Essential Organic Chemistry, Global Edition
3rd Edition
ISBN: 9781292089034
Author: Paula Yurkanis Bruice
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Question
Chapter 15.2, Problem 4P
Interpretation Introduction
Interpretation:
The substance which is made from more highly branched polyethylene should be given from beach chair and beach ball.
Concept Introduction:
Monomers combine together to form polymers. Monomers are the repeating units of small molecules which link together to form polymers and the process is called as
Two types of polymers:
- Synthetic and biopolymers.
- DNA is an example for biopolymer and these type of polymers are synthesized by cells.
- Polymers synthesized by scientists are called
synthetic polymers and some examples are nylon, polyester etc.
Two types of synthetic polymers:
- Chain-growth
polymers or addition polymers and Step-growthpolymers or Condensation polymers. - Chain growth polymers are formed by the monomer addition to the end of a growing chain.
- Step-growth polymers are formed by combining monomers by removing small molecules of water or alcohol.
Physical properties of the polymer may be affected my branching.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
1. Which one(s) of these can be oxidized with CrO3 ?
(could be more than one)
a) triphenylmethanol
b) 2-pentanol
c) Ethyl alcohol
d)
CH3
2. Write in all the product(s) of this reaction. Label them
as "major" or "minor".
2-methyl-2-hexanol
H2SO4, heat
3) Determine if the pairs are constitutional isomers, enantiomers, diastereomers, or mesocompounds.
(4 points)
In the decomposition reaction in solution B → C, only species C absorbs UV radiation, but neither B nor the solvent absorbs. If we call At the absorbance measured at any time, A0 the absorbance at the beginning of the reaction, and A∞ the absorbance at the end of the reaction, which of the expressions is valid? We assume that Beer's law is fulfilled.
Chapter 15 Solutions
Essential Organic Chemistry, Global Edition
Ch. 15.2 - Prob. 1PCh. 15.2 - Prob. 2PCh. 15.2 - Prob. 3PCh. 15.2 - Prob. 4PCh. 15.2 - List the following groups of monomers in order...Ch. 15.2 - List the following groups of monomers in order...Ch. 15.2 - Prob. 7PCh. 15.2 - Why does methyl methacrylate not undergo cationic...Ch. 15.2 - Which monomer and which type of initiator would...Ch. 15.2 - Prob. 10P
Ch. 15.2 - Prob. 11PCh. 15.5 - Draw a short segment of gutta-percha.Ch. 15.5 - Prob. 13PCh. 15.6 - Prob. 14PCh. 15.8 - Prob. 15PCh. 15.8 - Prob. 16PCh. 15.8 - Prob. 17PCh. 15.8 - a. Propose a mechanism for the formation of the...Ch. 15.8 - Propose a mechanism for the formation of Melmac.Ch. 15.8 - Explain why, when a small amount of glycerol is...Ch. 15.10 - Prob. 21PCh. 15 - Draw short segments of the polymers obtained from...Ch. 15 - Prob. 23PCh. 15 - Draw the structure of the monomer or monomers used...Ch. 15 - Draw short segments of the polymers obtained from...Ch. 15 - Prob. 26PCh. 15 - Prob. 27PCh. 15 - Prob. 28PCh. 15 - A particularly strong and rigid polyester used for...Ch. 15 - Prob. 30PCh. 15 - Prob. 31PCh. 15 - Prob. 32PCh. 15 - Prob. 33PCh. 15 - Prob. 34PCh. 15 - Prob. 35PCh. 15 - Delrin (polyoxymethylene) is a tough...
Knowledge Booster
Similar questions
- > You are trying to decide if there is a single reagent you can add that will make the following synthesis possible without any other major side products: 1. ☑ CI 2. H3O+ O Draw the missing reagent X you think will make this synthesis work in the drawing area below. If there is no reagent that will make your desired product in good yield or without complications, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. Explanation Check ? DO 18 Ar B © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibilityarrow_forwardDon't use ai to answer I will report you answerarrow_forwardConsider a solution of 0.00304 moles of 4-nitrobenzoic acid (pKa = 3.442) dissolved in 25 mL water and titrated with 0.0991 M NaOH. Calculate the pH at the equivalence pointarrow_forward
- What is the name of the following compound? SiMe3arrow_forwardK Draw the starting structure that would lead to the major product shown under the provided conditions. Drawing 1. NaNH2 2. PhCH2Br 4 57°F Sunny Q Searcharrow_forward7 Draw the starting alkyl bromide that would produce this alkyne under these conditions. F Drawing 1. NaNH2, A 2. H3O+ £ 4 Temps to rise Tomorrow Q Search H2arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Chemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
Introductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage Learning
World of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage Learning
Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Introductory Chemistry: An Active Learning Approa...
Chemistry
ISBN:9781305079250
Author:Mark S. Cracolice, Ed Peters
Publisher:Cengage Learning
World of Chemistry, 3rd edition
Chemistry
ISBN:9781133109655
Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher:Brooks / Cole / Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning