NH4+$ is calculated as shown below.

$Moles of NH4+=2×0.0875 moles=0.175 moles$

Therefore, the number of moles of $NH4+$ ions in solution is $0.175 moles$ .

Answer 28

Interpretation Introduction

(d)

Interpretation:

The number of moles of the indicated ion present in the given solution is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solutionin Liters$ .

Answer 29

Expert Solution

Answer to Problem 49QAP

The number of moles of $NH4+$ ions in solution is $0.175 moles$ .

Answer 30

Expert Solution

Answer 31

Expert Solution

Answer 32

Expert Solution

Answer 33

Explanation of Solution

The volume and molarity of $NH42SO4$ solution is given to be $250 mL$ and $0.350 M$ respectively.

The conversion of units of volume into $L$ is done as,

$250 mL=2501000 L=0.250 L$

The number of moles of a solute is calculated by the formula,

$Number of moles of solute=Volume of solution×Molarity$

Substitute the values of volume of solution and molarity of $NH42SO4$ solution in the above expression.

$Number of moles of solute=0.250 L×0.350 M=0.0875 moles$

The solution of $NH42SO4$ consists of $NH4+$ and $SO42−$ ions. The compound $NH42SO4$ has two $NH4+$ ions.

Thus, the number of moles of $NH4+$ is calculated as shown below.

$Moles of NH4+=2×0.0875 moles=0.175 moles$

Therefore, the number of moles of $NH4+$ ions in solution is $0.175 moles$ .

Answer 34

Ch. 15.3 - ercise 15.1 A 1 35-g sample of seawater is...Ch. 15.3 - Prob. 15.2SC Ch. 15.4 - ercise 15.3 Calculate the molarity of a solution...Ch. 15.4 - ercise 15.4 Give the concentrations of the ions in...Ch. 15.4 - ercise 15.5 Calculate the number of moles of Cl...Ch. 15.4 - ercise 15.6 Formalin is an aqueous solution of...Ch. 15.5 - ercise 15.7 What volume of 12 M HCI must be taken...Ch. 15.6 - at if all ionic solids were soluble in water? How...Ch. 15.6 - Exercise 15.8 When aqueous solutions of Na2SO3 and...Ch. 15.7 - ercise 15.9 Calculate the volume of 0.10 M HNO3...

Answer to Problem 49QAP

Explanation of Solution

Answer to Problem 49QAP

Explanation of Solution

Answer to Problem 49QAP

Explanation of Solution

Answer to Problem 49QAP

Explanation of Solution

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