EBK INTRODUCTION TO CHEMISTRY
EBK INTRODUCTION TO CHEMISTRY
5th Edition
ISBN: 9781260162165
Author: BAUER
Publisher: MCGRAW HILL BOOK COMPANY
Question
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Chapter 15, Problem 27QP

(a)

Interpretation Introduction

Interpretation:

The balanced nuclear reaction for the given nuclear reaction is to be determined

(a)

Expert Solution
Check Mark

Explanation of Solution

A nuclear reaction involves changes at the subatomic level such as, the changes in the number of protons, the number of neutrons, and the energy state. To balance a nuclear reaction, two conservation conditions can be used, conservation of mass number and conservation of charges (atomic number).

The given reaction is as follows.

U92238 T90234h + XZA

Where, A is mass number and Z is the atomic number of the unknown product, X .

Apply the conservation conditions for mass numbers and atomic numbers to identify the product, X . Balance the mass numbers.

The sum of mass numbers of reactants is equal to the sum of mass numbers of the products.

238=234+AA = 4

Similarly, balance the atomic numbers. The sum of atomic numbers of reactants is equal to the sum of atomic numbers of the products.

92=90+ZZ = 2

The element with atomic number 2 is Helium, denoted by H24e . It is an alpha particle. Therefore, the product, X is α24 . Hence, the balanced reaction can be written as,

U92238 T90234h + α24

(b)

Interpretation Introduction

Interpretation:

The balanced nuclear reaction for the given nuclear reaction is to be determined

(b)

Expert Solution
Check Mark

Explanation of Solution

The given reaction is as follows.

T90234h P91234a + XZA

Where, A is mass number and Z is the atomic number of the unknown product, X .

Apply the conservation conditions for mass numbers and atomic numbers to identify the product, X . Balance the mass numbers. The sum of mass number of reactants is equal to the sum of mass number of the products.

234=234+AA = 0

Similarly, balance the atomic numbers. The sum of atomic numbers of reactants is equal to the sum of atomic numbers of the products.

90=91+ZZ = 1

As the charge is 1 , product X is a beta particle.

Hence, the balanced reaction can be written as,

T90234h P91234a + β-10-

(c)

Interpretation Introduction

Interpretation:

The balanced nuclear reaction for the given nuclear reaction is to be determined

(c)

Expert Solution
Check Mark

Explanation of Solution

The given reaction is as follows.

U92234 α24 + XZA

Where, A is mass number and Z is the atomic number the unknown product, X.

Apply the conservation conditions for mass numbers and atomic numbers to identify the product, X .

Balance the mass numbers.

The sum of mass numbers of reactants is equal to the sum of mass numbers of the products.

234=4+AA = 230

Similarly, balance the atomic numbers. The sum of atomic numbers of reactants is equal to the sum of atomic numbers of the products.

92=2+ZZ = 90

The element with atomic number 90 is Thorium. Therefore, the product, X , is T90230h .

Hence, the balanced reaction can be written as,

U92234 α24 + T90230

(d)

Interpretation Introduction

Interpretation:

The balanced nuclear reaction for the given nuclear reaction is to be determined

(d)

Expert Solution
Check Mark

Explanation of Solution

The given reaction is as follows.

B83210i + e10XZA

Where, A is mass number and Z is the atomic number of the unknown product, X .

Apply the conservation conditions for mass numbers and atomic numbers to identify the product, X .

Balance the mass numbers. The sum of mass numbers of reactants equal to the sum of mass numbers of the products.

210+0=AA = 210

Similarly, balance the atomic numbers.

The sum of atomic numbers of reactants is equal to the sum of atomic numbers of the products.

83+1=ZZ = 82

The element with atomic number 82 is Lead. Therefore, the product, X , is P82210b . Hence, the balanced reaction can be written as,

B83210i + e10P82210b

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Chapter 15 Solutions

EBK INTRODUCTION TO CHEMISTRY

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