
Concept explainers
The central angles and the corresponding chord lengthsfor a compound curve which connects two tangents.

Answer to Problem 17P
For the first curve central angle and chord length is shown in table below,
Station | Deflection angle | Chord length |
| | |
| | |
| | |
| | |
| | |
| | |
| | |
For the second curve central angle and chord length is shown in table below,
Station | Deflection angle | Chord length |
| | |
| | |
| | |
| | |
Explanation of Solution
Given information:
Intersection angle
Angle of first deflection curve
Radius of first curve
Radius of second curve
PCC station
Calculation:
Deflection for second curve is given by,
Tangent length of first curve is given by,
Similarly tangent length for second curve is given by,
Length of first curve is given by,
Length of second curve is given by,
Station of first curve at PC is given by,
The station of PCis the point of curve according to the standards of AASHTOit is calculated by dividing the station when it reaches above
Station at point of tangency is given by,
For the first curve calculate degree of first curve is given by,
Deflection angle for first full station is given by,
Deflection angle is given by,
For the first curve chord length is given by,
Deflection angle for last full station is given by,
For the first curve central angle and chord length is shown in table below,
Station | Deflection angle | Chord length |
| | |
| | |
| | |
| | |
| | |
| | |
| | |
For the second curve calculate degree of second curve is given by,
Deflection angle for first full station is given by,
Deflection angle is given by,
For the second curve chord length is given by,
Deflection angle for last full station is given by,
For the second curve central angle and chord length is shown in table below,
Station | Deflection angle | Chord length |
| | |
| | |
| | |
| | |
Want to see more full solutions like this?
Chapter 15 Solutions
Traffic And Highway Engineering
- 30 20 10 Stress N/mm² 0 -10 -20 -30 Time Question 1 A Grade S355 steel member, which forms part of the structural framework supporting a storage tank in a warehouse, is subjected to various loads, as shown in Figure 1. The yield and tensile strength of the steel member are 355 N/mm² and 510 N/mm², respectively. The steel member is subjected to axial tension due to its self-weight and appurtenances of 40.0kN. The 10.0kN storage tank is positioned 1.0 m from the centreline of the steel member, and it experiences a fatigue load range of 5.0kN. The steel member is a fillet welded built-up section that comprises two flange plates (100mm x 20mm) and a web plate (250mm x 10mm) as depicted in Section A-A. The leg size of the weld is 8 mm. Use an appropriate consequence class. Based on the damage tolerant method and the modified Goodman equation. Determine an equivalent completely reversed stress. Ignore the vibration and dynamic amplification. Use Euro-code 1993-1-9. (a) Calculate the maximum…arrow_forwardPlease do not use design aid - R. Show step by step and every formular usedarrow_forwardFollowing is the variation of the field standard penetration number (№60) in a sand deposit: Depth (m) N60 1.5 6 3 8 4.5 9 6 8 7.5 9 13 14 The groundwater table is located at a depth of 6 m. Given: the dry unit weight of sand from 0 to a depth of 6 m is 16 kN/m³, and the saturated unit weight of sand for depth 6 to 12 m is 18.2 kN/m². Use the relationship given in the equation CN = 1 σo/Pa 0.5 to calculate the corrected penetration numbers. (Round your answers to the nearest whole number.) Depth (m) Neo (N1)00 1.5 3 6 8 4.5 9 6 7.5 9 14 8 13arrow_forward
- 1,5 m 1,5 m A 1,6 KN F 0,8 m E 0,8 marrow_forward5.85 The flow pattern through the pipe contraction is as shown, and the Q of water is 60 cfs. For d = 2 ft and D = 6 ft, what is the pressure at point B if the pressure at point C is 3200 psf? D E Problem 5.85 20° Barrow_forwardPlease solve problem 8.13 (the highlighted question).arrow_forward
- The following figure shows a vertical retaining wall with a granular backfill: 100.0 50.0 40.0 30.0 20.0 10.0- 5.0- 4.0 3.0- 2.0- = +1 0.8 0.6 0.4 0.2 0.0 -0.2 -0.4 -0.6 -0.8 -0.9 1.0- 0 10 20 30 40 45 ' (deg) (a) Figure Caquot and Kerisel's solution for K 3 Let H = 4m, a = 17.5°, y = 17.5 kN/m³, ' = 35°, and 8' = 10°. For given values of ' and 8', R' = 0.53. Based on Caquot and Kerisel's solution, what would be the passive force per meter length of the wall? (Enter your answer to two significant figures.) Pp= kN/marrow_forwardThe dam presented below is 180 m long (in the direction perpendicular to the plane of thecross-section). For the water elevations given on the drawing:a) Construct the flow net (minimum number of equipotential lines should be 10),b) Calculate the rate of seepage for the entire dam,c) Find the total uplift force on the dam (ignore barriers), andd) Estimate the hydraulic gradient at points A, B, and Darrow_forwardThe influence line for moment at B for the beam shown is A -6 m- B a. O at A, 6 at B, and 15 at C b. 1 at A, 1 at B, and 1 at C c. O at A, 0 at B, and -9 at C d. O at A, 1 at B, and 1 and C -9 m-arrow_forward
- Consider the following figure: H/3 Pa Given: H = 7 m, y = 13 kN/m³, ø′ = 25°, c′ = 12 kN/m², and a = 10°. For given values, K₁ = 0.296. Calculate the Rankine active force per unit length of the wall after the occurrence of the tensile crack. (Enter your answer to three significant figures.) Pa = kN/marrow_forwardWall movement to left 45+ '/2 45 + 6'/2 Rotation of wall about this point A vertical retaining wall shown in the figure above is 7 m high with a horizontal backfill. For the backfill, assume that y = 14.5 kN/m³, ' = 26°, and c′ = 18 kN/m². Determine the Rankine active force per unit length of the wall after the occurrence of the tensile crack. (Enter your answer to three significant figures.) Pa = kN/marrow_forwardConsider the following figure: 0.6 "d 0.5 k₁ = 0 0.4 03 =0 kh = 0.2 0.3 0.025 0.2 0.05 0.1 0.1 0.2 0 -0.1 ↓ 0 5 10 15 20 25 30 35 40 45 ' (deg) For a retaining wall with a vertical back and horizontal backfill with a c'-' soil, the following are given: H = 10 ft Y = 111 lb/ft³ ' = 25° kh = 0.2 k₁ = 0 c = 113 lb/ft² Determine the magnitude of active force Pae on the wall. (Enter your answer to two significant figures.) Pae = lb/ftarrow_forward
- Traffic and Highway EngineeringCivil EngineeringISBN:9781305156241Author:Garber, Nicholas J.Publisher:Cengage Learning
