Concept explainers
Draw short segments of the
- a. CH2 =CHF
- b. CH2 =CHCO2H
(a)
Interpretation:
The short segment of polymer obtained from the given monomer has to be drawn and also have to indicate whether it is a chain growth or step growth polymer.
Answer to Problem 22P
The short segment of given monomer is shown below and the monomer undergoes chain growth polymerization.
Explanation of Solution
Given the monomer is
The short segment of polymer obtained from this monomer is given below.
The polymer formed is a Chain growth polymer because monomer addition occurs at the end of the chain.
(b)
Interpretation:
The short segment of polymer obtained from the given monomer has to be drawn and also have to indicate whether it is a chain growth or step growth polymer.
Answer to Problem 22P
The short segment of given monomer is shown below and the monomer undergoes chain growth polymerization.
Explanation of Solution
Given the monomer is
The short segment of polymer obtained from this monomer is given below.
The polymer formed is a Chain growth polymer because monomer addition occurs at the end of the chain.
(c)
Interpretation:
The short segment of polymer obtained from the given monomer has to be drawn and also have to indicate whether it is a chain growth or step growth polymer.
Answer to Problem 22P
The short segment of given monomer is shown below and the monomer undergoes step growth polymerization.
Explanation of Solution
Given the monomer is
The short segment of polymer obtained from this monomer is given below.
The polymer formed is a Step growth polymer because monomer addition occurs not at the end of the chain and these polymers are formed by combining monomers by removing small molecules of water or alcohol.
(d)
Interpretation:
The short segment of polymer obtained from the given monomer has to be drawn and also have to indicate whether it is a chain growth or step growth polymer.
Answer to Problem 22P
The short segment of given monomer is shown below and the monomer undergoes step growth polymerization.
Explanation of Solution
Given the monomer is
The short segment of polymer obtained from this monomer is given below.
The polymer formed is a step growth polymer because monomer addition occurs not at the end of the chain and these polymers are formed by combining monomers by removing small molecules of water or alcohol.
(e)
Interpretation:
The short segment of polymer obtained from the given monomer has to be drawn and also have to indicate whether it is a chain growth or step growth polymer.
Answer to Problem 22P
The short segment of given monomer is shown below and the monomer undergoes step growth polymerization.
Explanation of Solution
Polymers are formed from linking small units called monomers and they are classified into Chain growth polymers and Step growth polymers.
Given the monomer is
The short segment of polymer obtained from this monomer is given below.
The polymer formed is a Step growth polymer because monomer addition occurs not at the end of the chain and these polymers are formed by combining monomers by removing small molecules of water or alcohol.
Want to see more full solutions like this?
Chapter 15 Solutions
Essential Organic Chemistry, Global Edition
- What monomer is needed to form each polymer? COOEt COOEt cOOEt Et = CH,CH3 polyisobutylene (used to make basketballs) poly(ethyl acrylate) (used in latex paints)arrow_forwardDrawing the Structure of a Polymer Formed from a Monomer What polymer is formed when CH2=CHCO2H (acrylic acid) is polymerized to form poly(acrylic acid)?arrow_forward1. Draw the structure of the polymer formed by the following monomer. H H H-C=C- C = Narrow_forward
- Addition Polymerization: draw the polymer resulting from the addition polymerization of each of the following monomers: CH₂=CH₂ CH₂=CH CI CH₂=CH-CH3 CH₂=CH CF₂=CF₂ CH₂=CH N CH₂=C-CH₂ COCH, 0 CH₂=CH OCCH,arrow_forwardA thermosetting material called polyester is made when a carboxylic acid reacts with dialcohol. Write the condensation polymerization with byproduct. The monomers of carboxylic acid and dialcohol are respectively: HO-C -C-OH HO-CH,CH,-OHarrow_forwardDraw the structure of the monomer used to prepare the polymer shown below. CH₂- CH-CH₂-CH-CH₂-CH-CH₂-CH- CH3 CH3 CH3 CH₂arrow_forward
- full structural form is needed for complete reaction h.warrow_forwardDraw short segments of the polymers obtained from the following monomers. indicate whether the polymerization is a chain-growth or a step-growth polymerization.arrow_forwardNomex, another aromatic polyamide (compare aramid), is prepared by polymerization of 1,3-benzenediamine and the diacid chloride of 1,3-benzenedicarboxylic acid. The physical properties of the polymer make it suitable for high-strength, high-temperature applications such as parachute cords and jet aircraft tires. Draw a structural formula for the repeating unit of Nomex. H,N. NH2 CI polymerization Nomex 1,3-Benzenediamine 1,3-Benzene- dicarbonyl chloridearrow_forward
- Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
- Chemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning